mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
155 lines
32 KiB
JSON
155 lines
32 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "284",
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"questionFrontendId": "284",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1880,
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"title": "Peeking Iterator",
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"titleSlug": "peeking-iterator",
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"content": "<p>Design an iterator that supports the <code>peek</code> operation on an existing iterator in addition to the <code>hasNext</code> and the <code>next</code> operations.</p>\n\n<p>Implement the <code>PeekingIterator</code> class:</p>\n\n<ul>\n\t<li><code>PeekingIterator(Iterator<int> nums)</code> Initializes the object with the given integer iterator <code>iterator</code>.</li>\n\t<li><code>int next()</code> Returns the next element in the array and moves the pointer to the next element.</li>\n\t<li><code>boolean hasNext()</code> Returns <code>true</code> if there are still elements in the array.</li>\n\t<li><code>int peek()</code> Returns the next element in the array <strong>without</strong> moving the pointer.</li>\n</ul>\n\n<p><strong>Note:</strong> Each language may have a different implementation of the constructor and <code>Iterator</code>, but they all support the <code>int next()</code> and <code>boolean hasNext()</code> functions.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input</strong>\n["PeekingIterator", "next", "peek", "next", "next", "hasNext"]\n[[[1, 2, 3]], [], [], [], [], []]\n<strong>Output</strong>\n[null, 1, 2, 2, 3, false]\n\n<strong>Explanation</strong>\nPeekingIterator peekingIterator = new PeekingIterator([1, 2, 3]); // [<u><strong>1</strong></u>,2,3]\npeekingIterator.next(); // return 1, the pointer moves to the next element [1,<u><strong>2</strong></u>,3].\npeekingIterator.peek(); // return 2, the pointer does not move [1,<u><strong>2</strong></u>,3].\npeekingIterator.next(); // return 2, the pointer moves to the next element [1,2,<u><strong>3</strong></u>]\npeekingIterator.next(); // return 3, the pointer moves to the next element [1,2,3]\npeekingIterator.hasNext(); // return False\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 1000</code></li>\n\t<li><code>1 <= nums[i] <= 1000</code></li>\n\t<li>All the calls to <code>next</code> and <code>peek</code> are valid.</li>\n\t<li>At most <code>1000</code> calls will be made to <code>next</code>, <code>hasNext</code>, and <code>peek</code>.</li>\n</ul>\n\n<p> </p>\n<strong>Follow up:</strong> How would you extend your design to be generic and work with all types, not just integer?",
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"translatedTitle": "窥视迭代器",
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"translatedContent": "<p>请你在设计一个迭代器,在集成现有迭代器拥有的 <code>hasNext</code> 和 <code>next</code> 操作的基础上,还额外支持 <code>peek</code> 操作。</p>\n\n<p>实现 <code>PeekingIterator</code> 类:</p>\n\n<ul>\n\t<li><code>PeekingIterator(Iterator<int> nums)</code> 使用指定整数迭代器 <code>nums</code> 初始化迭代器。</li>\n\t<li><code>int next()</code> 返回数组中的下一个元素,并将指针移动到下个元素处。</li>\n\t<li><code>bool hasNext()</code> 如果数组中存在下一个元素,返回 <code>true</code> ;否则,返回 <code>false</code> 。</li>\n\t<li><code>int peek()</code> 返回数组中的下一个元素,但 <strong>不</strong> 移动指针。</li>\n</ul>\n\n<p><strong>注意:</strong>每种语言可能有不同的构造函数和迭代器 <code>Iterator</code>,但均支持 <code>int next()</code> 和 <code>boolean hasNext()</code> 函数。