leetcode-problemset/leetcode-cn/originData/minimum-operations-to-collect-elements.json

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            "questionId": "3044",
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            "categoryTitle": "Algorithms",
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            "title": "Minimum Operations to Collect Elements",
            "titleSlug": "minimum-operations-to-collect-elements",
            "content": "<p>You are given an array <code>nums</code> of positive integers and an integer <code>k</code>.</p>\n\n<p>In one operation, you can remove the last element of the array and add it to your collection.</p>\n\n<p>Return <em>the <strong>minimum number of operations</strong> needed to collect elements</em> <code>1, 2, ..., k</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,5,4,2], k = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> After 4 operations, we collect elements 2, 4, 5, and 1, in this order. Our collection contains elements 1 and 2. Hence, the answer is 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,5,4,2], k = 5\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> After 5 operations, we collect elements 2, 4, 5, 1, and 3, in this order. Our collection contains elements 1 through 5. Hence, the answer is 5.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,2,5,3,1], k = 3\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> After 4 operations, we collect elements 1, 3, 5, and 2, in this order. Our collection contains elements 1 through 3. Hence, the answer is 4.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= nums.length</code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length</code></li>\n\t<li>The input is generated such that you can collect elements <code>1, 2, ..., k</code>.</li>\n</ul>\n",
            "translatedTitle": "收集元素的最少æ“<C3A6>作次数",
            "translatedContent": "<p>给你一个正整数数组&nbsp;<code>nums</code>&nbsp;和一个整数&nbsp;<code>k</code>&nbsp;。</p>\n\n<p>一次æ“<C3A6>作中，你å<C2A0>¯ä»¥å°†æ•°ç»„的最å<E282AC>Žä¸€ä¸ªå…ƒç´ åˆ é™¤ï¼Œå°†è¯¥å…ƒç´ æ·»åŠ åˆ°ä¸€ä¸ªé›†å<E280A0>ˆä¸­ã€‚</p>\n\n<p>请你返回收集元素&nbsp;<code>1, 2, ..., k</code>&nbsp;需è¦<C3A8>çš„&nbsp;<strong>最少æ“<C3A6>作次数</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [3,1,5,4,2], k = 2\n<b>输出：</b>4\n<b>解释：</b>4 次æ“<C3A6>作å<C593>Žï¼Œé›†å<E280A0>ˆä¸­çš„元素ä¾<C3A4>次添加了 2 ，4 ，5 å’Œ 1 。此时集å<E280A0>ˆä¸­åŒ…å<E280A6>«å…ƒç´  1 å’Œ 2 ，所以答案为 4 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [3,1,5,4,2], k = 5\n<b>输出：</b>5\n<b>解释：</b>5 次æ“<C3A6>作å<C593>Žï¼Œé›†å<E280A0>ˆä¸­çš„元素ä¾<C3A4>次添加了 2 ，4 ，5 ，1 å’Œ 3 。此时集å<E280A0>ˆä¸­åŒ…å<E280A6>«å…ƒç´  1 到 5 ，所以答案为 5 。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [3,2,5,3,1], k = 3\n<b>输出：</b>4\n<b>解释：</b>4 次æ“<C3A6>作å<C593>Žï¼Œé›†å<E280A0>ˆä¸­çš„元素ä¾<C3A4>次添加了 1 ，3 ，5 å’Œ 2 。此时集å<E280A0>ˆä¸­åŒ…å<E280A6>«å…ƒç´  1 到 3  ，所以答案为 4 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>æ<><C3A6>示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= nums.length</code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length</code></li>\n\t<li>输入ä¿<C3A4>è¯<C3A8>ä½ å<C2A0>¯ä»¥æ”¶é›†åˆ°å…ƒç´ &nbsp;<code>1, 2, ..., k</code> 。</li>\n</ul>\n",
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                "Use an occurrence array.",
                "Iterate over the elements in reverse order.",
                "If the current element <code>nums[i]</code> is not marked in the occurrence array and <code>nums[i] &lt;= k</code>, mark <code>nums[i]</code>.",
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