leetcode-problemset/leetcode-cn/originData/painting-the-walls.json

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        "question": {
            "questionId": "2808",
            "questionFrontendId": "2742",
            "categoryTitle": "Algorithms",
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            "title": "Painting the Walls",
            "titleSlug": "painting-the-walls",
            "content": "<p>You are given two <strong>0-indexed</strong> integer arrays,&nbsp;<code>cost</code> and <code>time</code>, of size <code>n</code> representing the costs and the time taken to paint <code>n</code> different walls respectively. There are two painters available:</p>\n\n<ul>\n\t<li>A<strong>&nbsp;paid painter</strong>&nbsp;that paints the <code>i<sup>th</sup></code> wall in <code>time[i]</code> units of time and takes <code>cost[i]</code> units of money.</li>\n\t<li>A<strong>&nbsp;free painter</strong> that paints&nbsp;<strong>any</strong> wall in <code>1</code> unit of time at a cost of <code>0</code>. But the&nbsp;free painter can only be used if the paid painter is already <strong>occupied</strong>.</li>\n</ul>\n\n<p>Return <em>the minimum amount of money required to paint the </em><code>n</code><em>&nbsp;walls.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> cost = [1,2,3,2], time = [1,2,3,2]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The walls at index 0 and 1 will be painted by the paid painter, and it will take 3 units of time; meanwhile, the free painter will paint the walls at index 2 and 3, free of cost in 2 units of time. Thus, the total cost is 1 + 2 = 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> cost = [2,3,4,2], time = [1,1,1,1]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The walls at index 0 and 3 will be painted by the paid painter, and it will take 2 units of time; meanwhile, the free painter will paint the walls at index 1 and 2, free of cost in 2 units of time. Thus, the total cost is 2 + 2 = 4.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= cost.length &lt;= 500</code></li>\n\t<li><code>cost.length == time.length</code></li>\n\t<li><code>1 &lt;= cost[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>1 &lt;= time[i] &lt;= 500</code></li>\n</ul>\n",
            "translatedTitle": "给墙壁刷油漆",
            "translatedContent": "<p>给你两个长度为 <code>n</code>&nbsp;下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>cost</code> 和&nbsp;<code>time</code>&nbsp;，分别表示给&nbsp;<code>n</code>&nbsp;堵不同的墙刷油漆需要的开销和时间。你有两名油漆匠：</p>\n\n<ul>\n\t<li>一位需要 <strong>付费</strong>&nbsp;的油漆匠，刷第&nbsp;<code>i</code>&nbsp;堵墙需要花费&nbsp;<code>time[i]</code>&nbsp;单位的时间，开销为&nbsp;<code>cost[i]</code>&nbsp;单位的钱。</li>\n\t<li>一位 <strong>免费</strong>&nbsp;的油漆匠，刷 <strong>任意</strong>&nbsp;一堵墙的时间为&nbsp;<code>1</code>&nbsp;单位，开销为&nbsp;<code>0</code>&nbsp;。但是必须在付费油漆匠&nbsp;<strong>工作</strong>&nbsp;时，免费油漆匠才会工作。</li>\n</ul>\n\n<p>请你返回刷完 <code>n</code>&nbsp;堵墙最少开销为多少。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>cost = [1,2,3,2], time = [1,2,3,2]\n<b>输出：</b>3\n<strong>解释：</strong>下标为 0 和 1 的墙由付费油漆匠来刷，需要 3 单位时间。同时，免费油漆匠刷下标为 2 和 3 的墙，需要 2 单位时间，开销为 0 。总开销为 1 + 2 = 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>cost = [2,3,4,2], time = [1,1,1,1]\n<b>输出：</b>4\n<b>解释：</b>下标为 0 和 3 的墙由付费油漆匠来刷，需要 2 单位时间。同时，免费油漆匠刷下标为 1 和 2 的墙，需要 2 单位时间，开销为 0 。总开销为 2 + 2 = 4 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= cost.length &lt;= 500</code></li>\n\t<li><code>cost.length == time.length</code></li>\n\t<li><code>1 &lt;= cost[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>1 &lt;= time[i] &lt;= 500</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int paintWalls(vector<int>& cost, vector<int>& time) {\n        \n    }\n};",
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                "Can we break the problem down into smaller subproblems and use DP?",
                "Paid painters will be used for a maximum of N/2 units of time. There is no need to use paid painter for a time greater than this."
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