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>\n[\"PeekingIterator\", \"next\", \"peek\", \"next\", \"next\", \"hasNext\"]\n[[[1, 2, 3]], [], [], [], [], []]\n<strong>输出:</strong>\n[null, 1, 2, 2, 3, false]\n\n<strong>解释:</strong>\nPeekingIterator peekingIterator = new PeekingIterator([1, 2, 3]); // [<u><strong>1</strong></u>,2,3]\npeekingIterator.next(); // 返回 1 ,指针移动到下一个元素 [1,<u><strong>2</strong></u>,3]\npeekingIterator.peek(); // 返回 2 ,指针未发生移动 [1,<u><strong>2</strong></u>,3]\npeekingIterator.next(); // 返回 2 ,指针移动到下一个元素 [1,2,<u><strong>3</strong></u>]\npeekingIterator.next(); // 返回 3 ,指针移动到下一个元素 [1,2,3]\npeekingIterator.hasNext(); // 返回 False\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 1000</code></li>\n\t<li><code>1 <= nums[i] <= 1000</code></li>\n\t<li>对 <code>next</code> 和 <code>peek</code> 的调用均有效</li>\n\t<li><code>next</code>、<code>hasNext</code> 和 <code>peek </code>最多调用 <code>1000</code> 次</li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶:</strong>你将如何拓展你的设计?使之变得通用化,从而适应所有的类型,而不只是整数型?</p>\n",
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"code": "/*\n * Below is the interface for Iterator, which is already defined for you.\n * **DO NOT** modify the interface for Iterator.\n *\n * class Iterator {\n *\t\tstruct Data;\n * \t\tData* data;\n * public:\n *\t\tIterator(const vector<int>& nums);\n * \t\tIterator(const Iterator& iter);\n *\n * \t\t// Returns the next element in the iteration.\n *\t\tint next();\n *\n *\t\t// Returns true if the iteration has more elements.\n *\t\tbool hasNext() const;\n *\t};\n */\n\nclass PeekingIterator : public Iterator {\npublic:\n\tPeekingIterator(const vector<int>& nums) : Iterator(nums) {\n\t // Initialize any member here.\n\t // **DO NOT** save a copy of nums and manipulate it directly.\n\t // You should only use the Iterator interface methods.\n\t \n\t}\n\t\n // Returns the next element in the iteration without advancing the iterator.\n\tint peek() {\n \n\t}\n\t\n\t// hasNext() and next() should behave the same as in the Iterator interface.\n\t// Override them if needed.\n\tint next() {\n\t \n\t}\n\t\n\tbool hasNext() const {\n\t \n\t}\n};",
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"code": "// Java Iterator interface reference:\n// https://docs.oracle.com/javase/8/docs/api/java/util/Iterator.html\n\nclass PeekingIterator implements Iterator<Integer> {\n\tpublic PeekingIterator(Iterator<Integer> iterator) {\n\t // initialize any member here.\n\t \n\t}\n\t\n // Returns the next element in the iteration without advancing the iterator.\n\tpublic Integer peek() {\n \n\t}\n\t\n\t// hasNext() and next() should behave the same as in the Iterator interface.\n\t// Override them if needed.\n\t@Override\n\tpublic Integer next() {\n\t \n\t}\n\t\n\t@Override\n\tpublic boolean hasNext() {\n\t \n\t}\n}",
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"code": "# Below is the interface for Iterator, which is already defined for you.\n#\n# class Iterator(object):\n# def __init__(self, nums):\n# \"\"\"\n# Initializes an iterator object to the beginning of a list.\n# :type nums: List[int]\n# \"\"\"\n#\n# def hasNext(self):\n# \"\"\"\n# Returns true if the iteration has more elements.\n# :rtype: bool\n# \"\"\"\n#\n# def next(self):\n# \"\"\"\n# Returns the next element in the iteration.\n# :rtype: int\n# \"\"\"\n\nclass PeekingIterator(object):\n def __init__(self, iterator):\n \"\"\"\n Initialize your data structure here.\n :type iterator: Iterator\n \"\"\"\n \n\n def peek(self):\n \"\"\"\n Returns the next element in the iteration without advancing the iterator.\n :rtype: int\n \"\"\"\n \n\n def next(self):\n \"\"\"\n :rtype: int\n \"\"\"\n \n\n def hasNext(self):\n \"\"\"\n :rtype: bool\n \"\"\"\n \n\n# Your PeekingIterator object will be instantiated and called as such:\n# iter = PeekingIterator(Iterator(nums))\n# while iter.hasNext():\n# val = iter.peek() # Get the next element but not advance the iterator.\n# iter.next() # Should return the same value as [val].",
