leetcode-problemset/leetcode-cn/originData/string-compression-iii.json

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        "question": {
            "questionId": "3451",
            "questionFrontendId": "3163",
            "categoryTitle": "Algorithms",
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            "title": "String Compression III",
            "titleSlug": "string-compression-iii",
            "content": "<p>Given a string <code>word</code>, compress it using the following algorithm:</p>\n\n<ul>\n\t<li>Begin with an empty string <code>comp</code>. While <code>word</code> is <strong>not</strong> empty, use the following operation:\n\n\t<ul>\n\t\t<li>Remove a maximum length prefix of <code>word</code> made of a <em>single character</em> <code>c</code> repeating <strong>at most</strong> 9 times.</li>\n\t\t<li>Append the length of the prefix followed by <code>c</code> to <code>comp</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>Return the string <code>comp</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">word = &quot;abcde&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">&quot;1a1b1c1d1e&quot;</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Initially, <code>comp = &quot;&quot;</code>. Apply the operation 5 times, choosing <code>&quot;a&quot;</code>, <code>&quot;b&quot;</code>, <code>&quot;c&quot;</code>, <code>&quot;d&quot;</code>, and <code>&quot;e&quot;</code> as the prefix in each operation.</p>\n\n<p>For each prefix, append <code>&quot;1&quot;</code> followed by the character to <code>comp</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">word = &quot;aaaaaaaaaaaaaabb&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">&quot;9a5a2b&quot;</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Initially, <code>comp = &quot;&quot;</code>. Apply the operation 3 times, choosing <code>&quot;aaaaaaaaa&quot;</code>, <code>&quot;aaaaa&quot;</code>, and <code>&quot;bb&quot;</code> as the prefix in each operation.</p>\n\n<ul>\n\t<li>For prefix <code>&quot;aaaaaaaaa&quot;</code>, append <code>&quot;9&quot;</code> followed by <code>&quot;a&quot;</code> to <code>comp</code>.</li>\n\t<li>For prefix <code>&quot;aaaaa&quot;</code>, append <code>&quot;5&quot;</code> followed by <code>&quot;a&quot;</code> to <code>comp</code>.</li>\n\t<li>For prefix <code>&quot;bb&quot;</code>, append <code>&quot;2&quot;</code> followed by <code>&quot;b&quot;</code> to <code>comp</code>.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>word</code> consists only of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "压缩字符串 III",
            "translatedContent": "<p>给你一个字符串 <code>word</code>，请你使用以下算法进行压缩：</p>\n\n<ul>\n\t<li>从空字符串 <code>comp</code> 开始。当 <code>word</code> <strong>不为空</strong> 时，执行以下操作：\n\n\t<ul>\n\t\t<li>移除 <code>word</code> 的最长单字符前缀，该前缀由单一字符 <code>c</code> 重复多次组成，且该前缀长度 <strong>最多 </strong>为 9 。</li>\n\t\t<li>将前缀的长度和字符 <code>c</code> 追加到 <code>comp</code> 。</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>返回字符串 <code>comp</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">word = \"abcde\"</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">\"1a1b1c1d1e\"</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>初始时，<code>comp = \"\"</code> 。进行 5 次操作，每次操作分别选择 <code>\"a\"</code>、<code>\"b\"</code>、<code>\"c\"</code>、<code>\"d\"</code> 和 <code>\"e\"</code> 作为前缀。</p>\n\n<p>对每个前缀，将 <code>\"1\"</code> 和对应的字符追加到 <code>comp</code>。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">word = \"aaaaaaaaaaaaaabb\"</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">\"9a5a2b\"</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>初始时，<code>comp = \"\"</code>。进行 3 次操作，每次操作分别选择 <code>\"aaaaaaaaa\"</code>、<code>\"aaaaa\"</code> 和 <code>\"bb\"</code> 作为前缀。</p>\n\n<ul>\n\t<li>对于前缀 <code>\"aaaaaaaaa\"</code>，将 <code>\"9\"</code> 和 <code>\"a\"</code> 追加到 <code>comp</code>。</li>\n\t<li>对于前缀 <code>\"aaaaa\"</code>，将 <code>\"5\"</code> 和 <code>\"a\"</code> 追加到 <code>comp</code>。</li>\n\t<li>对于前缀 <code>\"bb\"</code>，将 <code>\"2\"</code> 和 <code>\"b\"</code> 追加到 <code>comp</code>。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>word</code> 仅由小写英文字母组成。</li>\n</ul>\n",
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