leetcode-problemset/leetcode-cn/originData/minimum-time-to-visit-a-cell-in-a-grid.json

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            "title": "Minimum Time to Visit a Cell In a Grid",
            "titleSlug": "minimum-time-to-visit-a-cell-in-a-grid",
            "content": "<p>You are given a <code>m x n</code> matrix <code>grid</code> consisting of <b>non-negative</b> integers where <code>grid[row][col]</code> represents the <strong>minimum</strong> time required to be able to visit the cell <code>(row, col)</code>, which means you can visit the cell <code>(row, col)</code> only when the time you visit it is greater than or equal to <code>grid[row][col]</code>.</p>\n\n<p>You are standing in the <strong>top-left</strong> cell of the matrix in the <code>0<sup>th</sup></code> second, and you must move to <strong>any</strong> adjacent cell in the four directions: up, down, left, and right. Each move you make takes 1 second.</p>\n\n<p>Return <em>the <strong>minimum</strong> time required in which you can visit the bottom-right cell of the matrix</em>. If you cannot visit the bottom-right cell, then return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/02/14/yetgriddrawio-8.png\" /></p>\n\n<pre>\n<strong>Input:</strong> grid = [[0,1,3,2],[5,1,2,5],[4,3,8,6]]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> One of the paths that we can take is the following:\n- at t = 0, we are on the cell (0,0).\n- at t = 1, we move to the cell (0,1). It is possible because grid[0][1] &lt;= 1.\n- at t = 2, we move to the cell (1,1). It is possible because grid[1][1] &lt;= 2.\n- at t = 3, we move to the cell (1,2). It is possible because grid[1][2] &lt;= 3.\n- at t = 4, we move to the cell (1,1). It is possible because grid[1][1] &lt;= 4.\n- at t = 5, we move to the cell (1,2). It is possible because grid[1][2] &lt;= 5.\n- at t = 6, we move to the cell (1,3). It is possible because grid[1][3] &lt;= 6.\n- at t = 7, we move to the cell (2,3). It is possible because grid[2][3] &lt;= 7.\nThe final time is 7. It can be shown that it is the minimum time possible.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/02/14/yetgriddrawio-9.png\" style=\"width: 151px; height: 151px;\" /></p>\n\n<pre>\n<strong>Input:</strong> grid = [[0,2,4],[3,2,1],[1,0,4]]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> There is no path from the top left to the bottom-right cell.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>2 &lt;= m, n &lt;= 1000</code></li>\n\t<li><code>4 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= grid[i][j] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>grid[0][0] == 0</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<style type=\"text/css\">.spoilerbutton {display:block; border:dashed; padding: 0px 0px; margin:10px 0px; font-size:150%; font-weight: bold; color:#000000; background-color:cyan; outline:0; \n}\n.spoiler {overflow:hidden;}\n.spoiler > div {-webkit-transition: all 0s ease;-moz-transition: margin 0s ease;-o-transition: all 0s ease;transition: margin 0s ease;}\n.spoilerbutton[value=\"Show Message\"] + .spoiler > div {margin-top:-500%;}\n.spoilerbutton[value=\"Hide Message\"] + .spoiler {padding:5px;}\n</style>\n",
            "translatedTitle": "在网格图中访问一个格子的最少时间",
            "translatedContent": "<p>给你一个&nbsp;<code>m x n</code>&nbsp;的矩阵&nbsp;<code>grid</code>&nbsp;，每个元素都为 <strong>非负</strong>&nbsp;整数，其中&nbsp;<code>grid[row][col]</code>&nbsp;表示可以访问格子&nbsp;<code>(row, col)</code>&nbsp;的&nbsp;<strong>最早</strong>&nbsp;时间。也就是说当你访问格子&nbsp;<code>(row, col)</code>&nbsp;时，最少已经经过的时间为&nbsp;<code>grid[row][col]</code>&nbsp;。</p>\n\n<p>你从 <strong>最左上角</strong>&nbsp;出发，出发时刻为 <code>0</code>&nbsp;，你必须一直移动到上下左右相邻四个格子中的 <strong>任意</strong>&nbsp;一个格子（即不能停留在格子上）。每次移动都需要花费 1 单位时间。</p>\n\n<p>请你返回 <strong>最早</strong>&nbsp;到达右下角格子的时间，如果你无法到达右下角的格子，请你返回 <code>-1</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/02/14/yetgriddrawio-8.png\" /></p>\n\n<pre>\n<b>输入：</b>grid = [[0,1,3,2],[5,1,2,5],[4,3,8,6]]\n<b>输出：</b>7\n<b>解释：</b>一条可行的路径为：\n- 时刻 t = 0 ，我们在格子 (0,0) 。\n- 时刻 t = 1 ，我们移动到格子 (0,1) ，可以移动的原因是 grid[0][1] &lt;= 1 。\n- 时刻 t = 2 ，我们移动到格子 (1,1) ，可以移动的原因是 grid[1][1] &lt;= 2 。\n- 时刻 t = 3 ，我们移动到格子 (1,2) ，可以移动的原因是 grid[1][2] &lt;= 3 。\n- 时刻 t = 4 ，我们移动到格子 (1,1) ，可以移动的原因是 grid[1][1] &lt;= 4 。\n- 时刻 t = 5 ，我们移动到格子 (1,2) ，可以移动的原因是 grid[1][2] &lt;= 5 。\n- 时刻 t = 6 ，我们移动到格子 (1,3) ，可以移动的原因是 grid[1][3] &lt;= 6 。\n- 时刻 t = 7 ，我们移动到格子 (2,3) ，可以移动的原因是 grid[2][3] &lt;= 7 。\n最终到达时刻为 7 。这是最早可以到达的时间。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/02/14/yetgriddrawio-9.png\" style=\"width: 151px; height: 151px;\" /></p>\n\n<pre>\n<b>输入：</b>grid = [[0,2,4],[3,2,1],[1,0,4]]\n<b>输出：</b>-1\n<b>解释：</b>没法从左上角按题目规定走到右下角。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>2 &lt;= m, n &lt;= 1000</code></li>\n\t<li><code>4 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= grid[i][j] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>grid[0][0] == 0</code></li>\n</ul>\n",
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