leetcode-problemset/leetcode-cn/originData/sum-of-beauty-of-all-substrings.json

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            "questionId": "1890",
            "questionFrontendId": "1781",
            "categoryTitle": "Algorithms",
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            "title": "Sum of Beauty of All Substrings",
            "titleSlug": "sum-of-beauty-of-all-substrings",
            "content": "<p>The <strong>beauty</strong> of a string is the difference in frequencies between the most frequent and least frequent characters.</p>\n\n<ul>\n\t<li>For example, the beauty of <code>&quot;abaacc&quot;</code> is <code>3 - 1 = 2</code>.</li>\n</ul>\n\n<p>Given a string <code>s</code>, return <em>the sum of <strong>beauty</strong> of all of its substrings.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aabcb&quot;\n<strong>Output:</strong> 5\n<strong>Explanation: </strong>The substrings with non-zero beauty are [&quot;aab&quot;,&quot;aabc&quot;,&quot;aabcb&quot;,&quot;abcb&quot;,&quot;bcb&quot;], each with beauty equal to 1.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aabcbaa&quot;\n<strong>Output:</strong> 17\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;=<sup> </sup>500</code></li>\n\t<li><code>s</code> consists of only lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "所有子字符串美丽值之和",
            "translatedContent": "<p>一个字符串的 <strong>美丽值</strong> 定义为：出现频率最高字符与出现频率最低字符的出现次数之差。</p>\n\n<ul>\n\t<li>比方说，<code>\"abaacc\"</code> 的美丽值为 <code>3 - 1 = 2</code> 。</li>\n</ul>\n\n<p>给你一个字符串 <code>s</code> ，请你返回它所有子字符串的 <strong>美丽值</strong> 之和。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"aabcb\"\n<b>输出：</b>5\n<strong>解释：</strong>美丽值不为零的字符串包括 [\"aab\",\"aabc\",\"aabcb\",\"abcb\",\"bcb\"] ，每一个字符串的美丽值都为 1 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"aabcbaa\"\n<b>输出：</b>17\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <=<sup> </sup>500</code></li>\n\t<li><code>s</code> 只包含小写英文字母。</li>\n</ul>\n",
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                    "langSlug": "cpp",
                    "code": "class Solution {\npublic:\n    int beautySum(string s) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def beautySum(self, s):\n        \"\"\"\n        :type s: str\n        :rtype: int\n        \"\"\"",
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                    "code": "int beautySum(char* s) {\n    \n}",
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                    "code": "public class Solution {\n    public int BeautySum(string s) {\n\n    }\n}",
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                    "code": "/**\n * @param {string} s\n * @return {number}\n */\nvar beautySum = function(s) {\n\n};",
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                    "code": "function beautySum(s: string): number {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param String $s\n     * @return Integer\n     */\n    function beautySum($s) {\n\n    }\n}",
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                    "code": "class Solution {\n    func beautySum(_ s: String) -> Int {\n\n    }\n}",
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                    "code": "func beautySum(s string) int {\n\n}",
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                    "code": "# @param {String} s\n# @return {Integer}\ndef beauty_sum(s)\n\nend",
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                    "lang": "Erlang",
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                    "code": "-spec beauty_sum(S :: unicode:unicode_binary()) -> integer().\nbeauty_sum(S) ->\n  .",
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            "hints": [
                "Maintain a prefix sum for the frequencies of characters.",
                "You can iterate over all substring then iterate over the alphabet and find which character appears most and which appears least using the prefix sum array"
            ],
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            "status": null,
            "sampleTestCase": "\"aabcb\"",
            "metaData": "{\n  \"name\": \"beautySum\",\n  \"params\": [\n    {\n      \"name\": \"s\",\n      \"type\": \"string\"\n    }\n  ],\n  \"return\": {\n    \"type\": \"integer\"\n  }\n}",
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