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leetcode-problemset/leetcode-cn/originData/longest-palindromic-substring.json
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{
"data": {
"question": {
"questionId": "5",
"questionFrontendId": "5",
"categoryTitle": "Algorithms",
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"title": "Longest Palindromic Substring",
"titleSlug": "longest-palindromic-substring",
"content": "<p>Given a string <code>s</code>, return <em>the longest</em> <span data-keyword=\"palindromic-string\"><em>palindromic</em></span> <span data-keyword=\"substring-nonempty\"><em>substring</em></span> in <code>s</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;babad&quot;\n<strong>Output:</strong> &quot;bab&quot;\n<strong>Explanation:</strong> &quot;aba&quot; is also a valid answer.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;cbbd&quot;\n<strong>Output:</strong> &quot;bb&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> consist of only digits and English letters.</li>\n</ul>\n",
"translatedTitle": "最长回文子串",
"translatedContent": "<p>给你一个字符串 <code>s</code>,找到 <code>s</code> 中最长的回文子串。</p>\n\n<p>如果字符串的反序与原始字符串相同,则该字符串称为回文字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"babad\"\n<strong>输出:</strong>\"bab\"\n<strong>解释:</strong>\"aba\" 同样是符合题意的答案。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"cbbd\"\n<strong>输出:</strong>\"bb\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> 仅由数字和英文字母组成</li>\n</ul>\n",
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"hints": [
"How can we reuse a previously computed palindrome to compute a larger palindrome?",
"If “aba” is a palindrome, is “xabax” a palindrome? Similarly is “xabay” a palindrome?",
"Complexity based hint:</br>\r\nIf we use brute-force and check whether for every start and end position a substring is a palindrome we have O(n^2) start - end pairs and O(n) palindromic checks. Can we reduce the time for palindromic checks to O(1) by reusing some previous computation."
],
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