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https://gitee.com/coder-xiaomo/leetcode-problemset
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93 lines
11 KiB
JSON
93 lines
11 KiB
JSON
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"questionId": "3530",
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"questionFrontendId": "3220",
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"categoryTitle": "Database",
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"boundTopicId": 2847569,
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"title": "Odd and Even Transactions",
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"titleSlug": "odd-and-even-transactions",
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"content": "<p>Table: <code>transactions</code></p>\n\n<pre>\n+------------------+------+\n| Column Name | Type | \n+------------------+------+\n| transaction_id | int |\n| amount | int |\n| transaction_date | date |\n+------------------+------+\nThe transactions_id column uniquely identifies each row in this table.\nEach row of this table contains the transaction id, amount and transaction date.\n</pre>\n\n<p>Write a solution to find the <strong>sum of amounts</strong> for <strong>odd</strong> and <strong>even</strong> transactions for each day. If there are no odd or even transactions for a specific date, display as <code>0</code>.</p>\n\n<p>Return <em>the result table ordered by</em> <code>transaction_date</code> <em>in <strong>ascending</strong> order</em>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong></p>\n\n<p><code>transactions</code> table:</p>\n\n<pre class=\"example-io\">\n+----------------+--------+------------------+\n| transaction_id | amount | transaction_date |\n+----------------+--------+------------------+\n| 1 | 150 | 2024-07-01 |\n| 2 | 200 | 2024-07-01 |\n| 3 | 75 | 2024-07-01 |\n| 4 | 300 | 2024-07-02 |\n| 5 | 50 | 2024-07-02 |\n| 6 | 120 | 2024-07-03 |\n+----------------+--------+------------------+\n </pre>\n\n<p><strong>Output:</strong></p>\n\n<pre class=\"example-io\">\n+------------------+---------+----------+\n| transaction_date | odd_sum | even_sum |\n+------------------+---------+----------+\n| 2024-07-01 | 75 | 350 |\n| 2024-07-02 | 0 | 350 |\n| 2024-07-03 | 0 | 120 |\n+------------------+---------+----------+\n </pre>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>For transaction dates:\n\t<ul>\n\t\t<li>2024-07-01:\n\t\t<ul>\n\t\t\t<li>Sum of amounts for odd transactions: 75</li>\n\t\t\t<li>Sum of amounts for even transactions: 150 + 200 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-02:\n\t\t<ul>\n\t\t\t<li>Sum of amounts for odd transactions: 0</li>\n\t\t\t<li>Sum of amounts for even transactions: 300 + 50 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-03:\n\t\t<ul>\n\t\t\t<li>Sum of amounts for odd transactions: 0</li>\n\t\t\t<li>Sum of amounts for even transactions: 120</li>\n\t\t</ul>\n\t\t</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p><strong>Note:</strong> The output table is ordered by <code>transaction_date</code> in ascending order.</p>\n</div>\n",
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"translatedTitle": "奇数和偶数交易",
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"translatedContent": "<p>表：<code>transactions</code></p>\n\n<pre>\n+------------------+------+\n| Column Name | Type | \n+------------------+------+\n| transaction_id | int |\n| amount | int |\n| transaction_date | date |\n+------------------+------+\ntransactions_id 列唯一标识了表中的每一行。\n这张表的每一行包含交易 id，金额总和和交易日期。\n</pre>\n\n<p>编写一个解决方案来查找每天 <strong>奇数</strong> 交易金额和 <strong>偶数</strong> 交易金额的 <strong>总和</strong>。如果某天没有奇数或偶数交易，显示为 <code>0</code>。</p>\n\n<p>返回结果表以 <code>transaction_date</code> <strong>升序</strong> 排序。</p>\n\n<p>结果格式如下所示。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例：</strong></p>\n\n<div class=\"example-block\">\n<p><b>输入：</b></p>\n\n<p><code>transactions</code> 表：</p>\n\n<pre class=\"example-io\">\n+----------------+--------+------------------+\n| transaction_id | amount | transaction_date |\n+----------------+--------+------------------+\n| 1 | 150 | 2024-07-01 |\n| 2 | 200 | 2024-07-01 |\n| 3 | 75 | 2024-07-01 |\n| 4 | 300 | 2024-07-02 |\n| 5 | 50 | 2024-07-02 |\n| 6 | 120 | 2024-07-03 |\n+----------------+--------+------------------+\n </pre>\n\n<p><strong>输出：</strong></p>\n\n<pre class=\"example-io\">\n+------------------+---------+----------+\n| transaction_date | odd_sum | even_sum |\n+------------------+---------+----------+\n| 2024-07-01 | 75 | 350 |\n| 2024-07-02 | 0 | 350 |\n| 2024-07-03 | 0 | 120 |\n+------------------+---------+----------+\n </pre>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>对于交易日期：\n\t<ul>\n\t\t<li>2024-07-01:\n\t\t<ul>\n\t\t\t<li>奇数交易金额总和：75</li>\n\t\t\t<li>偶数交易金额总和：150 + 200 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-02:\n\t\t<ul>\n\t\t\t<li>奇数交易金额总和：0</li>\n\t\t\t<li>偶数交易金额总和：300 + 50 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-03:\n\t\t<ul>\n\t\t\t<li>奇数交易金额总和：0</li>\n\t\t\t<li>偶数交易金额总和：120</li>\n\t\t</ul>\n\t\t</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p><b>注意：</b>输出表以 <code>transaction_date</code> 升序排序。</p>\n</div>\n",
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"sampleTestCase": "{\"headers\":{\"transactions\":[\"transaction_id\",\"amount\",\"transaction_date\"]},\"rows\":{\"transactions\":[[1,150,\"2024-07-01\"],[2,200,\"2024-07-01\"],[3,75,\"2024-07-01\"],[4,300,\"2024-07-02\"],[5,50,\"2024-07-02\"],[6,120,\"2024-07-03\"]]}}",
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"Create table if not exists transactions ( transaction_id int, amount int, transaction_date date)",
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"Truncate table transactions",
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"insert into transactions (transaction_id, amount, transaction_date) values ('1', '150', '2024-07-01')",
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"insert into transactions (transaction_id, amount, transaction_date) values ('2', '200', '2024-07-01')",
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"insert into transactions (transaction_id, amount, transaction_date) values ('3', '75', '2024-07-01')",
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"insert into transactions (transaction_id, amount, transaction_date) values ('4', '300', '2024-07-02')",
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"insert into transactions (transaction_id, amount, transaction_date) values ('5', '50', '2024-07-02')",
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"insert into transactions (transaction_id, amount, transaction_date) values ('6', '120', '2024-07-03')"
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