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leetcode-problemset/leetcode-cn/originData/longest-word-in-dictionary.json
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{
"data": {
"question": {
"questionId": "720",
"questionFrontendId": "720",
"categoryTitle": "Algorithms",
"boundTopicId": 1768,
"title": "Longest Word in Dictionary",
"titleSlug": "longest-word-in-dictionary",
"content": "<p>Given an array of strings <code>words</code> representing an English Dictionary, return <em>the longest word in</em> <code>words</code> <em>that can be built one character at a time by other words in</em> <code>words</code>.</p>\n\n<p>If there is more than one possible answer, return the longest word with the smallest lexicographical order. If there is no answer, return the empty string.</p>\n\n<p>Note that the word should be built from left to right with each additional character being added to the end of a previous word.&nbsp;</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;w&quot;,&quot;wo&quot;,&quot;wor&quot;,&quot;worl&quot;,&quot;world&quot;]\n<strong>Output:</strong> &quot;world&quot;\n<strong>Explanation:</strong> The word &quot;world&quot; can be built one character at a time by &quot;w&quot;, &quot;wo&quot;, &quot;wor&quot;, and &quot;worl&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;a&quot;,&quot;banana&quot;,&quot;app&quot;,&quot;appl&quot;,&quot;ap&quot;,&quot;apply&quot;,&quot;apple&quot;]\n<strong>Output:</strong> &quot;apple&quot;\n<strong>Explanation:</strong> Both &quot;apply&quot; and &quot;apple&quot; can be built from other words in the dictionary. However, &quot;apple&quot; is lexicographically smaller than &quot;apply&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 30</code></li>\n\t<li><code>words[i]</code> consists of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "词典中最长的单词",
"translatedContent": "<p>给出一个字符串数组&nbsp;<code>words</code> 组成的一本英语词典。返回&nbsp;<code>words</code> 中最长的一个单词,该单词是由&nbsp;<code>words</code>&nbsp;词典中其他单词逐步添加一个字母组成。</p>\n\n<p>若其中有多个可行的答案,则返回答案中字典序最小的单词。若无答案,则返回空字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"w\",\"wo\",\"wor\",\"worl\", \"world\"]\n<strong>输出:</strong>\"world\"\n<strong>解释:</strong> 单词\"world\"可由\"w\", \"wo\", \"wor\", 和 \"worl\"逐步添加一个字母组成。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"a\", \"banana\", \"app\", \"appl\", \"ap\", \"apply\", \"apple\"]\n<strong>输出:</strong>\"apple\"\n<strong>解释:</strong>\"apply\" 和 \"apple\" 都能由词典中的单词组成。但是 \"apple\" 的字典序小于 \"apply\" \n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 30</code></li>\n\t<li>所有输入的字符串&nbsp;<code>words[i]</code>&nbsp;都只包含小写字母。</li>\n</ul>\n",
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"slug": "trie",
"translatedName": "字典树",
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"translatedName": "数组",
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"code": "class Solution(object):\n def longestWord(self, words):\n \"\"\"\n :type words: List[str]\n :rtype: str\n \"\"\"",
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"code": "impl Solution {\n pub fn longest_word(words: Vec<String>) -> String {\n\n }\n}",
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"For every word in the input list, we can check whether all prefixes of that word are in the input list by using a Set."
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