leetcode-problemset/leetcode-cn/originData/most-frequent-ids.json

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        "question": {
            "questionId": "3363",
            "questionFrontendId": "3092",
            "categoryTitle": "Algorithms",
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            "title": "Most Frequent IDs",
            "titleSlug": "most-frequent-ids",
            "content": "<p>The problem involves tracking the frequency of IDs in a collection that changes over time. You have two integer arrays, <code>nums</code> and <code>freq</code>, of equal length <code>n</code>. Each element in <code>nums</code> represents an ID, and the corresponding element in <code>freq</code> indicates how many times that ID should be added to or removed from the collection at each step.</p>\n\n<ul>\n\t<li><strong>Addition of IDs:</strong> If <code>freq[i]</code> is positive, it means <code>freq[i]</code> IDs with the value <code>nums[i]</code> are added to the collection at step <code>i</code>.</li>\n\t<li><strong>Removal of IDs:</strong> If <code>freq[i]</code> is negative, it means <code>-freq[i]</code> IDs with the value <code>nums[i]</code> are removed from the collection at step <code>i</code>.</li>\n</ul>\n\n<p>Return an array <code>ans</code> of length <code>n</code>, where <code>ans[i]</code> represents the <strong>count</strong> of the <em>most frequent ID</em> in the collection after the <code>i<sup>th</sup></code>&nbsp;step. If the collection is empty at any step, <code>ans[i]</code> should be 0 for that step.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,3,2,1], freq = [3,2,-3,1]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[3,3,2,2]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>After step 0, we have 3 IDs with the value of 2. So <code>ans[0] = 3</code>.<br />\nAfter step 1, we have 3 IDs with the value of 2 and 2 IDs with the value of 3. So <code>ans[1] = 3</code>.<br />\nAfter step 2, we have 2 IDs with the value of 3. So <code>ans[2] = 2</code>.<br />\nAfter step 3, we have 2 IDs with the value of 3 and 1 ID with the value of 1. So <code>ans[3] = 2</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [5,5,3], freq = [2,-2,1]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[2,0,1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>After step 0, we have 2 IDs with the value of 5. So <code>ans[0] = 2</code>.<br />\nAfter step 1, there are no IDs. So <code>ans[1] = 0</code>.<br />\nAfter step 2, we have 1 ID with the value of 3. So <code>ans[2] = 1</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length == freq.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> &lt;= freq[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>freq[i] != 0</code></li>\n\t<li>The input is generated<!-- notionvc: a136b55a-f319-4fa6-9247-11be9f3b1db8 --> such that the occurrences of an ID will not be negative in any step.</li>\n</ul>\n",
            "translatedTitle": "最高频率的 ID",
            "translatedContent": "<p>你需要在一个集合里动态记录 ID 的出现频率。给你两个长度都为 <code>n</code>&nbsp;的整数数组&nbsp;<code>nums</code> 和&nbsp;<code>freq</code>&nbsp;，<code>nums</code>&nbsp;中每一个元素表示一个 ID ，对应的 <code>freq</code>&nbsp;中的元素表示这个 ID 在集合中此次操作后需要增加或者减少的数目。</p>\n\n<ul>\n\t<li><strong>增加 ID 的数目：</strong>如果&nbsp;<code>freq[i]</code>&nbsp;是正数，那么&nbsp;<code>freq[i]</code>&nbsp;个 ID 为&nbsp;<code>nums[i]</code>&nbsp;的元素在第 <code>i</code>&nbsp;步操作后会添加到集合中。</li>\n\t<li><strong>减少 ID 的数目：</strong>如果&nbsp;<code>freq[i]</code>&nbsp;是负数，那么&nbsp;<code>-freq[i]</code>&nbsp;个 ID 为&nbsp;<code>nums[i]</code>&nbsp;的元素在第 <code>i</code>&nbsp;步操作后会从集合中删除。</li>\n</ul>\n\n<p>请你返回一个长度为 <code>n</code>&nbsp;的数组 <code>ans</code>&nbsp;，其中&nbsp;<code>ans[i]</code>&nbsp;表示第 <code>i</code>&nbsp;步操作后出现频率最高的 ID <strong>数目</strong>&nbsp;，如果在某次操作后集合为空，那么 <code>ans[i]</code>&nbsp;为 0 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [2,3,2,1], freq = [3,2,-3,1]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[3,3,2,2]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>第 0 步操作后，有 3 个 ID 为 2 的元素，所以&nbsp;<code>ans[0] = 3</code>&nbsp;。<br />\n第 1 步操作后，有 3 个 ID 为 2 的元素和 2 个 ID 为 3 的元素，所以&nbsp;<code>ans[1] = 3</code>&nbsp;。<br />\n第 2 步操作后，有 2 个 ID 为 3 的元素，所以&nbsp;<code>ans[2] = 2</code>&nbsp;。<br />\n第 3 步操作后，有 2 个 ID 为 3 的元素和 1 个 ID 为 1 的元素，所以&nbsp;<code>ans[3] = 2</code>&nbsp;。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [5,5,3], freq = [2,-2,1]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[2,0,1]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>第 0 步操作后，有 2 个 ID 为 5 的元素，所以&nbsp;<code>ans[0] = 2</code>&nbsp;。<br />\n第 1 步操作后，集合中没有任何元素，所以&nbsp;<code>ans[1] = 0</code>&nbsp;。<br />\n第 2 步操作后，有 1 个 ID 为 3 的元素，所以&nbsp;<code>ans[2] = 1</code>&nbsp;。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length == freq.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> &lt;= freq[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>freq[i] != 0</code></li>\n\t<li>输入保证任何操作后，集合中的元素出现次数不会为负数。</li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def mostFrequentIDs(self, nums, freq):\n        \"\"\"\n        :type nums: List[int]\n        :type freq: List[int]\n        :rtype: List[int]\n        \"\"\"",
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target=\\\"_blank\\\">Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\"<p>\\u7248\\u672c\\uff1a<code>Go 1.21<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u548c <a href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 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