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39 lines
1.8 KiB
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<p>Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.</p>
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<p>According to the <a href="https://en.wikipedia.org/wiki/Lowest_common_ancestor" target="_blank">definition of LCA on Wikipedia</a>: “The lowest common ancestor is defined between two nodes <code>p</code> and <code>q</code> as the lowest node in <code>T</code> that has both <code>p</code> and <code>q</code> as descendants (where we allow <b>a node to be a descendant of itself</b>).”</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2018/12/14/binarysearchtree_improved.png" style="width: 200px; height: 190px;" />
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<pre>
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<strong>Input:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8
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<strong>Output:</strong> 6
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<strong>Explanation:</strong> The LCA of nodes 2 and 8 is 6.
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</pre>
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<p><strong>Example 2:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2018/12/14/binarysearchtree_improved.png" style="width: 200px; height: 190px;" />
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<pre>
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<strong>Input:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4
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<strong>Output:</strong> 2
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<strong>Explanation:</strong> The LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> root = [2,1], p = 2, q = 1
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<strong>Output:</strong> 2
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li>The number of nodes in the tree is in the range <code>[2, 10<sup>5</sup>]</code>.</li>
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<li><code>-10<sup>9</sup> <= Node.val <= 10<sup>9</sup></code></li>
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<li>All <code>Node.val</code> are <strong>unique</strong>.</li>
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<li><code>p != q</code></li>
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<li><code>p</code> and <code>q</code> will exist in the BST.</li>
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</ul>
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