leetcode-problemset/leetcode-cn/originData/time-taken-to-mark-all-nodes.json

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        "question": {
            "questionId": "3532",
            "questionFrontendId": "3241",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2868081,
            "title": "Time Taken to Mark All Nodes",
            "titleSlug": "time-taken-to-mark-all-nodes",
            "content": "<p>There exists an <strong>undirected</strong> tree with <code>n</code> nodes numbered <code>0</code> to <code>n - 1</code>. You are given a 2D integer array <code>edges</code> of length <code>n - 1</code>, where <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> indicates that there is an edge between nodes <code>u<sub>i</sub></code> and <code>v<sub>i</sub></code> in the tree.</p>\n\n<p>Initially, <strong>all</strong> nodes are <strong>unmarked</strong>. For each node <code>i</code>:</p>\n\n<ul>\n\t<li>If <code>i</code> is odd, the node will get marked at time <code>x</code> if there is <strong>at least</strong> one node <em>adjacent</em> to it which was marked at time <code>x - 1</code>.</li>\n\t<li>If <code>i</code> is even, the node will get marked at time <code>x</code> if there is <strong>at least</strong> one node <em>adjacent</em> to it which was marked at time <code>x - 2</code>.</li>\n</ul>\n\n<p>Return an array <code>times</code> where <code>times[i]</code> is the time when all nodes get marked in the tree, if you mark node <code>i</code> at time <code>t = 0</code>.</p>\n\n<p><strong>Note</strong> that the answer for each <code>times[i]</code> is <strong>independent</strong>, i.e. when you mark node <code>i</code> all other nodes are <em>unmarked</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">edges = [[0,1],[0,2]]</span></p>\n\n<p><strong>Output:</strong> [2,4,3]</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122236.png\" style=\"width: 500px; height: 241px;\" /></p>\n\n<ul>\n\t<li>For <code>i = 0</code>:\n\n\t<ul>\n\t\t<li>Node 1 is marked at <code>t = 1</code>, and Node 2 at <code>t = 2</code>.</li>\n\t</ul>\n\t</li>\n\t<li>For <code>i = 1</code>:\n\t<ul>\n\t\t<li>Node 0 is marked at <code>t = 2</code>, and Node 2 at <code>t = 4</code>.</li>\n\t</ul>\n\t</li>\n\t<li>For <code>i = 2</code>:\n\t<ul>\n\t\t<li>Node 0 is marked at <code>t = 2</code>, and Node 1 at <code>t = 3</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">edges = [[0,1]]</span></p>\n\n<p><strong>Output:</strong> [1,2]</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122249.png\" style=\"width: 500px; height: 257px;\" /></p>\n\n<ul>\n\t<li>For <code>i = 0</code>:\n\n\t<ul>\n\t\t<li>Node 1 is marked at <code>t = 1</code>.</li>\n\t</ul>\n\t</li>\n\t<li>For <code>i = 1</code>:\n\t<ul>\n\t\t<li>Node 0 is marked at <code>t = 2</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">edges = </span>[[2,4],[0,1],[2,3],[0,2]]</p>\n\n<p><strong>Output:</strong> [4,6,3,5,5]</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/03/screenshot-2024-06-03-210550.png\" style=\"height: 266px; width: 500px;\" /></p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>edges.length == n - 1</code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= edges[i][0], edges[i][1] &lt;= n - 1</code></li>\n\t<li>The input is generated such that <code>edges</code> represents a valid tree.</li>\n</ul>\n",
