leetcode-problemset/leetcode/originData/hash-divided-string.json

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        "question": {
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            "title": "Hash Divided String",
            "titleSlug": "hash-divided-string",
            "content": "<p>You are given a string <code>s</code> of length <code>n</code> and an integer <code>k</code>, where <code>n</code> is a <strong>multiple</strong> of <code>k</code>. Your task is to hash the string <code>s</code> into a new string called <code>result</code>, which has a length of <code>n / k</code>.</p>\n\n<p>First, divide <code>s</code> into <code>n / k</code> <strong><span data-keyword=\"substring-nonempty\">substrings</span></strong>, each with a length of <code>k</code>. Then, initialize <code>result</code> as an <strong>empty</strong> string.</p>\n\n<p>For each <strong>substring</strong> in order from the beginning:</p>\n\n<ul>\n\t<li>The <strong>hash value</strong> of a character is the index of that characte<!-- notionvc: 4b67483a-fa95-40b6-870d-2eacd9bc18d8 -->r in the <strong>English alphabet</strong> (e.g., <code>&#39;a&#39; &rarr;<!-- notionvc: d3f8e4c2-23cd-41ad-a14b-101dfe4c5aba --> 0</code>, <code>&#39;b&#39; &rarr;<!-- notionvc: d3f8e4c2-23cd-41ad-a14b-101dfe4c5aba --> 1</code>, ..., <code>&#39;z&#39; &rarr;<!-- notionvc: d3f8e4c2-23cd-41ad-a14b-101dfe4c5aba --> 25</code>).</li>\n\t<li>Calculate the <em>sum</em> of all the <strong>hash values</strong> of the characters in the substring.</li>\n\t<li>Find the remainder of this sum when divided by 26, which is called <code>hashedChar</code>.</li>\n\t<li>Identify the character in the English lowercase alphabet that corresponds to <code>hashedChar</code>.</li>\n\t<li>Append that character to the end of <code>result</code>.</li>\n</ul>\n\n<p>Return <code>result</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;abcd&quot;, k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">&quot;bf&quot;</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>First substring: <code>&quot;ab&quot;</code>, <code>0 + 1 = 1</code>, <code>1 % 26 = 1</code>, <code>result[0] = &#39;b&#39;</code>.</p>\n\n<p>Second substring: <code>&quot;cd&quot;</code>, <code>2 + 3 = 5</code>, <code>5 % 26 = 5</code>, <code>result[1] = &#39;f&#39;</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;mxz&quot;, k = 3</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">&quot;i&quot;</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The only substring: <code>&quot;mxz&quot;</code>, <code>12 + 23 + 25 = 60</code>, <code>60 % 26 = 8</code>, <code>result[0] = &#39;i&#39;</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= 100</code></li>\n\t<li><code>k &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s.length</code> is divisible by <code>k</code>.</li>\n\t<li><code>s</code> consists only of lowercase English letters.</li>\n</ul>\n",
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            "difficulty": "Medium",
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            "exampleTestcases": "\"abcd\"\n2\n\"mxz\"\n3",
            "categoryTitle": "Algorithms",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    string stringHash(string s, int k) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def stringHash(self, s, k):\n        \"\"\"\n        :type s: str\n        :type k: int\n        :rtype: str\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def stringHash(self, s: str, k: int) -> str:\n        ",
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                    "code": "public class Solution {\n    public string StringHash(string s, int k) {\n        \n    }\n}",
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                    "code": "/**\n * @param {string} s\n * @param {number} k\n * @return {string}\n */\nvar stringHash = function(s, k) {\n    \n};",
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                    "code": "function stringHash(s: string, k: number): string {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param String $s\n     * @param Integer $k\n     * @return String\n     */\n    function stringHash($s, $k) {\n        \n    }\n}",
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                    "code": "class Solution {\n    func stringHash(_ s: String, _ k: Int) -> String {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun stringHash(s: String, k: Int): String {\n        \n    }\n}",
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                    "lang": "Go",
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                    "code": "func stringHash(s string, k int) string {\n    \n}",
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                    "code": "# @param {String} s\n# @param {Integer} k\n# @return {String}\ndef string_hash(s, k)\n    \nend",
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                    "code": "object Solution {\n    def stringHash(s: String, k: Int): String = {\n        \n    }\n}",
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                    "lang": "Rust",
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                    "code": "impl Solution {\n    pub fn string_hash(s: String, k: i32) -> String {\n        \n    }\n}",
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                {
                    "lang": "Racket",
                    "langSlug": "racket",
                    "code": "(define/contract (string-hash s k)\n  (-> string? exact-integer? string?)\n  )",
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                    "lang": "Erlang",
                    "langSlug": "erlang",
                    "code": "-spec string_hash(S :: unicode:unicode_binary(), K :: integer()) -> unicode:unicode_binary().\nstring_hash(S, K) ->\n  .",
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                    "lang": "Elixir",
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                    "code": "defmodule Solution do\n  @spec string_hash(s :: String.t, k :: integer) :: String.t\n  def string_hash(s, k) do\n    \n  end\nend",
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            "hints": [
                "Try to find each substring.",
                "Use a for loop to find <code>hashedChar</code> of each substring.",
                "Find the answer using <code>hashedChar</code> of each substring."
            ],
            "solution": null,
            "status": null,
            "sampleTestCase": "\"abcd\"\n2",
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