leetcode-problemset/leetcode-cn/originData/smallest-missing-non-negative-integer-after-operations.json

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            "title": "Smallest Missing Non-negative Integer After Operations",
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            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>value</code>.</p>\n\n<p>In one operation, you can add or subtract <code>value</code> from any element of <code>nums</code>.</p>\n\n<ul>\n\t<li>For example, if <code>nums = [1,2,3]</code> and <code>value = 2</code>, you can choose to subtract <code>value</code> from <code>nums[0]</code> to make <code>nums = [-1,2,3]</code>.</li>\n</ul>\n\n<p>The MEX (minimum excluded) of an array is the smallest missing <strong>non-negative</strong> integer in it.</p>\n\n<ul>\n\t<li>For example, the MEX of <code>[-1,2,3]</code> is <code>0</code> while the MEX of <code>[1,0,3]</code> is <code>2</code>.</li>\n</ul>\n\n<p>Return <em>the maximum MEX of </em><code>nums</code><em> after applying the mentioned operation <strong>any number of times</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,-10,7,13,6,8], value = 5\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> One can achieve this result by applying the following operations:\n- Add value to nums[1] twice to make nums = [1,<strong><u>0</u></strong>,7,13,6,8]\n- Subtract value from nums[2] once to make nums = [1,0,<strong><u>2</u></strong>,13,6,8]\n- Subtract value from nums[3] twice to make nums = [1,0,2,<strong><u>3</u></strong>,6,8]\nThe MEX of nums is 4. It can be shown that 4 is the maximum MEX we can achieve.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,-10,7,13,6,8], value = 7\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> One can achieve this result by applying the following operation:\n- subtract value from nums[2] once to make nums = [1,-10,<u><strong>0</strong></u>,13,6,8]\nThe MEX of nums is 2. It can be shown that 2 is the maximum MEX we can achieve.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, value &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "执行操作后的最大 MEX",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> 和一个整数 <code>value</code> 。</p>\n\n<p>在一步操作中，你可以对 <code>nums</code> 中的任一元素加上或减去 <code>value</code> 。</p>\n\n<ul>\n\t<li>例如，如果 <code>nums = [1,2,3]</code> 且 <code>value = 2</code> ，你可以选择 <code>nums[0]</code> 减去 <code>value</code> ，得到 <code>nums = [-1,2,3]</code> 。</li>\n</ul>\n\n<p>数组的 MEX (minimum excluded) 是指其中数组中缺失的最小非负整数。</p>\n\n<ul>\n\t<li>例如，<code>[-1,2,3]</code> 的 MEX 是 <code>0</code> ，而 <code>[1,0,3]</code> 的 MEX 是 <code>2</code> 。</li>\n</ul>\n\n<p>返回在执行上述操作 <strong>任意次</strong> 后，<code>nums</code><em> </em>的最大 MEX <em>。</em></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,-10,7,13,6,8], value = 5\n<strong>输出：</strong>4\n<strong>解释：</strong>执行下述操作可以得到这一结果：\n- nums[1] 加上 value 两次，nums = [1,<em><strong>0</strong></em>,7,13,6,8]\n- nums[2] 减去 value 一次，nums = [1,0,<em><strong>2</strong></em>,13,6,8]\n- nums[3] 减去 value 两次，nums = [1,0,2,<em><strong>3</strong></em>,6,8]\nnums 的 MEX 是 4 。可以证明 4 是可以取到的最大 MEX 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,-10,7,13,6,8], value = 7\n<strong>输出：</strong>2\n<strong>解释：</strong>执行下述操作可以得到这一结果：\n- nums[2] 减去 value 一次，nums = [1,-10,<em><strong>0</strong></em>,13,6,8]\nnums 的 MEX 是 2 。可以证明 2 是可以取到的最大 MEX 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, value &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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