leetcode-problemset/leetcode/originData/number-of-adjacent-elements-with-the-same-color.json

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            "questionId": "2779",
            "questionFrontendId": "2672",
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            "title": "Number of Adjacent Elements With the Same Color",
            "titleSlug": "number-of-adjacent-elements-with-the-same-color",
            "content": "<p>There is a <strong>0-indexed</strong> array <code>nums</code> of length <code>n</code>. Initially, all elements are <strong>uncolored </strong>(has a value of <code>0</code>).</p>\n\n<p>You are given a 2D integer array <code>queries</code> where <code>queries[i] = [index<sub>i</sub>, color<sub>i</sub>]</code>.</p>\n\n<p>For each query, you color the index <code>index<sub>i</sub></code> with the color <code>color<sub>i</sub></code> in the array <code>nums</code>.</p>\n\n<p>Return <em>an array </em><code>answer</code><em> of the same length as </em><code>queries</code><em> where </em><code>answer[i]</code><em> is the number of adjacent elements with the same color <strong>after</strong> the </em><code>i<sup>th</sup></code><em> query</em>.</p>\n\n<p>More formally, <code>answer[i]</code> is the number of indices <code>j</code>, such that <code>0 &lt;= j &lt; n - 1</code> and <code>nums[j] == nums[j + 1]</code> and <code>nums[j] != 0</code> after the <code>i<sup>th</sup></code> query.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4, queries = [[0,2],[1,2],[3,1],[1,1],[2,1]]\n<strong>Output:</strong> [0,1,1,0,2]\n<strong>Explanation:</strong> Initially array nums = [0,0,0,0], where 0 denotes uncolored elements of the array.\n- After the 1<sup>st</sup> query nums = [2,0,0,0]. The count of adjacent elements with the same color is 0.\n- After the 2<sup>nd</sup> query nums = [2,2,0,0]. The count of adjacent elements with the same color is 1.\n- After the 3<sup>rd</sup>&nbsp;query nums = [2,2,0,1]. The count of adjacent elements with the same color is 1.\n- After the 4<sup>th</sup>&nbsp;query nums = [2,1,0,1]. The count of adjacent elements with the same color is 0.\n- After the 5<sup>th</sup>&nbsp;query nums = [2,1,1,1]. The count of adjacent elements with the same color is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1, queries = [[0,100000]]\n<strong>Output:</strong> [0]\n<strong>Explanation:</strong> Initially array nums = [0], where 0 denotes uncolored elements of the array.\n- After the 1<sup>st</sup> query nums = [100000]. The count of adjacent elements with the same color is 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>queries[i].length&nbsp;== 2</code></li>\n\t<li><code>0 &lt;= index<sub>i</sub>&nbsp;&lt;= n - 1</code></li>\n\t<li><code>1 &lt;=&nbsp; color<sub>i</sub>&nbsp;&lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<int> colorTheArray(int n, vector<vector<int>>& queries) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int[] colorTheArray(int n, int[][] queries) {\n        \n    }\n}",
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                    "lang": "Python",
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                    "code": "class Solution(object):\n    def colorTheArray(self, n, queries):\n        \"\"\"\n        :type n: int\n        :type queries: List[List[int]]\n        :rtype: List[int]\n        \"\"\"\n        ",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* colorTheArray(int n, int** queries, int queriesSize, int* queriesColSize, int* returnSize){\n\n}",
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                    "lang": "C#",
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                    "code": "public class Solution {\n    public int[] ColorTheArray(int n, int[][] queries) {\n        \n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * @param {number} n\n * @param {number[][]} queries\n * @return {number[]}\n */\nvar colorTheArray = function(n, queries) {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer $n\n     * @param Integer[][] $queries\n     * @return Integer[]\n     */\n    function colorTheArray($n, $queries) {\n        \n    }\n}",
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                    "code": "class Solution {\n    func colorTheArray(_ n: Int, _ queries: [[Int]]) -> [Int] {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun colorTheArray(n: Int, queries: Array<IntArray>): IntArray {\n        \n    }\n}",
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                    "code": "class Solution {\n  List<int> colorTheArray(int n, List<List<int>> queries) {\n\n  }\n}",
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                    "lang": "Go",
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                    "code": "func colorTheArray(n int, queries [][]int) []int {\n    \n}",
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                    "code": "# @param {Integer} n\n# @param {Integer[][]} queries\n# @return {Integer[]}\ndef color_the_array(n, queries)\n    \nend",
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                    "code": "object Solution {\n    def colorTheArray(n: Int, queries: Array[Array[Int]]): Array[Int] = {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn color_the_array(n: i32, queries: Vec<Vec<i32>>) -> Vec<i32> {\n        \n    }\n}",
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                    "code": "-spec color_the_array(N :: integer(), Queries :: [[integer()]]) -> [integer()].\ncolor_the_array(N, Queries) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec color_the_array(n :: integer, queries :: [[integer]]) :: [integer]\n  def color_the_array(n, queries) do\n\n  end\nend",
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            "hints": [
                "Since at each query, only one element is being recolored, we just need to focus on its neighbors.",
                "If an element that is changed on the i-th query had the same color as its right element answer decreases by 1. Similarly contributes its left element too.",
                "After changing the color, if the element has the same color as its right element answer increases by 1. Similarly contributes its left element too."
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