mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
18 KiB
JSON
186 lines
18 KiB
JSON
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"questionId": "2114",
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"title": "Minimum Number of Work Sessions to Finish the Tasks",
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"content": "<p>There are <code>n</code> tasks assigned to you. The task times are represented as an integer array <code>tasks</code> of length <code>n</code>, where the <code>i<sup>th</sup></code> task takes <code>tasks[i]</code> hours to finish. A <strong>work session</strong> is when you work for <strong>at most</strong> <code>sessionTime</code> consecutive hours and then take a break.</p>\n\n<p>You should finish the given tasks in a way that satisfies the following conditions:</p>\n\n<ul>\n\t<li>If you start a task in a work session, you must complete it in the <strong>same</strong> work session.</li>\n\t<li>You can start a new task <strong>immediately</strong> after finishing the previous one.</li>\n\t<li>You may complete the tasks in <strong>any order</strong>.</li>\n</ul>\n\n<p>Given <code>tasks</code> and <code>sessionTime</code>, return <em>the <strong>minimum</strong> number of <strong>work sessions</strong> needed to finish all the tasks following the conditions above.</em></p>\n\n<p>The tests are generated such that <code>sessionTime</code> is <strong>greater</strong> than or <strong>equal</strong> to the <strong>maximum</strong> element in <code>tasks[i]</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [1,2,3], sessionTime = 3\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can finish the tasks in two work sessions.\n- First work session: finish the first and the second tasks in 1 + 2 = 3 hours.\n- Second work session: finish the third task in 3 hours.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [3,1,3,1,1], sessionTime = 8\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can finish the tasks in two work sessions.\n- First work session: finish all the tasks except the last one in 3 + 1 + 3 + 1 = 8 hours.\n- Second work session: finish the last task in 1 hour.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [1,2,3,4,5], sessionTime = 15\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> You can finish all the tasks in one work session.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == tasks.length</code></li>\n\t<li><code>1 <= n <= 14</code></li>\n\t<li><code>1 <= tasks[i] <= 10</code></li>\n\t<li><code>max(tasks[i]) <= sessionTime <= 15</code></li>\n</ul>\n",
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"code": "# @param {Integer[]} tasks\n# @param {Integer} session_time\n# @return {Integer}\ndef min_sessions(tasks, session_time)\n \nend",
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"Try all possible ways of assignment.",
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"If we can store the assignments in form of a state then we can reuse that state and solve the problem in a faster way."
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