leetcode-problemset/leetcode-cn/originData/target-sum.json

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            "categoryTitle": "Algorithms",
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            "title": "Target Sum",
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            "content": "<p>You are given an integer array <code>nums</code> and an integer <code>target</code>.</p>\n\n<p>You want to build an <strong>expression</strong> out of nums by adding one of the symbols <code>&#39;+&#39;</code> and <code>&#39;-&#39;</code> before each integer in nums and then concatenate all the integers.</p>\n\n<ul>\n\t<li>For example, if <code>nums = [2, 1]</code>, you can add a <code>&#39;+&#39;</code> before <code>2</code> and a <code>&#39;-&#39;</code> before <code>1</code> and concatenate them to build the expression <code>&quot;+2-1&quot;</code>.</li>\n</ul>\n\n<p>Return the number of different <strong>expressions</strong> that you can build, which evaluates to <code>target</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,1,1,1], target = 3\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> There are 5 ways to assign symbols to make the sum of nums be target 3.\n-1 + 1 + 1 + 1 + 1 = 3\n+1 - 1 + 1 + 1 + 1 = 3\n+1 + 1 - 1 + 1 + 1 = 3\n+1 + 1 + 1 - 1 + 1 = 3\n+1 + 1 + 1 + 1 - 1 = 3\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1], target = 1\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 20</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>0 &lt;= sum(nums[i]) &lt;= 1000</code></li>\n\t<li><code>-1000 &lt;= target &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "目标和",
            "translatedContent": "<p>给你一个非负整数数组 <code>nums</code> 和一个整数 <code>target</code> 。</p>\n\n<p>向数组中的每个整数前添加&nbsp;<code>'+'</code> 或 <code>'-'</code> ，然后串联起所有整数，可以构造一个 <strong>表达式</strong> ：</p>\n\n<ul>\n\t<li>例如，<code>nums = [2, 1]</code> ，可以在 <code>2</code> 之前添加 <code>'+'</code> ，在 <code>1</code> 之前添加 <code>'-'</code> ，然后串联起来得到表达式 <code>\"+2-1\"</code> 。</li>\n</ul>\n\n<p>返回可以通过上述方法构造的、运算结果等于 <code>target</code> 的不同 <strong>表达式</strong> 的数目。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,1,1,1,1], target = 3\n<strong>输出：</strong>5\n<strong>解释：</strong>一共有 5 种方法让最终目标和为 3 。\n-1 + 1 + 1 + 1 + 1 = 3\n+1 - 1 + 1 + 1 + 1 = 3\n+1 + 1 - 1 + 1 + 1 = 3\n+1 + 1 + 1 - 1 + 1 = 3\n+1 + 1 + 1 + 1 - 1 = 3\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1], target = 1\n<strong>输出：</strong>1\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 20</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>0 &lt;= sum(nums[i]) &lt;= 1000</code></li>\n\t<li><code>-1000 &lt;= target &lt;= 1000</code></li>\n</ul>\n",
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