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leetcode-problemset/算法题(国内版)/originData/[no content]check-if-a-number-is-majority-element-in-a-sorted-array.json

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{
"data": {
"question": {
"questionId": "1102",
"questionFrontendId": "1150",
"categoryTitle": "Algorithms",
"boundTopicId": 4457,
"title": "Check If a Number Is Majority Element in a Sorted Array",
"titleSlug": "check-if-a-number-is-majority-element-in-a-sorted-array",
"content": null,
"translatedTitle": "检查一个数是否在数组中占绝大多数",
"translatedContent": null,
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"difficulty": "Easy",
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"similarQuestions": "[{\"title\": \"Majority Element\", \"titleSlug\": \"majority-element\", \"difficulty\": \"Easy\", \"translatedTitle\": \"\\u591a\\u6570\\u5143\\u7d20\"}, {\"title\": \"Majority Element II\", \"titleSlug\": \"majority-element-ii\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u6c42\\u4f17\\u6570 II\"}]",
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"topicTags": [
{
"name": "Array",
"slug": "array",
"translatedName": "数组",
"__typename": "TopicTagNode"
},
{
"name": "Binary Search",
"slug": "binary-search",
"translatedName": "二分查找",
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"hints": [
"How to check if a given number target is a majority element?.",
"Find the frequency of target and compare it to the length of the array.",
"You can find the frequency of an element using Binary Search since the array is sorted.",
"Using Binary Search, find the first and last occurrences of A. Then just calculate the difference between the indexes of these occurrences."
],
"solution": null,
"status": null,
"sampleTestCase": "[2,4,5,5,5,5,5,6,6]\n5",
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