            "translatedTitle": "标记所有节点需要的时间",
            "translatedContent": "<p>给你一棵 <strong>无向</strong>&nbsp;树，树中节点从 <code>0</code>&nbsp;到 <code>n - 1</code>&nbsp;编号。同时给你一个长度为 <code>n - 1</code>&nbsp;的二维整数数组&nbsp;<code>edges</code>&nbsp;，其中&nbsp;<code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>]</code>&nbsp;表示节点&nbsp;<code>u<sub>i</sub></code> 和&nbsp;<code>v<sub>i</sub></code>&nbsp;在树中有一条边。</p>\n\n<p>一开始，<strong>所有</strong>&nbsp;节点都 <strong>未标记</strong>&nbsp;。对于节点 <code>i</code>&nbsp;：</p>\n\n<ul>\n\t<li>当&nbsp;<code>i</code>&nbsp;是奇数时，如果时刻 <code>x - 1</code>&nbsp;该节点有 <strong>至少</strong>&nbsp;一个相邻节点已经被标记了，那么节点 <code>i</code>&nbsp;会在时刻 <code>x</code>&nbsp;被标记。</li>\n\t<li>当&nbsp;<code>i</code>&nbsp;是偶数时，如果时刻 <code>x - 2</code>&nbsp;该节点有 <strong>至少</strong>&nbsp;一个相邻节点已经被标记了，那么节点 <code>i</code>&nbsp;会在时刻 <code>x</code>&nbsp;被标记。</li>\n</ul>\n\n<p>请你返回一个数组&nbsp;<code>times</code>&nbsp;，表示如果你在时刻 <code>t = 0</code>&nbsp;标记节点 <code>i</code>&nbsp;，那么时刻 <code>times[i]</code>&nbsp;时，树中所有节点都会被标记。</p>\n\n<p>请注意，每个 <code>times[i]</code> 的答案都是独立的，即当你标记节点 <code>i</code> 时，所有其他节点都未标记。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>edges = [[0,1],[0,2]]</span></p>\n\n<p><b>输出：</b>[2,4,3]</p>\n\n<p><strong>解释：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122236.png\" style=\"width: 500px; height: 241px;\" /></p>\n\n<ul>\n\t<li>对于&nbsp;<code>i = 0</code>&nbsp;：\n\n\t<ul>\n\t\t<li>节点 1 在时刻&nbsp;<code>t = 1</code>&nbsp;被标记，节点 2 在时刻&nbsp;<code>t = 2</code>&nbsp;被标记。</li>\n\t</ul>\n\t</li>\n\t<li>对于&nbsp;<code>i = 1</code>&nbsp;：\n\t<ul>\n\t\t<li>节点 0 在时刻&nbsp;<code>t = 2</code>&nbsp;被标记，节点 2 在时刻&nbsp;<code>t = 4</code>&nbsp;被标记。</li>\n\t</ul>\n\t</li>\n\t<li>对于&nbsp;<code>i = 2</code>&nbsp;：\n\t<ul>\n\t\t<li>节点 0 在时刻&nbsp;<code>t = 2</code>&nbsp;被标记，节点 1 在时刻&nbsp;<code>t = 3</code>&nbsp;被标记。</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>edges = [[0,1]]</span></p>\n\n<p><b>输出：</b>[1,2]</p>\n\n<p><strong>解释：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122249.png\" style=\"width: 500px; height: 257px;\" /></p>\n\n<ul>\n\t<li>对于&nbsp;<code>i = 0</code>&nbsp;：\n\n\t<ul>\n\t\t<li>节点 1 在时刻&nbsp;<code>t = 1</code>&nbsp;被标记。</li>\n\t</ul>\n\t</li>\n\t<li>对于&nbsp;<code>i = 1</code>&nbsp;：\n\t<ul>\n\t\t<li>节点 0 在时刻&nbsp;<code>t = 2</code>&nbsp;被标记。</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>edges = </span>[[2,4],[0,1],[2,3],[0,2]]</p>\n\n<p><b>输出：</b>[4,6,3,5,5]</p>\n\n<p><b>解释：</b></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/03/screenshot-2024-06-03-210550.png\" style=\"height: 266px; width: 500px;\" /></p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>edges.length == n - 1</code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= edges[i][0], edges[i][1] &lt;= n - 1</code></li>\n\t<li>输入保证&nbsp;<code>edges</code>&nbsp;表示一棵合法的树。</li>\n</ul>\n",
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<code>out-of-bounds<\\/code> \\u548c <code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = 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