leetcode-problemset/leetcode-cn/originData/squares-of-a-sorted-array.json

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            "categoryTitle": "Algorithms",
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            "title": "Squares of a Sorted Array",
            "titleSlug": "squares-of-a-sorted-array",
            "content": "<p>Given an integer array <code>nums</code> sorted in <strong>non-decreasing</strong> order, return <em>an array of <strong>the squares of each number</strong> sorted in non-decreasing order</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-4,-1,0,3,10]\n<strong>Output:</strong> [0,1,9,16,100]\n<strong>Explanation:</strong> After squaring, the array becomes [16,1,0,9,100].\nAfter sorting, it becomes [0,1,9,16,100].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-7,-3,2,3,11]\n<strong>Output:</strong> [4,9,9,49,121]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code><span>1 &lt;= nums.length &lt;= </span>10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>nums</code> is sorted in <strong>non-decreasing</strong> order.</li>\n</ul>\n\n<p>&nbsp;</p>\n<strong>Follow up:</strong> Squaring each element and sorting the new array is very trivial, could you find an <code>O(n)</code> solution using a different approach?",
            "translatedTitle": "有序数组的平方",
            "translatedContent": "<p>给你一个按 <strong>非递减顺序</strong> 排序的整数数组 <code>nums</code>，返回 <strong>每个数字的平方</strong> 组成的新数组，要求也按 <strong>非递减顺序</strong> 排序。</p>\n\n<ul>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [-4,-1,0,3,10]\n<strong>输出：</strong>[0,1,9,16,100]\n<strong>解释：</strong>平方后，数组变为 [16,1,0,9,100]\n排序后，数组变为 [0,1,9,16,100]</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [-7,-3,2,3,11]\n<strong>输出：</strong>[4,9,9,49,121]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code><span>1 <= nums.length <= </span>10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>\n\t<li><code>nums</code> 已按 <strong>非递减顺序</strong> 排序</li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong></p>\n\n<ul>\n\t<li>请你<span style=\"color: rgb(36, 41, 46); font-family: -apple-system, BlinkMacSystemFont, &quot;Segoe UI&quot;, Helvetica, Arial, sans-serif, &quot;Apple Color Emoji&quot;, &quot;Segoe UI Emoji&quot;; font-size: 14px; font-style: normal; font-variant-ligatures: normal; font-variant-caps: normal; font-weight: 400; letter-spacing: normal; orphans: 2; text-align: start; text-indent: 0px; text-transform: none; white-space: normal; widows: 2; word-spacing: 0px; -webkit-text-stroke-width: 0px; background-color: rgb(255, 255, 255); text-decoration-style: initial; text-decoration-color: initial; display: inline !important; float: none;\">设计时间复杂度为 <code>O(n)</code> 的算法解决本问题</span></li>\n</ul>\n",
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