mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
186 lines
27 KiB
JSON
186 lines
27 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "98",
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"questionFrontendId": "98",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1297,
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"title": "Validate Binary Search Tree",
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"titleSlug": "validate-binary-search-tree",
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"content": "<p>Given the <code>root</code> of a binary tree, <em>determine if it is a valid binary search tree (BST)</em>.</p>\n\n<p>A <strong>valid BST</strong> is defined as follows:</p>\n\n<ul>\n\t<li>The left <span data-keyword=\"subtree\">subtree</span> of a node contains only nodes with keys <strong>less than</strong> the node's key.</li>\n\t<li>The right subtree of a node contains only nodes with keys <strong>greater than</strong> the node's key.</li>\n\t<li>Both the left and right subtrees must also be binary search trees.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/01/tree1.jpg\" style=\"width: 302px; height: 182px;\" />\n<pre>\n<strong>Input:</strong> root = [2,1,3]\n<strong>Output:</strong> true\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/01/tree2.jpg\" style=\"width: 422px; height: 292px;\" />\n<pre>\n<strong>Input:</strong> root = [5,1,4,null,null,3,6]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> The root node's value is 5 but its right child's value is 4.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-2<sup>31</sup> <= Node.val <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"translatedTitle": "验证二叉搜索树",
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"translatedContent": "<p>给你一个二叉树的根节点 <code>root</code> ，判断其是否是一个有效的二叉搜索树。</p>\n\n<p><strong>有效</strong> 二叉搜索树定义如下：</p>\n\n<ul>\n\t<li>节点的左子树只包含<strong> 小于 </strong>当前节点的数。</li>\n\t<li>节点的右子树只包含 <strong>大于</strong> 当前节点的数。</li>\n\t<li>所有左子树和右子树自身必须也是二叉搜索树。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/01/tree1.jpg\" style=\"width: 302px; height: 182px;\" />\n<pre>\n<strong>输入：</strong>root = [2,1,3]\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/01/tree2.jpg\" style=\"width: 422px; height: 292px;\" />\n<pre>\n<strong>输入：</strong>root = [5,1,4,null,null,3,6]\n<strong>输出：</strong>false\n<strong>解释：</strong>根节点的值是 5 ，但是右子节点的值是 4 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数目范围在<code>[1, 10<sup>4</sup>]</code> 内</li>\n\t<li><code>-2<sup>31</sup> <= Node.val <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"difficulty": "Medium",
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"name": "Depth-First Search",
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"translatedName": "深度优先搜索",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n bool isValidBST(TreeNode* root) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public boolean isValidBST(TreeNode root) {\n\n }\n}",
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"lang": "Python",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def isValidBST(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: bool\n \"\"\"\n ",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def isValidBST(self, root: Optional[TreeNode]) -> bool:",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public bool IsValidBST(TreeNode root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {boolean}\n */\nvar isValidBST = function(root) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction isValidBST(root: TreeNode | null): boolean {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Boolean\n */\n function isValidBST($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func isValidBST(_ root: TreeNode?) -> Bool {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun isValidBST(root: TreeNode?): Boolean {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n bool isValidBST(TreeNode? root) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc isValidBST(root *TreeNode) bool {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Boolean}\ndef is_valid_bst(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def isValidBST(root: TreeNode): Boolean = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn is_valid_bst(root: Option<Rc<RefCell<TreeNode>>>) -> bool {\n\n }\n}",
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