mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
186 lines
25 KiB
JSON
186 lines
25 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "234",
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"questionFrontendId": "234",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1417,
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"title": "Palindrome Linked List",
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"titleSlug": "palindrome-linked-list",
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"content": "<p>Given the <code>head</code> of a singly linked list, return <code>true</code><em> if it is a </em><span data-keyword=\"palindrome-sequence\"><em>palindrome</em></span><em> or </em><code>false</code><em> otherwise</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/03/pal1linked-list.jpg\" style=\"width: 422px; height: 62px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2,2,1]\n<strong>Output:</strong> true\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/03/pal2linked-list.jpg\" style=\"width: 182px; height: 62px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2]\n<strong>Output:</strong> false\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the list is in the range <code>[1, 10<sup>5</sup>]</code>.</li>\n\t<li><code>0 <= Node.val <= 9</code></li>\n</ul>\n\n<p> </p>\n<strong>Follow up:</strong> Could you do it in <code>O(n)</code> time and <code>O(1)</code> space?",
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"translatedTitle": "回文链表",
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"translatedContent": "<p>给你一个单链表的头节点 <code>head</code> ，请你判断该链表是否为回文链表。如果是，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/03/pal1linked-list.jpg\" style=\"width: 422px; height: 62px;\" />\n<pre>\n<strong>输入：</strong>head = [1,2,2,1]\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/03/pal2linked-list.jpg\" style=\"width: 182px; height: 62px;\" />\n<pre>\n<strong>输入：</strong>head = [1,2]\n<strong>输出：</strong>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表中节点数目在范围<code>[1, 10<sup>5</sup>]</code> 内</li>\n\t<li><code>0 <= Node.val <= 9</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>你能否用 <code>O(n)</code> 时间复杂度和 <code>O(1)</code> 空间复杂度解决此题？</p>\n",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * ListNode *next;\n * ListNode() : val(0), next(nullptr) {}\n * ListNode(int x) : val(x), next(nullptr) {}\n * ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n bool isPalindrome(ListNode* head) {\n\n }\n};",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * int val;\n * ListNode next;\n * ListNode() {}\n * ListNode(int val) { this.val = val; }\n * ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n public boolean isPalindrome(ListNode head) {\n\n }\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution(object):\n def isPalindrome(self, head):\n \"\"\"\n :type head: ListNode\n :rtype: bool\n \"\"\"\n ",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n def isPalindrome(self, head: Optional[ListNode]) -> bool:",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public int val;\n * public ListNode next;\n * public ListNode(int val=0, ListNode next=null) {\n * this.val = val;\n * this.next = next;\n * }\n * }\n */\npublic class Solution {\n public bool IsPalindrome(ListNode head) {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {boolean}\n */\nvar isPalindrome = function(head) {\n\n};",
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"code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n * public $val = 0;\n * public $next = null;\n * function __construct($val = 0, $next = null) {\n * $this->val = $val;\n * $this->next = $next;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param ListNode $head\n * @return Boolean\n */\n function isPalindrome($head) {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public var val: Int\n * public var next: ListNode?\n * public init() { self.val = 0; self.next = nil; }\n * public init(_ val: Int) { self.val = val; self.next = nil; }\n * public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n func isPalindrome(_ head: ListNode?) -> Bool {\n\n }\n}",
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"code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n * var next: ListNode? = null\n * }\n */\nclass Solution {\n fun isPalindrome(head: ListNode?): Boolean {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n * int val;\n * ListNode? next;\n * ListNode([this.val = 0, this.next]);\n * }\n */\nclass Solution {\n bool isPalindrome(ListNode? head) {\n \n }\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode\n# attr_accessor :val, :next\n# def initialize(val = 0, _next = nil)\n# @val = val\n# @next = _next\n# end\n# end\n# @param {ListNode} head\n# @return {Boolean}\ndef is_palindrome(head)\n\nend",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n * var next: ListNode = _next\n * var x: Int = _x\n * }\n */\nobject Solution {\n def isPalindrome(head: ListNode): Boolean = {\n\n }\n}",
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