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30 lines
1.1 KiB
HTML
30 lines
1.1 KiB
HTML
<p>Given an integer array <code>nums</code> sorted in <strong>non-decreasing</strong> order, return <em>an array of <strong>the squares of each number</strong> sorted in non-decreasing order</em>.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [-4,-1,0,3,10]
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<strong>Output:</strong> [0,1,9,16,100]
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<strong>Explanation:</strong> After squaring, the array becomes [16,1,0,9,100].
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After sorting, it becomes [0,1,9,16,100].
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [-7,-3,2,3,11]
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<strong>Output:</strong> [4,9,9,49,121]
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code><span>1 <= nums.length <= </span>10<sup>4</sup></code></li>
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<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>
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<li><code>nums</code> is sorted in <strong>non-decreasing</strong> order.</li>
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</ul>
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<p> </p>
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<strong>Follow up:</strong> Squaring each element and sorting the new array is very trivial, could you find an <code>O(n)</code> solution using a different approach? |