mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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182 lines
17 KiB
JSON
182 lines
17 KiB
JSON
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"title": "Total Appeal of A String",
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"content": "<p>The <b>appeal</b> of a string is the number of <strong>distinct</strong> characters found in the string.</p>\n\n<ul>\n\t<li>For example, the appeal of <code>"abbca"</code> is <code>3</code> because it has <code>3</code> distinct characters: <code>'a'</code>, <code>'b'</code>, and <code>'c'</code>.</li>\n</ul>\n\n<p>Given a string <code>s</code>, return <em>the <strong>total appeal of all of its <strong>substrings</strong>.</strong></em></p>\n\n<p>A <strong>substring</strong> is a contiguous sequence of characters within a string.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "abbca"\n<strong>Output:</strong> 28\n<strong>Explanation:</strong> The following are the substrings of "abbca":\n- Substrings of length 1: "a", "b", "b", "c", "a" have an appeal of 1, 1, 1, 1, and 1 respectively. The sum is 5.\n- Substrings of length 2: "ab", "bb", "bc", "ca" have an appeal of 2, 1, 2, and 2 respectively. The sum is 7.\n- Substrings of length 3: "abb", "bbc", "bca" have an appeal of 2, 2, and 3 respectively. The sum is 7.\n- Substrings of length 4: "abbc", "bbca" have an appeal of 3 and 3 respectively. The sum is 6.\n- Substrings of length 5: "abbca" has an appeal of 3. The sum is 3.\nThe total sum is 5 + 7 + 7 + 6 + 3 = 28.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "code"\n<strong>Output:</strong> 20\n<strong>Explanation:</strong> The following are the substrings of "code":\n- Substrings of length 1: "c", "o", "d", "e" have an appeal of 1, 1, 1, and 1 respectively. The sum is 4.\n- Substrings of length 2: "co", "od", "de" have an appeal of 2, 2, and 2 respectively. The sum is 6.\n- Substrings of length 3: "cod", "ode" have an appeal of 3 and 3 respectively. The sum is 6.\n- Substrings of length 4: "code" has an appeal of 4. The sum is 4.\nThe total sum is 4 + 6 + 6 + 4 = 20.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
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"Consider the set of substrings that end at a certain index i. Then, consider a specific alphabetic character. How do you count the number of substrings ending at index i that contain that character?",
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"The number of substrings that contain the alphabetic character is equivalent to 1 plus the index of the last occurrence of the character before index i + 1.",
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"The total appeal of all substrings ending at index i is the total sum of the number of substrings that contain each alphabetic character.",
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"To find the total appeal of all substrings, we simply sum up the total appeal for each index."
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