mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
182 lines
28 KiB
JSON
182 lines
28 KiB
JSON
{
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"questionId": "1157",
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"questionFrontendId": "1080",
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"categoryTitle": "Algorithms",
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"boundTopicId": 7692,
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"title": "Insufficient Nodes in Root to Leaf Paths",
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"titleSlug": "insufficient-nodes-in-root-to-leaf-paths",
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"content": "<p>Given the <code>root</code> of a binary tree and an integer <code>limit</code>, delete all <strong>insufficient nodes</strong> in the tree simultaneously, and return <em>the root of the resulting binary tree</em>.</p>\n\n<p>A node is <strong>insufficient</strong> if every root to <strong>leaf</strong> path intersecting this node has a sum strictly less than <code>limit</code>.</p>\n\n<p>A <strong>leaf</strong> is a node with no children.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/06/05/insufficient-11.png\" style=\"width: 500px; height: 207px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,3,4,-99,-99,7,8,9,-99,-99,12,13,-99,14], limit = 1\n<strong>Output:</strong> [1,2,3,4,null,null,7,8,9,null,14]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/06/05/insufficient-3.png\" style=\"width: 400px; height: 274px;\" />\n<pre>\n<strong>Input:</strong> root = [5,4,8,11,null,17,4,7,1,null,null,5,3], limit = 22\n<strong>Output:</strong> [5,4,8,11,null,17,4,7,null,null,null,5]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/06/11/screen-shot-2019-06-11-at-83301-pm.png\" style=\"width: 250px; height: 199px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,-3,-5,null,4,null], limit = -1\n<strong>Output:</strong> [1,null,-3,4]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 5000]</code>.</li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> <= limit <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedTitle": "根到叶路径上的不足节点",
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"translatedContent": "<p>给你二叉树的根节点 <code>root</code> 和一个整数 <code>limit</code> ，请你同时删除树中所有 <strong>不足节点 </strong>，并返回最终二叉树的根节点。</p>\n\n<p>假如通过节点 <code>node</code> 的每种可能的 “根-叶” 路径上值的总和全都小于给定的 <code>limit</code>，则该节点被称之为<strong> 不足节点 </strong>，需要被删除。</p>\n\n<p><strong>叶子节点</strong>，就是没有子节点的节点。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/06/05/insufficient-11.png\" style=\"width: 500px; height: 207px;\" />\n<pre>\n<strong>输入：</strong>root = [1,2,3,4,-99,-99,7,8,9,-99,-99,12,13,-99,14], limit = 1\n<strong>输出：</strong>[1,2,3,4,null,null,7,8,9,null,14]\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/06/05/insufficient-3.png\" style=\"width: 400px; height: 274px;\" />\n<pre>\n<strong>输入：</strong>root = [5,4,8,11,null,17,4,7,1,null,null,5,3], limit = 22\n<strong>输出：</strong>[5,4,8,11,null,17,4,7,null,null,null,5]\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/06/11/screen-shot-2019-06-11-at-83301-pm.png\" style=\"width: 250px; height: 199px;\" />\n<pre>\n<strong>输入：</strong>root = [1,2,-3,-5,null,4,null], limit = -1\n<strong>输出：</strong>[1,null,-3,4]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数目在范围 <code>[1, 5000]</code> 内</li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> <= limit <= 10<sup>9</sup></code></li>\n</ul>\n\n<p> </p>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* sufficientSubset(TreeNode* root, int limit) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode SufficientSubset(TreeNode root, int limit) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} limit\n * @return {TreeNode}\n */\nvar sufficientSubset = function(root, limit) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction sufficientSubset(root: TreeNode | null, limit: number): TreeNode | null {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $limit\n * @return TreeNode\n */\n function sufficientSubset($root, $limit) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func sufficientSubset(_ root: TreeNode?, _ limit: Int) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun sufficientSubset(root: TreeNode?, limit: Int): TreeNode? {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? sufficientSubset(TreeNode? root, int limit) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc sufficientSubset(root *TreeNode, limit int) *TreeNode {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} limit\n# @return {TreeNode}\ndef sufficient_subset(root, limit)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def sufficientSubset(root: TreeNode, limit: Int): TreeNode = {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec sufficient_subset(root :: TreeNode.t | nil, limit :: integer) :: TreeNode.t | nil\n def sufficient_subset(root, limit) do\n \n end\nend",
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"Consider a DFS traversal of the tree. You can keep track of the current path sum from root to this node, and you can also use DFS to return the minimum value of any path from this node to the leaf. This will tell you if this node is insufficient."
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