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"questionId": "918",
"questionFrontendId": "882",
"categoryTitle": "Algorithms",
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"title": "Reachable Nodes In Subdivided Graph",
"titleSlug": "reachable-nodes-in-subdivided-graph",
"content": "<p>You are given an undirected graph (the <strong>&quot;original graph&quot;</strong>) with <code>n</code> nodes labeled from <code>0</code> to <code>n - 1</code>. You decide to <strong>subdivide</strong> each edge in the graph into a chain of nodes, with the number of new nodes varying between each edge.</p>\n\n<p>The graph is given as a 2D array of <code>edges</code> where <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>, cnt<sub>i</sub>]</code> indicates that there is an edge between nodes <code>u<sub>i</sub></code> and <code>v<sub>i</sub></code> in the original graph, and <code>cnt<sub>i</sub></code> is the total number of new nodes that you will <strong>subdivide</strong> the edge into. Note that <code>cnt<sub>i</sub> == 0</code> means you will not subdivide the edge.</p>\n\n<p>To <strong>subdivide</strong> the edge <code>[u<sub>i</sub>, v<sub>i</sub>]</code>, replace it with <code>(cnt<sub>i</sub> + 1)</code> new edges and <code>cnt<sub>i</sub></code> new nodes. The new nodes are <code>x<sub>1</sub></code>, <code>x<sub>2</sub></code>, ..., <code>x<sub>cnt<sub>i</sub></sub></code>, and the new edges are <code>[u<sub>i</sub>, x<sub>1</sub>]</code>, <code>[x<sub>1</sub>, x<sub>2</sub>]</code>, <code>[x<sub>2</sub>, x<sub>3</sub>]</code>, ..., <code>[x<sub>cnt<sub>i</sub>-1</sub>, x<sub>cnt<sub>i</sub></sub>]</code>, <code>[x<sub>cnt<sub>i</sub></sub>, v<sub>i</sub>]</code>.</p>\n\n<p>In this <strong>new graph</strong>, you want to know how many nodes are <strong>reachable</strong> from the node <code>0</code>, where a node is <strong>reachable</strong> if the distance is <code>maxMoves</code> or less.</p>\n\n<p>Given the original graph and <code>maxMoves</code>, return <em>the number of nodes that are <strong>reachable</strong> from node </em><code>0</code><em> in the new graph</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/01/origfinal.png\" style=\"width: 600px; height: 247px;\" />\n<pre>\n<strong>Input:</strong> edges = [[0,1,10],[0,2,1],[1,2,2]], maxMoves = 6, n = 3\n<strong>Output:</strong> 13\n<strong>Explanation:</strong> The edge subdivisions are shown in the image above.\nThe nodes that are reachable are highlighted in yellow.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> edges = [[0,1,4],[1,2,6],[0,2,8],[1,3,1]], maxMoves = 10, n = 4\n<strong>Output:</strong> 23\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> edges = [[1,2,4],[1,4,5],[1,3,1],[2,3,4],[3,4,5]], maxMoves = 17, n = 5\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> Node 0 is disconnected from the rest of the graph, so only node 0 is reachable.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= edges.length &lt;= min(n * (n - 1) / 2, 10<sup>4</sup>)</code></li>\n\t<li><code>edges[i].length == 3</code></li>\n\t<li><code>0 &lt;= u<sub>i</sub> &lt; v<sub>i</sub> &lt; n</code></li>\n\t<li>There are <strong>no multiple edges</strong> in the graph.</li>\n\t<li><code>0 &lt;= cnt<sub>i</sub> &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= maxMoves &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= n &lt;= 3000</code></li>\n</ul>\n",
"translatedTitle": "细分图中的可到达节点",
"translatedContent": "<p>给你一个无向图(<strong>原始图</strong>),图中有 <code>n</code> 个节点,编号从 <code>0</code> 到 <code>n - 1</code> 。你决定将图中的每条边 <strong>细分</strong> 为一条节点链,每条边之间的新节点数各不相同。</p>\n\n<p>图用由边组成的二维数组 <code>edges</code> 表示,其中&nbsp;<code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>, cnt<sub>i</sub>]</code> 表示原始图中节点&nbsp;<code>u<sub>i</sub></code> 和&nbsp;<code>v<sub>i</sub></code> 之间存在一条边,<code>cnt<sub>i</sub></code> 是将边 <strong>细分</strong> 后的新节点总数。注意,<code>cnt<sub>i</sub> == 0</code> 表示边不可细分。</p>\n\n<p>要 <strong>细分</strong> 边 <code>[ui, vi]</code> ,需要将其替换为 <code>(cnt<sub>i</sub> + 1)</code> 条新边,和&nbsp;<code>cnt<sub>i</sub></code> 个新节点。新节点为 <code>x<sub>1</sub></code>, <code>x<sub>2</sub></code>, ..., <code>x<sub>cnt<sub>i</sub></sub></code> ,新边为 <code>[u<sub>i</sub>, x<sub>1</sub>]</code>, <code>[x<sub>1</sub>, x<sub>2</sub>]</code>, <code>[x<sub>2</sub>, x<sub>3</sub>]</code>, ..., <code>[x<sub>cnt<sub>i</sub>-1</sub>, x<sub>cnt<sub>i</sub></sub>]</code>, <code>[x<sub>cnt<sub>i</sub></sub>, v<sub>i</sub>]</code> 。</p>\n\n<p>现在得到一个&nbsp;<strong>新的细分图</strong> ,请你计算从节点 <code>0</code> 出发,可以到达多少个节点?如果节点间距离是 <code>maxMoves</code> 或更少,则视为 <strong>可以到达</strong> 。</p>\n\n<p>给你原始图和 <code>maxMoves</code> ,返回 <em>新的细分图中从节点 <code>0</code> 出发</em><strong><em> 可到达的节点数</em></strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/01/origfinal.png\" style=\"height: 247px; width: 600px;\" />\n<pre>\n<strong>输入:</strong>edges = [[0,1,10],[0,2,1],[1,2,2]], maxMoves = 6, n = 3\n<strong>输出:</strong>13\n<strong>解释:</strong>边的细分情况如上图所示。\n可以到达的节点已经用黄色标注出来。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>edges = [[0,1,4],[1,2,6],[0,2,8],[1,3,1]], maxMoves = 10, n = 4\n<strong>输出:</strong>23\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>edges = [[1,2,4],[1,4,5],[1,3,1],[2,3,4],[3,4,5]], maxMoves = 17, n = 5\n<strong>输出:</strong>1\n<strong>解释:</strong>节点 0 与图的其余部分没有连通,所以只有节点 0 可以到达。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= edges.length &lt;= min(n * (n - 1) / 2, 10<sup>4</sup>)</code></li>\n\t<li><code>edges[i].length == 3</code></li>\n\t<li><code>0 &lt;= u<sub>i</sub> &lt; v<sub>i</sub> &lt; n</code></li>\n\t<li>图中 <strong>不存在平行边</strong></li>\n\t<li><code>0 &lt;= cnt<sub>i</sub> &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= maxMoves &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= n &lt;= 3000</code></li>\n</ul>\n",
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