leetcode-problemset/算法题（国外版）/number-of-pairs-of-strings-with-concatenation-equal-to-target.html

<p>Given an array of <strong>digit</strong> strings <code>nums</code> and a <strong>digit</strong> string <code>target</code>, return <em>the number of pairs of indices </em><code>(i, j)</code><em> (where </em><code>i != j</code><em>) such that the <strong>concatenation</strong> of </em><code>nums[i] + nums[j]</code><em> equals </em><code>target</code>.</p>

<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [&quot;777&quot;,&quot;7&quot;,&quot;77&quot;,&quot;77&quot;], target = &quot;7777&quot;
<strong>Output:</strong> 4
<strong>Explanation:</strong> Valid pairs are:
- (0, 1): &quot;777&quot; + &quot;7&quot;
- (1, 0): &quot;7&quot; + &quot;777&quot;
- (2, 3): &quot;77&quot; + &quot;77&quot;
- (3, 2): &quot;77&quot; + &quot;77&quot;
</pre>

<p><strong>Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [&quot;123&quot;,&quot;4&quot;,&quot;12&quot;,&quot;34&quot;], target = &quot;1234&quot;
<strong>Output:</strong> 2
<strong>Explanation:</strong> Valid pairs are:
- (0, 1): &quot;123&quot; + &quot;4&quot;
- (2, 3): &quot;12&quot; + &quot;34&quot;
</pre>

<p><strong>Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [&quot;1&quot;,&quot;1&quot;,&quot;1&quot;], target = &quot;11&quot;
<strong>Output:</strong> 6
<strong>Explanation:</strong> Valid pairs are:
- (0, 1): &quot;1&quot; + &quot;1&quot;
- (1, 0): &quot;1&quot; + &quot;1&quot;
- (0, 2): &quot;1&quot; + &quot;1&quot;
- (2, 0): &quot;1&quot; + &quot;1&quot;
- (1, 2): &quot;1&quot; + &quot;1&quot;
- (2, 1): &quot;1&quot; + &quot;1&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= nums.length &lt;= 100</code></li>
	<li><code>1 &lt;= nums[i].length &lt;= 100</code></li>
	<li><code>2 &lt;= target.length &lt;= 100</code></li>
	<li><code>nums[i]</code> and <code>target</code> consist of digits.</li>
	<li><code>nums[i]</code> and <code>target</code> do not have leading zeros.</li>
</ul>