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			45 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
<p>You are given a <strong>0-indexed</strong> <code>m x n</code> integer matrix <code>mat</code> and an integer <code>k</code>. You have to cyclically <strong>right</strong> shift <strong>odd</strong> indexed rows <code>k</code> times and cyclically <strong>left</strong> shift <strong>even</strong> indexed rows <code>k</code> times.</p>
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<p>Return <code>true</code> <em>if the initial and final matrix are exactly the same and </em><code>false</code> <em>otherwise.</em></p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> mat = [[1,2,1,2],[5,5,5,5],[6,3,6,3]], k = 2
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<strong>Output:</strong> true
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<strong>Explanation:</strong>
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<img alt="" src="https://assets.leetcode.com/uploads/2023/10/29/similarmatrix.png" style="width: 500px; height: 117px;" />
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Initially, the matrix looks like the first figure. 
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Second figure represents the state of the matrix after one right and left cyclic shifts to even and odd indexed rows.
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Third figure is the final state of the matrix after two cyclic shifts which is similar to the initial matrix.
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Therefore, return true.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> mat = [[2,2],[2,2]], k = 3
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<strong>Output:</strong> true
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<strong>Explanation:</strong> As all the values are equal in the matrix, even after performing cyclic shifts the matrix will remain the same. Therefeore, we return true.
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</pre>
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<p><strong class="example">Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> mat = [[1,2]], k = 1
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<strong>Output:</strong> false
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<strong>Explanation:</strong> After one cyclic shift, mat = [[2,1]] which is not equal to the initial matrix. Therefore we return false.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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	<li><code>1 <= mat.length <= 25</code></li>
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	<li><code>1 <= mat[i].length <= 25</code></li>
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	<li><code>1 <= mat[i][j] <= 25</code></li>
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	<li><code>1 <= k <= 50</code></li>
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</ul>
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