mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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165 lines
17 KiB
JSON
165 lines
17 KiB
JSON
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"questionId": "858",
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"title": "Masking Personal Information",
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"titleSlug": "masking-personal-information",
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"content": "<p>You are given a personal information string <code>s</code>, representing either an <strong>email address</strong> or a <strong>phone number</strong>. Return <em>the <strong>masked</strong> personal information using the below rules</em>.</p>\n\n<p><u><strong>Email address:</strong></u></p>\n\n<p>An email address is:</p>\n\n<ul>\n\t<li>A <strong>name</strong> consisting of uppercase and lowercase English letters, followed by</li>\n\t<li>The <code>'@'</code> symbol, followed by</li>\n\t<li>The <strong>domain</strong> consisting of uppercase and lowercase English letters with a dot <code>'.'</code> somewhere in the middle (not the first or last character).</li>\n</ul>\n\n<p>To mask an email:</p>\n\n<ul>\n\t<li>The uppercase letters in the <strong>name</strong> and <strong>domain</strong> must be converted to lowercase letters.</li>\n\t<li>The middle letters of the <strong>name</strong> (i.e., all but the first and last letters) must be replaced by 5 asterisks <code>"*****"</code>.</li>\n</ul>\n\n<p><u><strong>Phone number:</strong></u></p>\n\n<p>A phone number is formatted as follows:</p>\n\n<ul>\n\t<li>The phone number contains 10-13 digits.</li>\n\t<li>The last 10 digits make up the <strong>local number</strong>.</li>\n\t<li>The remaining 0-3 digits, in the beginning, make up the <strong>country code</strong>.</li>\n\t<li><strong>Separation characters</strong> from the set <code>{'+', '-', '(', ')', ' '}</code> separate the above digits in some way.</li>\n</ul>\n\n<p>To mask a phone number:</p>\n\n<ul>\n\t<li>Remove all <strong>separation characters</strong>.</li>\n\t<li>The masked phone number should have the form:\n\t<ul>\n\t\t<li><code>"***-***-XXXX"</code> if the country code has 0 digits.</li>\n\t\t<li><code>"+*-***-***-XXXX"</code> if the country code has 1 digit.</li>\n\t\t<li><code>"+**-***-***-XXXX"</code> if the country code has 2 digits.</li>\n\t\t<li><code>"+***-***-***-XXXX"</code> if the country code has 3 digits.</li>\n\t</ul>\n\t</li>\n\t<li><code>"XXXX"</code> is the last 4 digits of the <strong>local number</strong>.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "LeetCode@LeetCode.com"\n<strong>Output:</strong> "l*****e@leetcode.com"\n<strong>Explanation:</strong> s is an email address.\nThe name and domain are converted to lowercase, and the middle of the name is replaced by 5 asterisks.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "AB@qq.com"\n<strong>Output:</strong> "a*****b@qq.com"\n<strong>Explanation:</strong> s is an email address.\nThe name and domain are converted to lowercase, and the middle of the name is replaced by 5 asterisks.\nNote that even though "ab" is 2 characters, it still must have 5 asterisks in the middle.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "1(234)567-890"\n<strong>Output:</strong> "***-***-7890"\n<strong>Explanation:</strong> s is a phone number.\nThere are 10 digits, so the local number is 10 digits and the country code is 0 digits.\nThus, the resulting masked number is "***-***-7890".\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>s</code> is either a <strong>valid</strong> email or a phone number.</li>\n\t<li>If <code>s</code> is an email:\n\t<ul>\n\t\t<li><code>8 <= s.length <= 40</code></li>\n\t\t<li><code>s</code> consists of uppercase and lowercase English letters and exactly one <code>'@'</code> symbol and <code>'.'</code> symbol.</li>\n\t</ul>\n\t</li>\n\t<li>If <code>s</code> is a phone number:\n\t<ul>\n\t\t<li><code>10 <= s.length <= 20</code></li>\n\t\t<li><code>s</code> consists of digits, spaces, and the symbols <code>'('</code>, <code>')'</code>, <code>'-'</code>, and <code>'+'</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n",
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"isPaidOnly": false,
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"difficulty": "Medium",
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"likes": 159,
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"exampleTestcases": "\"LeetCode@LeetCode.com\"\n\"AB@qq.com\"\n\"1(234)567-890\"",
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"categoryTitle": "Algorithms",
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"contributors": [],
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"name": "String",
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"code": "class Solution(object):\n def maskPII(self, s):\n \"\"\"\n :type s: str\n :rtype: str\n \"\"\"\n ",
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"lang": "Kotlin",
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"lang": "Go",
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"code": "# @param {String} s\n# @return {String}\ndef mask_pii(s)\n \nend",
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"code": "object Solution {\n def maskPII(s: String): String = {\n \n }\n}",
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"code": "impl Solution {\n pub fn mask_pii(s: String) -> String {\n \n }\n}",
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"lang": "Erlang",
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"code": "-spec mask_pii(S :: unicode:unicode_binary()) -> unicode:unicode_binary().\nmask_pii(S) ->\n .",
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"code": "defmodule Solution do\n @spec mask_pii(s :: String.t) :: String.t\n def mask_pii(s) do\n \n end\nend",
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"sampleTestCase": "\"LeetCode@LeetCode.com\"",
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"metaData": "{\n \"name\": \"maskPII\",\n \"params\": [\n {\n \"name\": \"s\",\n \"type\": \"string\"\n }\n ],\n \"return\": {\n \"type\": \"string\"\n }\n}",
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