leetcode-problemset/leetcode-cn/originData/maximum-subarray-min-product.json

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            "title": "Maximum Subarray Min-Product",
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            "content": "<p>The <strong>min-product</strong> of an array is equal to the <strong>minimum value</strong> in the array <strong>multiplied by</strong> the array&#39;s <strong>sum</strong>.</p>\n\n<ul>\n\t<li>For example, the array <code>[3,2,5]</code> (minimum value is <code>2</code>) has a min-product of <code>2 * (3+2+5) = 2 * 10 = 20</code>.</li>\n</ul>\n\n<p>Given an array of integers <code>nums</code>, return <em>the <strong>maximum min-product</strong> of any <strong>non-empty subarray</strong> of </em><code>nums</code>. Since the answer may be large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>Note that the min-product should be maximized <strong>before</strong> performing the modulo operation. Testcases are generated such that the maximum min-product <strong>without</strong> modulo will fit in a <strong>64-bit signed integer</strong>.</p>\n\n<p>A <strong>subarray</strong> is a <strong>contiguous</strong> part of an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,<u>2,3,2</u>]\n<strong>Output:</strong> 14\n<strong>Explanation:</strong> The maximum min-product is achieved with the subarray [2,3,2] (minimum value is 2).\n2 * (2+3+2) = 2 * 7 = 14.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,<u>3,3</u>,1,2]\n<strong>Output:</strong> 18\n<strong>Explanation:</strong> The maximum min-product is achieved with the subarray [3,3] (minimum value is 3).\n3 * (3+3) = 3 * 6 = 18.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,<u>5,6,4</u>,2]\n<strong>Output:</strong> 60\n<strong>Explanation:</strong> The maximum min-product is achieved with the subarray [5,6,4] (minimum value is 4).\n4 * (5+6+4) = 4 * 15 = 60.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>7</sup></code></li>\n</ul>\n",
            "translatedTitle": "子数组最小乘积的最大值",
            "translatedContent": "<p>一个数组的 <strong>最小乘积</strong> 定义为这个数组中 <strong>最小值</strong> <strong>乘以 </strong>数组的 <strong>和</strong> 。</p>\n\n<ul>\n\t<li>比方说，数组 <code>[3,2,5]</code> （最小值是 <code>2</code>）的最小乘积为 <code>2 * (3+2+5) = 2 * 10 = 20</code> 。</li>\n</ul>\n\n<p>给你一个正整数数组 <code>nums</code> ，请你返回 <code>nums</code> 任意 <strong>非空子数组</strong> 的<strong>最小乘积</strong> 的 <strong>最大值</strong> 。由于答案可能很大，请你返回答案对  <code>10<sup>9</sup> + 7</code> <strong>取余 </strong>的结果。</p>\n\n<p>请注意，最小乘积的最大值考虑的是取余操作 <strong>之前</strong> 的结果。题目保证最小乘积的最大值在 <strong>不取余</strong> 的情况下可以用 <strong>64 位有符号整数</strong> 保存。</p>\n\n<p><strong>子数组</strong> 定义为一个数组的 <strong>连续</strong> 部分。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,<strong>2,3,2</strong>]\n<b>输出：</b>14\n<b>解释：</b>最小乘积的最大值由子数组 [2,3,2] （最小值是 2）得到。\n2 * (2+3+2) = 2 * 7 = 14 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [2,<strong>3,3</strong>,1,2]\n<b>输出：</b>18\n<b>解释：</b>最小乘积的最大值由子数组 [3,3] （最小值是 3）得到。\n3 * (3+3) = 3 * 6 = 18 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [3,1,<strong>5,6,4</strong>,2]\n<b>输出：</b>60\n<b>解释：</b>最小乘积的最大值由子数组 [5,6,4] （最小值是 4）得到。\n4 * (5+6+4) = 4 * 15 = 60 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>7</sup></code></li>\n</ul>\n",
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