leetcode-problemset/leetcode-cn/originData/subsequence-with-the-minimum-score.json

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            "title": "Subsequence With the Minimum Score",
            "titleSlug": "subsequence-with-the-minimum-score",
            "content": "<p>You are given two strings <code>s</code> and <code>t</code>.</p>\n\n<p>You are allowed to remove any number of characters from the string <code>t</code>.</p>\n\n<p>The score of the string is <code>0</code> if no characters are removed from the string <code>t</code>, otherwise:</p>\n\n<ul>\n\t<li>Let <code>left</code> be the minimum index among all removed characters.</li>\n\t<li>Let <code>right</code> be the maximum index among all removed characters.</li>\n</ul>\n\n<p>Then the score of the string is <code>right - left + 1</code>.</p>\n\n<p>Return <em>the minimum possible score to make </em><code>t</code><em>&nbsp;a subsequence of </em><code>s</code><em>.</em></p>\n\n<p>A <strong>subsequence</strong> of a string is a new string that is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (i.e., <code>&quot;ace&quot;</code> is a subsequence of <code>&quot;<u>a</u>b<u>c</u>d<u>e</u>&quot;</code> while <code>&quot;aec&quot;</code> is not).</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abacaba&quot;, t = &quot;bzaa&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> In this example, we remove the character &quot;z&quot; at index 1 (0-indexed).\nThe string t becomes &quot;baa&quot; which is a subsequence of the string &quot;abacaba&quot; and the score is 1 - 1 + 1 = 1.\nIt can be proven that 1 is the minimum score that we can achieve.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;cde&quot;, t = &quot;xyz&quot;\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> In this example, we remove characters &quot;x&quot;, &quot;y&quot; and &quot;z&quot; at indices 0, 1, and 2 (0-indexed).\nThe string t becomes &quot;&quot; which is a subsequence of the string &quot;cde&quot; and the score is 2 - 0 + 1 = 3.\nIt can be proven that 3 is the minimum score that we can achieve.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist of only lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "最少得分子序列",
            "translatedContent": "<p>给你两个字符串&nbsp;<code>s</code> 和&nbsp;<code>t</code>&nbsp;。</p>\n\n<p>你可以从字符串 <code>t</code>&nbsp;中删除任意数目的字符。</p>\n\n<p>如果没有从字符串&nbsp;<code>t</code>&nbsp;中删除字符，那么得分为&nbsp;<code>0</code>&nbsp;，否则：</p>\n\n<ul>\n\t<li>令&nbsp;<code>left</code>&nbsp;为删除字符中的最小下标。</li>\n\t<li>令&nbsp;<code>right</code>&nbsp;为删除字符中的最大下标。</li>\n</ul>\n\n<p>字符串的得分为&nbsp;<code>right - left + 1</code>&nbsp;。</p>\n\n<p>请你返回使<em>&nbsp;</em><code>t</code><em> </em>成为<em>&nbsp;</em><code>s</code>&nbsp;子序列的最小得分。</p>\n\n<p>一个字符串的 <strong>子序列</strong>&nbsp;是从原字符串中删除一些字符后（也可以一个也不删除），剩余字符不改变顺序得到的字符串。（比方说&nbsp;<code>\"ace\"</code> 是&nbsp;<code>\"<strong><em>a</em></strong>b<strong><em>c</em></strong>d<strong><em>e</em></strong>\"</code>&nbsp;的子序列，但是&nbsp;<code>\"aec\"</code>&nbsp;不是）。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"abacaba\", t = \"bzaa\"\n<b>输出：</b>1\n<b>解释：</b>这个例子中，我们删除下标 1 处的字符 \"z\" （下标从 0 开始）。\n字符串 t 变为 \"baa\" ，它是字符串 \"abacaba\" 的子序列，得分为 1 - 1 + 1 = 1 。\n1 是能得到的最小得分。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"cde\", t = \"xyz\"\n<b>输出：</b>3\n<b>解释：</b>这个例子中，我们将下标为 0， 1 和 2 处的字符 \"x\" ，\"y\" 和 \"z\" 删除（下标从 0 开始）。\n字符串变成 \"\" ，它是字符串 \"cde\" 的子序列，得分为 2 - 0 + 1 = 3 。\n3 是能得到的最小得分。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 和&nbsp;<code>t</code>&nbsp;都只包含小写英文字母。</li>\n</ul>\n\n<p>&nbsp;</p>\n",
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                "Maintain two pointers: i and j. We need to perform a similar operation: while t[0:i] + t[j:n] is not a subsequence of the string s, increase j.",
                "We can check the condition greedily. Create the array leftmost[i] which denotes minimum index k, such that in prefix s[0:k] exists subsequence t[0:i]. Similarly, we define rightmost[i].",
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