mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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184 lines
22 KiB
JSON
184 lines
22 KiB
JSON
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"title": "Maximum Product of the Length of Two Palindromic Substrings",
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"content": "<p>You are given a <strong>0-indexed</strong> string <code>s</code> and are tasked with finding two <strong>non-intersecting palindromic </strong>substrings of <strong>odd</strong> length such that the product of their lengths is maximized.</p>\n\n<p>More formally, you want to choose four integers <code>i</code>, <code>j</code>, <code>k</code>, <code>l</code> such that <code>0 <= i <= j < k <= l < s.length</code> and both the substrings <code>s[i...j]</code> and <code>s[k...l]</code> are palindromes and have odd lengths. <code>s[i...j]</code> denotes a substring from index <code>i</code> to index <code>j</code> <strong>inclusive</strong>.</p>\n\n<p>Return <em>the <strong>maximum</strong> possible product of the lengths of the two non-intersecting palindromic substrings.</em></p>\n\n<p>A <strong>palindrome</strong> is a string that is the same forward and backward. A <strong>substring</strong> is a contiguous sequence of characters in a string.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "ababbb"\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> Substrings "aba" and "bbb" are palindromes with odd length. product = 3 * 3 = 9.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "zaaaxbbby"\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> Substrings "aaa" and "bbb" are palindromes with odd length. product = 3 * 3 = 9.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
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"translatedTitle": "两个回文子字符串长度的最大乘积",
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"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的字符串 <code>s</code> ,你需要找到两个 <strong>不重叠</strong><strong>的回文 </strong>子字符串,它们的长度都必须为 <strong>奇数</strong> ,使得它们长度的乘积最大。</p>\n\n<p>更正式地,你想要选择四个整数 <code>i</code> ,<code>j</code> ,<code>k</code> ,<code>l</code> ,使得 <code>0 <= i <= j < k <= l < s.length</code> ,且子字符串 <code>s[i...j]</code> 和 <code>s[k...l]</code> 都是回文串且长度为奇数。<code>s[i...j]</code> 表示下标从 <code>i</code> 到 <code>j</code> 且 <strong>包含</strong> 两端下标的子字符串。</p>\n\n<p>请你返回两个不重叠回文子字符串长度的 <strong>最大</strong> 乘积。</p>\n\n<p><strong>回文字符串</strong> 指的是一个从前往后读和从后往前读一模一样的字符串。<strong>子字符串</strong> 指的是一个字符串中一段连续字符。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<b>输入:</b>s = \"ababbb\"\n<b>输出:</b>9\n<b>解释:</b>子字符串 \"aba\" 和 \"bbb\" 为奇数长度的回文串。乘积为 3 * 3 = 9 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<b>输入:</b>s = \"zaaaxbbby\"\n<b>输出:</b>9\n<b>解释:</b>子字符串 \"aaa\" 和 \"bbb\" 为奇数长度的回文串。乘积为 3 * 3 = 9 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 只包含小写英文字母。</li>\n</ul>\n",
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"You can use Manacher's algorithm to get the maximum palindromic substring centered at each index",
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"After using Manacher's for each center use a line sweep from the center to the left and from the center to the right to find for each index the farthest center to it with distance ≤ palin[center]",
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"After that, find the maximum palindrome size for each prefix in the string and for each suffix and the answer would be max(prefix[i] * suffix[i + 1])"
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