leetcode-problemset/leetcode-cn/originData/house-robber-iv.json

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            "title": "House Robber IV",
            "titleSlug": "house-robber-iv",
            "content": "<p>There are several consecutive houses along a street, each of which has some money inside. There is also a robber, who wants to steal money from the homes, but he <strong>refuses to steal from adjacent homes</strong>.</p>\n\n<p>The <strong>capability</strong> of the robber is the maximum amount of money he steals from one house of all the houses he robbed.</p>\n\n<p>You are given an integer array <code>nums</code> representing how much money is stashed in each house. More formally, the <code>i<sup>th</sup></code> house from the left has <code>nums[i]</code> dollars.</p>\n\n<p>You are also given an integer <code>k</code>, representing the <strong>minimum</strong> number of houses the robber will steal from. It is always possible to steal at least <code>k</code> houses.</p>\n\n<p>Return <em>the <strong>minimum</strong> capability of the robber out of all the possible ways to steal at least </em><code>k</code><em> houses</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,3,5,9], k = 2\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> \nThere are three ways to rob at least 2 houses:\n- Rob the houses at indices 0 and 2. Capability is max(nums[0], nums[2]) = 5.\n- Rob the houses at indices 0 and 3. Capability is max(nums[0], nums[3]) = 9.\n- Rob the houses at indices 1 and 3. Capability is max(nums[1], nums[3]) = 9.\nTherefore, we return min(5, 9, 9) = 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,7,9,3,1], k = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> There are 7 ways to rob the houses. The way which leads to minimum capability is to rob the house at index 0 and 4. Return max(nums[0], nums[4]) = 2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= (nums.length + 1)/2</code></li>\n</ul>\n",
            "translatedTitle": "打家劫舍 IV",
            "translatedContent": "<p>沿街有一排连续的房屋。每间房屋内都藏有一定的现金。现在有一位小偷计划从这些房屋中窃取现金。</p>\n\n<p>由于相邻的房屋装有相互连通的防盗系统，所以小偷 <strong>不会窃取相邻的房屋</strong> 。</p>\n\n<p>小偷的 <strong>窃取能力</strong> 定义为他在窃取过程中能从单间房屋中窃取的 <strong>最大金额</strong> 。</p>\n\n<p>给你一个整数数组 <code>nums</code> 表示每间房屋存放的现金金额。形式上，从左起第 <code>i</code> 间房屋中放有 <code>nums[i]</code> 美元。</p>\n\n<p>另给你一个整数&nbsp;<code>k</code> ，表示窃贼将会窃取的 <strong>最少</strong> 房屋数。小偷总能窃取至少 <code>k</code> 间房屋。</p>\n\n<p>返回小偷的 <strong>最小</strong> 窃取能力。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,3,5,9], k = 2\n<strong>输出：</strong>5\n<strong>解释：</strong>\n小偷窃取至少 2 间房屋，共有 3 种方式：\n- 窃取下标 0 和 2 处的房屋，窃取能力为 max(nums[0], nums[2]) = 5 。\n- 窃取下标 0 和 3 处的房屋，窃取能力为 max(nums[0], nums[3]) = 9 。\n- 窃取下标 1 和 3 处的房屋，窃取能力为 max(nums[1], nums[3]) = 9 。\n因此，返回 min(5, 9, 9) = 5 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,7,9,3,1], k = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>共有 7 种窃取方式。窃取能力最小的情况所对应的方式是窃取下标 0 和 4 处的房屋。返回 max(nums[0], nums[4]) = 2 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= (nums.length + 1)/2</code></li>\n</ul>\n",
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