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"code": "# Below is the interface for Iterator, which is already defined for you.\n#\n# class Iterator:\n# def __init__(self, nums):\n# \"\"\"\n# Initializes an iterator object to the beginning of a list.\n# :type nums: List[int]\n# \"\"\"\n#\n# def hasNext(self):\n# \"\"\"\n# Returns true if the iteration has more elements.\n# :rtype: bool\n# \"\"\"\n#\n# def next(self):\n# \"\"\"\n# Returns the next element in the iteration.\n# :rtype: int\n# \"\"\"\n\nclass PeekingIterator:\n def __init__(self, iterator):\n \"\"\"\n Initialize your data structure here.\n :type iterator: Iterator\n \"\"\"\n \n\n def peek(self):\n \"\"\"\n Returns the next element in the iteration without advancing the iterator.\n :rtype: int\n \"\"\"\n \n\n def next(self):\n \"\"\"\n :rtype: int\n \"\"\"\n \n\n def hasNext(self):\n \"\"\"\n :rtype: bool\n \"\"\"\n \n\n# Your PeekingIterator object will be instantiated and called as such:\n# iter = PeekingIterator(Iterator(nums))\n# while iter.hasNext():\n# val = iter.peek() # Get the next element but not advance the iterator.\n# iter.next() # Should return the same value as [val].",
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"code": "/*\n *\tstruct Iterator {\n *\t\t// Returns true if the iteration has more elements.\n *\t\tbool (*hasNext)();\n *\n * \t\t// Returns the next element in the iteration.\n *\t\tint (*next)();\n *\t};\n */\n\nstruct PeekingIterator {\n \n};\n\nstruct PeekingIterator* Constructor(struct Iterator* iter) {\n struct PeekingIterator* piter = malloc(sizeof(struct PeekingIterator));\n piter->iterator = iter;\n piter->hasPeeked = false;\n return piter;\n}\n\nint peek(struct PeekingIterator* obj) {\n \n}\n\nint next(struct PeekingIterator* obj) {\n \n}\n\nbool hasNext(struct PeekingIterator* obj) {\n \n}\n\n/**\n * Your PeekingIterator struct will be instantiated and called as such:\n * PeekingIterator* obj = peekingIteratorCreate(arr, arrSize);\n * int param_1 = peek(obj);\n * int param_2 = next(obj);\n * bool param_3 = hasNext(obj);\n * peekingIteratorFree(obj);\n*/",
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"code": "// C# IEnumerator interface reference:\n// https://docs.microsoft.com/en-us/dotnet/api/system.collections.ienumerator?view=netframework-4.8\n\nclass PeekingIterator {\n // iterators refers to the first element of the array.\n public PeekingIterator(IEnumerator<int> iterator) {\n // initialize any member here.\n }\n \n // Returns the next element in the iteration without advancing the iterator.\n public int Peek() {\n \n }\n \n // Returns the next element in the iteration and advances the iterator.\n public int Next() {\n \n }\n \n // Returns false if the iterator is refering to the end of the array of true otherwise.\n public bool HasNext() {\n\t\t\n }\n}",
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"code": "/**\n * // This is the Iterator's API interface.\n * // You should not implement it, or speculate about its implementation.\n * function Iterator() {\n * @ return {number}\n * this.next = function() { // return the next number of the iterator\n * ...\n * }; \n *\n * @return {boolean}\n * this.hasNext = function() { // return true if it still has numbers\n * ...\n * };\n * };\n */\n\n/**\n * @param {Iterator} iterator\n */\nvar PeekingIterator = function(iterator) {\n \n};\n\n/**\n * @return {number}\n */\nPeekingIterator.prototype.peek = function() {\n \n};\n\n/**\n * @return {number}\n */\nPeekingIterator.prototype.next = function() {\n \n};\n\n/**\n * @return {boolean}\n */\nPeekingIterator.prototype.hasNext = function() {\n \n};\n\n/** \n * Your PeekingIterator object will be instantiated and called as such:\n * var obj = new PeekingIterator(arr)\n * var param_1 = obj.peek()\n * var param_2 = obj.next()\n * var param_3 = obj.hasNext()\n */",
