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leetcode-problemset/leetcode-cn/originData/k-closest-points-to-origin.json
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"title": "K Closest Points to Origin",
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"content": "<p>Given an array of <code>points</code> where <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> represents a point on the <strong>X-Y</strong> plane and an integer <code>k</code>, return the <code>k</code> closest points to the origin <code>(0, 0)</code>.</p>\n\n<p>The distance between two points on the <strong>X-Y</strong> plane is the Euclidean distance (i.e., <code>&radic;(x<sub>1</sub> - x<sub>2</sub>)<sup>2</sup> + (y<sub>1</sub> - y<sub>2</sub>)<sup>2</sup></code>).</p>\n\n<p>You may return the answer in <strong>any order</strong>. The answer is <strong>guaranteed</strong> to be <strong>unique</strong> (except for the order that it is in).</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/03/closestplane1.jpg\" style=\"width: 400px; height: 400px;\" />\n<pre>\n<strong>Input:</strong> points = [[1,3],[-2,2]], k = 1\n<strong>Output:</strong> [[-2,2]]\n<strong>Explanation:</strong>\nThe distance between (1, 3) and the origin is sqrt(10).\nThe distance between (-2, 2) and the origin is sqrt(8).\nSince sqrt(8) &lt; sqrt(10), (-2, 2) is closer to the origin.\nWe only want the closest k = 1 points from the origin, so the answer is just [[-2,2]].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> points = [[3,3],[5,-1],[-2,4]], k = 2\n<strong>Output:</strong> [[3,3],[-2,4]]\n<strong>Explanation:</strong> The answer [[-2,4],[3,3]] would also be accepted.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= points.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
"translatedTitle": "最接近原点的 K 个点",
"translatedContent": "<p>给定一个数组 <code>points</code>&nbsp;,其中&nbsp;<code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code>&nbsp;表示 <strong>X-Y</strong> 平面上的一个点,并且是一个整数 <code>k</code> ,返回离原点 <code>(0,0)</code> 最近的 <code>k</code> 个点。</p>\n\n<p>这里,平面上两点之间的距离是&nbsp;<strong>欧几里德距离</strong>&nbsp;<code>√(x<sub>1</sub>&nbsp;- x<sub>2</sub>)<sup>2</sup>&nbsp;+ (y<sub>1</sub>&nbsp;- y<sub>2</sub>)<sup>2</sup></code>&nbsp;)。</p>\n\n<p>你可以按 <strong>任何顺序</strong> 返回答案。除了点坐标的顺序之外,答案 <strong>确保</strong> 是 <strong>唯一</strong> 的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/03/03/closestplane1.jpg\" style=\"height: 400px; width: 400px;\" /></p>\n\n<pre>\n<strong>输入:</strong>points = [[1,3],[-2,2]], k = 1\n<strong>输出:</strong>[[-2,2]]\n<strong>解释: </strong>\n(1, 3) 和原点之间的距离为 sqrt(10)\n(-2, 2) 和原点之间的距离为 sqrt(8)\n由于 sqrt(8) &lt; sqrt(10)(-2, 2) 离原点更近。\n我们只需要距离原点最近的 K = 1 个点,所以答案就是 [[-2,2]]。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>points = [[3,3],[5,-1],[-2,4]], k = 2\n<strong>输出:</strong>[[3,3],[-2,4]]\n答案 [[-2,4],[3,3]] 也会被接受。)\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= points.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup>&nbsp;&lt; x<sub>i</sub>, y<sub>i</sub>&nbsp;&lt; 10<sup>4</sup></code></li>\n</ul>\n",
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