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leetcode-problemset/leetcode/originData/even-odd-tree.json
2023-12-09 19:57:46 +08:00

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JSON

{
"data": {
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"questionId": "1731",
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"title": "Even Odd Tree",
"titleSlug": "even-odd-tree",
"content": "<p>A binary tree is named <strong>Even-Odd</strong> if it meets the following conditions:</p>\n\n<ul>\n\t<li>The root of the binary tree is at level index <code>0</code>, its children are at level index <code>1</code>, their children are at level index <code>2</code>, etc.</li>\n\t<li>For every <strong>even-indexed</strong> level, all nodes at the level have <strong>odd</strong> integer values in <strong>strictly increasing</strong> order (from left to right).</li>\n\t<li>For every <b>odd-indexed</b> level, all nodes at the level have <b>even</b> integer values in <strong>strictly decreasing</strong> order (from left to right).</li>\n</ul>\n\n<p>Given the <code>root</code> of a binary tree, <em>return </em><code>true</code><em> if the binary tree is <strong>Even-Odd</strong>, otherwise return </em><code>false</code><em>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/sample_1_1966.png\" style=\"width: 362px; height: 229px;\" />\n<pre>\n<strong>Input:</strong> root = [1,10,4,3,null,7,9,12,8,6,null,null,2]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> The node values on each level are:\nLevel 0: [1]\nLevel 1: [10,4]\nLevel 2: [3,7,9]\nLevel 3: [12,8,6,2]\nSince levels 0 and 2 are all odd and increasing and levels 1 and 3 are all even and decreasing, the tree is Even-Odd.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/sample_2_1966.png\" style=\"width: 363px; height: 167px;\" />\n<pre>\n<strong>Input:</strong> root = [5,4,2,3,3,7]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> The node values on each level are:\nLevel 0: [5]\nLevel 1: [4,2]\nLevel 2: [3,3,7]\nNode values in level 2 must be in strictly increasing order, so the tree is not Even-Odd.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/22/sample_1_333_1966.png\" style=\"width: 363px; height: 167px;\" />\n<pre>\n<strong>Input:</strong> root = [5,9,1,3,5,7]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> Node values in the level 1 should be even integers.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>5</sup>]</code>.</li>\n\t<li><code>1 &lt;= Node.val &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n bool isEvenOddTree(TreeNode* root) {\n \n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public boolean isEvenOddTree(TreeNode root) {\n \n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def isEvenOddTree(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: bool\n \"\"\"\n ",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def isEvenOddTree(self, root: Optional[TreeNode]) -> bool:\n ",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\nbool isEvenOddTree(struct TreeNode* root) {\n \n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public bool IsEvenOddTree(TreeNode root) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {boolean}\n */\nvar isEvenOddTree = function(root) {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction isEvenOddTree(root: TreeNode | null): boolean {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Boolean\n */\n function isEvenOddTree($root) {\n \n }\n}",
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"lang": "Swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func isEvenOddTree(_ root: TreeNode?) -> Bool {\n \n }\n}",
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"lang": "Kotlin",
"langSlug": "kotlin",
"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun isEvenOddTree(root: TreeNode?): Boolean {\n \n }\n}",
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"lang": "Dart",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n bool isEvenOddTree(TreeNode? root) {\n \n }\n}",
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"lang": "Go",
"langSlug": "golang",
"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc isEvenOddTree(root *TreeNode) bool {\n \n}",
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"lang": "Ruby",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Boolean}\ndef is_even_odd_tree(root)\n \nend",
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"lang": "Scala",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def isEvenOddTree(root: TreeNode): Boolean = {\n \n }\n}",
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"lang": "Rust",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn is_even_odd_tree(root: Option<Rc<RefCell<TreeNode>>>) -> bool {\n \n }\n}",
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"lang": "Racket",
"langSlug": "racket",
"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (is-even-odd-tree root)\n (-> (or/c tree-node? #f) boolean?)\n )",
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"lang": "Elixir",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec is_even_odd_tree(root :: TreeNode.t | nil) :: boolean\n def is_even_odd_tree(root) do\n \n end\nend",
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"hints": [
"Use the breadth-first search to go through all nodes layer by layer."
],
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