leetcode-problemset/leetcode-cn/originData/minimum-seconds-to-equalize-a-circular-array.json

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            "title": "Minimum Seconds to Equalize a Circular Array",
            "titleSlug": "minimum-seconds-to-equalize-a-circular-array",
            "content": "<p>You are given a <strong>0-indexed</strong> array <code>nums</code> containing <code>n</code> integers.</p>\n\n<p>At each second, you perform the following operation on the array:</p>\n\n<ul>\n\t<li>For every index <code>i</code> in the range <code>[0, n - 1]</code>, replace <code>nums[i]</code> with either <code>nums[i]</code>, <code>nums[(i - 1 + n) % n]</code>, or <code>nums[(i + 1) % n]</code>.</li>\n</ul>\n\n<p><strong>Note</strong> that all the elements get replaced simultaneously.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of seconds needed to make all elements in the array</em> <code>nums</code> <em>equal</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,1,2]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> We can equalize the array in 1 second in the following way:\n- At 1<sup>st</sup> second, replace values at each index with [nums[3],nums[1],nums[3],nums[3]]. After replacement, nums = [2,2,2,2].\nIt can be proven that 1 second is the minimum amount of seconds needed for equalizing the array.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,1,3,3,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We can equalize the array in 2 seconds in the following way:\n- At 1<sup>st</sup> second, replace values at each index with [nums[0],nums[2],nums[2],nums[2],nums[3]]. After replacement, nums = [2,3,3,3,3].\n- At 2<sup>nd</sup> second, replace values at each index with [nums[1],nums[1],nums[2],nums[3],nums[4]]. After replacement, nums = [3,3,3,3,3].\nIt can be proven that 2 seconds is the minimum amount of seconds needed for equalizing the array.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,5,5,5]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> We don&#39;t need to perform any operations as all elements in the initial array are the same.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "使循环数组所有元素相等的最少秒数",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始长度为 <code>n</code>&nbsp;的数组&nbsp;<code>nums</code>&nbsp;。</p>\n\n<p>每一秒，你可以对数组执行以下操作：</p>\n\n<ul>\n\t<li>对于范围在&nbsp;<code>[0, n - 1]</code>&nbsp;内的每一个下标&nbsp;<code>i</code>&nbsp;，将&nbsp;<code>nums[i]</code> 替换成&nbsp;<code>nums[i]</code>&nbsp;，<code>nums[(i - 1 + n) % n]</code>&nbsp;或者&nbsp;<code>nums[(i + 1) % n]</code>&nbsp;三者之一。</li>\n</ul>\n\n<p><strong>注意</strong>，所有元素会被同时替换。</p>\n\n<p>请你返回将数组 <code>nums</code>&nbsp;中所有元素变成相等元素所需要的 <strong>最少</strong>&nbsp;秒数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [1,2,1,2]\n<b>输出：</b>1\n<b>解释：</b>我们可以在 1 秒内将数组变成相等元素：\n- 第 1 秒，将每个位置的元素分别变为 [nums[3],nums[1],nums[3],nums[3]] 。变化后，nums = [2,2,2,2] 。\n1 秒是将数组变成相等元素所需要的最少秒数。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [2,1,3,3,2]\n<b>输出：</b>2\n<b>解释：</b>我们可以在 2 秒内将数组变成相等元素：\n- 第 1 秒，将每个位置的元素分别变为 [nums[0],nums[2],nums[2],nums[2],nums[3]] 。变化后，nums = [2,3,3,3,3] 。\n- 第 2 秒，将每个位置的元素分别变为 [nums[1],nums[1],nums[2],nums[3],nums[4]] 。变化后，nums = [3,3,3,3,3] 。\n2 秒是将数组变成相等元素所需要的最少秒数。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><b>输入：</b>nums = [5,5,5,5]\n<b>输出：</b>0\n<b>解释：</b>不需要执行任何操作，因为一开始数组中的元素已经全部相等。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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