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"code": "/**\n * // This is the Iterator's API interface.\n * // You should not implement it, or speculate about its implementation\n * class Iterator {\n * hasNext(): boolean {}\n *\n * next(): number {}\n * }\n */\n\nclass PeekingIterator {\n constructor(iterator: Iterator) {\n\n }\n\n peek(): number {\n\n }\n\n next(): number {\n\n }\n\n hasNext(): boolean {\n\n }\n}\n\n/**\n * Your PeekingIterator object will be instantiated and called as such:\n * var obj = new PeekingIterator(iterator)\n * var param_1 = obj.peek()\n * var param_2 = obj.next()\n * var param_3 = obj.hasNext()\n */",
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"code": "// PHP ArrayIterator reference:\n// https://www.php.net/arrayiterator\n\nclass PeekingIterator {\n /**\n * @param ArrayIterator $arr\n */\n function __construct($arr) {\n \n }\n \n /**\n * @return Integer\n */\n function next() {\n \n }\n \n /**\n * @return Integer\n */\n function peek() {\n \n }\n \n /**\n * @return Boolean\n */\n function hasNext() {\n \n }\n}\n\n/**\n * Your PeekingIterator object will be instantiated and called as such:\n * $obj = PeekingIterator($arr);\n * $ret_1 = $obj->next();\n * $ret_2 = $obj->peek();\n * $ret_3 = $obj->hasNext();\n */",
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"code": "// Swift IndexingIterator refernence:\n// https://developer.apple.com/documentation/swift/indexingiterator\n\nclass PeekingIterator {\n init(_ arr: IndexingIterator<Array<Int>>) {\n \n }\n \n func next() -> Int {\n \n }\n \n func peek() -> Int {\n \n }\n \n func hasNext() -> Bool {\n \n }\n}\n\n/**\n * Your PeekingIterator object will be instantiated and called as such:\n * let obj = PeekingIterator(arr)\n * let ret_1: Int = obj.next()\n * let ret_2: Int = obj.peek()\n * let ret_3: Bool = obj.hasNext()\n */",
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"code": "// Kotlin Iterator reference:\n// https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.collections/-iterator/\n\nclass PeekingIterator(iterator:Iterator<Int>):Iterator<Int> {\n fun peek(): Int {\n \t\n }\n \n override fun next(): Int {\n \n }\n \n override fun hasNext(): Boolean {\n \n }\n}\n\n/**\n * Your PeekingIterator object will be instantiated and called as such:\n * var obj = PeekingIterator(arr)\n * var param_1 = obj.next()\n * var param_2 = obj.peek()\n * var param_3 = obj.hasNext()\n */",
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"code": "// Scala Iterator reference:\n// https://www.scala-lang.org/api/2.12.2/scala/collection/Iterator.html\n\nclass PeekingIterator(_iterator: Iterator[Int]) {\n def peek(): Int = {\n \n }\n \n def next(): Int = {\n \n }\n \n def hasNext(): Boolean = {\n \n }\n}\n\n/**\n * Your PeekingIterator object will be instantiated and called as such:\n * var obj = new PeekingIterator(arr)\n * var param_1 = obj.next()\n * var param_2 = obj.peek()\n * var param_3 = obj.hasNext()\n */",
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||
"Think of \"looking ahead\". You want to cache the next element.",
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"Is one variable sufficient? Why or why not?",
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"Test your design with call order of <code>peek()</code> before <code>next()</code> vs <code>next()</code> before <code>peek()</code>.",
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"For a clean implementation, check out <a href=\"https://github.com/google/guava/blob/703ef758b8621cfbab16814f01ddcc5324bdea33/guava-gwt/src-super/com/google/common/collect/super/com/google/common/collect/Iterators.java#L1125\" target=\"_blank\">Google's guava library source code</a>."
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