leetcode-problemset/leetcode-cn/originData/word-subsets.json

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        "question": {
            "questionId": "952",
            "questionFrontendId": "916",
            "categoryTitle": "Algorithms",
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            "title": "Word Subsets",
            "titleSlug": "word-subsets",
            "content": "<p>You are given two string arrays <code>words1</code> and <code>words2</code>.</p>\n\n<p>A string <code>b</code> is a <strong>subset</strong> of string <code>a</code> if every letter in <code>b</code> occurs in <code>a</code> including multiplicity.</p>\n\n<ul>\n\t<li>For example, <code>&quot;wrr&quot;</code> is a subset of <code>&quot;warrior&quot;</code> but is not a subset of <code>&quot;world&quot;</code>.</li>\n</ul>\n\n<p>A string <code>a</code> from <code>words1</code> is <strong>universal</strong> if for every string <code>b</code> in <code>words2</code>, <code>b</code> is a subset of <code>a</code>.</p>\n\n<p>Return an array of all the <strong>universal</strong> strings in <code>words1</code>. You may return the answer in <strong>any order</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words1 = [&quot;amazon&quot;,&quot;apple&quot;,&quot;facebook&quot;,&quot;google&quot;,&quot;leetcode&quot;], words2 = [&quot;e&quot;,&quot;o&quot;]\n<strong>Output:</strong> [&quot;facebook&quot;,&quot;google&quot;,&quot;leetcode&quot;]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words1 = [&quot;amazon&quot;,&quot;apple&quot;,&quot;facebook&quot;,&quot;google&quot;,&quot;leetcode&quot;], words2 = [&quot;l&quot;,&quot;e&quot;]\n<strong>Output:</strong> [&quot;apple&quot;,&quot;google&quot;,&quot;leetcode&quot;]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words1.length, words2.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words1[i].length, words2[i].length &lt;= 10</code></li>\n\t<li><code>words1[i]</code> and <code>words2[i]</code> consist only of lowercase English letters.</li>\n\t<li>All the strings of <code>words1</code> are <strong>unique</strong>.</li>\n</ul>\n",
            "translatedTitle": "单词子集",
            "translatedContent": "<p>给你两个字符串数组 <code>words1</code>&nbsp;和&nbsp;<code>words2</code>。</p>\n\n<p>现在，如果&nbsp;<code>b</code> 中的每个字母都出现在 <code>a</code> 中，<strong>包括重复出现的字母</strong>，那么称字符串 <code>b</code> 是字符串 <code>a</code> 的 <strong>子集</strong> 。</p>\n\n<ul>\n\t<li>例如，<code>\"wrr\"</code> 是 <code>\"warrior\"</code> 的子集，但不是 <code>\"world\"</code> 的子集。</li>\n</ul>\n\n<p>如果对 <code>words2</code> 中的每一个单词&nbsp;<code>b</code>，<code>b</code> 都是 <code>a</code> 的子集，那么我们称&nbsp;<code>words1</code> 中的单词 <code>a</code> 是<em> </em><strong>通用单词</strong><em> </em>。</p>\n\n<p>以数组形式返回&nbsp;<code>words1</code> 中所有的通用单词。你可以按 <strong>任意顺序</strong> 返回答案。</p>\n\n<p>&nbsp;</p>\n\n<ol>\n</ol>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>words1 = [\"amazon\",\"apple\",\"facebook\",\"google\",\"leetcode\"], words2 = [\"e\",\"o\"]\n<strong>输出：</strong>[\"facebook\",\"google\",\"leetcode\"]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>words1 = [\"amazon\",\"apple\",\"facebook\",\"google\",\"leetcode\"], words2 = [\"l\",\"e\"]\n<strong>输出：</strong>[\"apple\",\"google\",\"leetcode\"]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>words1 = [\"amazon\",\"apple\",\"facebook\",\"google\",\"leetcode\"], words2 = [\"e\",\"oo\"]\n<strong>输出：</strong>[\"facebook\",\"google\"]\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>words1 = [\"amazon\",\"apple\",\"facebook\",\"google\",\"leetcode\"], words2 = [\"lo\",\"eo\"]\n<strong>输出：</strong>[\"google\",\"leetcode\"]\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>words1 = [\"amazon\",\"apple\",\"facebook\",\"google\",\"leetcode\"], words2 = [\"ec\",\"oc\",\"ceo\"]\n<strong>输出：</strong>[\"facebook\",\"leetcode\"]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words1.length, words2.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words1[i].length, words2[i].length &lt;= 10</code></li>\n\t<li><code>words1[i]</code> 和 <code>words2[i]</code> 仅由小写英文字母组成</li>\n\t<li><code>words1</code> 中的所有字符串 <strong>互不相同</strong></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<string> wordSubsets(vector<string>& words1, vector<string>& words2) {\n\n    }\n};",
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                    "code": "class Solution {\n    public List<String> wordSubsets(String[] words1, String[] words2) {\n\n    }\n}",
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                    "code": "class Solution(object):\n    def wordSubsets(self, words1, words2):\n        \"\"\"\n        :type words1: List[str]\n        :type words2: List[str]\n        :rtype: List[str]\n        \"\"\"",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** wordSubsets(char** words1, int words1Size, char** words2, int words2Size, int* returnSize) {\n    \n}",
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                    "code": "public class Solution {\n    public IList<string> WordSubsets(string[] words1, string[] words2) {\n\n    }\n}",
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                    "code": "/**\n * @param {string[]} words1\n * @param {string[]} words2\n * @return {string[]}\n */\nvar wordSubsets = function(words1, words2) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param String[] $words1\n     * @param String[] $words2\n     * @return String[]\n     */\n    function wordSubsets($words1, $words2) {\n\n    }\n}",
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                    "code": "class Solution {\n    fun wordSubsets(words1: Array<String>, words2: Array<String>): List<String> {\n\n    }\n}",
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                    "code": "class Solution {\n  List<String> wordSubsets(List<String> words1, List<String> words2) {\n    \n  }\n}",
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                    "code": "# @param {String[]} words1\n# @param {String[]} words2\n# @return {String[]}\ndef word_subsets(words1, words2)\n\nend",
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                    "code": "object Solution {\n    def wordSubsets(words1: Array[String], words2: Array[String]): List[String] = {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn word_subsets(words1: Vec<String>, words2: Vec<String>) -> Vec<String> {\n\n    }\n}",
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                    "code": "defmodule Solution do\n  @spec word_subsets(words1 :: [String.t], words2 :: [String.t]) :: [String.t]\n  def word_subsets(words1, words2) do\n    \n  end\nend",
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