leetcode-problemset/leetcode-cn/originData/longest-non-decreasing-subarray-from-two-arrays.json

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            "title": "Longest Non-decreasing Subarray From Two Arrays",
            "titleSlug": "longest-non-decreasing-subarray-from-two-arrays",
            "content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code> of length <code>n</code>.</p>\n\n<p>Let&#39;s define another <strong>0-indexed</strong> integer array, <code>nums3</code>, of length <code>n</code>. For each index <code>i</code> in the range <code>[0, n - 1]</code>, you can assign either <code>nums1[i]</code> or <code>nums2[i]</code> to <code>nums3[i]</code>.</p>\n\n<p>Your task is to maximize the length of the <strong>longest non-decreasing subarray</strong> in <code>nums3</code> by choosing its values optimally.</p>\n\n<p>Return <em>an integer representing the length of the <strong>longest non-decreasing</strong> subarray in</em> <code>nums3</code>.</p>\n\n<p><strong>Note: </strong>A <strong>subarray</strong> is a contiguous <strong>non-empty</strong> sequence of elements within an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [2,3,1], nums2 = [1,2,1]\n<strong>Output:</strong> 2\n<strong>Explanation: </strong>One way to construct nums3 is: \nnums3 = [nums1[0], nums2[1], nums2[2]] =&gt; [2,2,1]. \nThe subarray starting from index 0 and ending at index 1, [2,2], forms a non-decreasing subarray of length 2. \nWe can show that 2 is the maximum achievable length.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,3,2,1], nums2 = [2,2,3,4]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> One way to construct nums3 is: \nnums3 = [nums1[0], nums2[1], nums2[2], nums2[3]] =&gt; [1,2,3,4]. \nThe entire array forms a non-decreasing subarray of length 4, making it the maximum achievable length.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,1], nums2 = [2,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> One way to construct nums3 is: \nnums3 = [nums1[0], nums1[1]] =&gt; [1,1]. \nThe entire array forms a non-decreasing subarray of length 2, making it the maximum achievable length.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length == nums2.length == n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "构造最长非递减子数组",
            "translatedContent": "<p>给你两个下标从 <strong>0</strong> 开始的整数数组 <code>nums1</code> 和 <code>nums2</code> ，长度均为 <code>n</code> 。</p>\n\n<p>让我们定义另一个下标从 <strong>0</strong> 开始、长度为 <code>n</code> 的整数数组，<code>nums3</code> 。对于范围&nbsp;<code>[0, n - 1]</code> 的每个下标 <code>i</code> ，你可以将 <code>nums1[i]</code> 或 <code>nums2[i]</code> 的值赋给 <code>nums3[i]</code> 。</p>\n\n<p>你的任务是使用最优策略为 <code>nums3</code> 赋值，以最大化 <code>nums3</code> 中 <strong>最长非递减子数组</strong> 的长度。</p>\n\n<p>以整数形式表示并返回 <code>nums3</code> 中 <strong>最长非递减</strong> 子数组的长度。</p>\n\n<p><strong>注意：子数组</strong> 是数组中的一个连续非空元素序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums1 = [2,3,1], nums2 = [1,2,1]\n<strong>输出：</strong>2\n<strong>解释：</strong>构造 nums3 的方法之一是： \nnums3 = [nums1[0], nums2[1], nums2[2]] =&gt; [2,2,1]\n从下标 0 开始到下标 1 结束，形成了一个长度为 2 的非递减子数组 [2,2] 。 \n可以证明 2 是可达到的最大长度。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums1 = [1,3,2,1], nums2 = [2,2,3,4]\n<strong>输出：</strong>4\n<strong>解释：</strong>构造 nums3 的方法之一是： \nnums3 = [nums1[0], nums2[1], nums2[2], nums2[3]] =&gt; [1,2,3,4]\n整个数组形成了一个长度为 4 的非递减子数组，并且是可达到的最大长度。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>nums1 = [1,1], nums2 = [2,2]\n<strong>输出：</strong>2\n<strong>解释：</strong>构造 nums3 的方法之一是： \nnums3 = [nums1[0], nums1[1]] =&gt; [1,1] \n整个数组形成了一个长度为 2 的非递减子数组，并且是可达到的最大长度。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length == nums2.length == n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                "Let dp[i][0] (dp[i][1]) be the length of the longest non-decreasing ending with nums1[i] (nums2[i]).",
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