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leetcode-problemset/leetcode-cn/originData/gu-piao-de-zui-da-li-run-lcof.json
2023-12-09 19:57:46 +08:00

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{
"data": {
"question": {
"questionId": "100344",
"questionFrontendId": "LCR 188",
"categoryTitle": "Algorithms",
"boundTopicId": 88179,
"title": "买卖芯片的最佳时机",
"titleSlug": "gu-piao-de-zui-da-li-run-lcof",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "买卖芯片的最佳时机",
"translatedContent": "<p>数组 <code>prices</code> 记录了某芯片近期的交易价格,其中 <code>prices[i]</code> 表示的 <code>i</code> 天该芯片的价格。你只能选择 <strong>某一天</strong> 买入芯片,并选择在 <strong>未来的某一个不同的日子</strong> 卖出该芯片。请设计一个算法计算并返回你从这笔交易中能获取的最大利润。</p>\n\n<p>如果你不能获取任何利润,返回 0。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>prices = [3, 6, 2, 9, 8, 5]\n<strong>输出:</strong>7\n<strong>解释:</strong>在第 3 天(芯片价格 = 2买入在第 4 天(芯片价格 = 9卖出最大利润 = 9 - 2 = 7。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>prices = [8, 12, 15, 7, 3, 10]\n<strong>输出:</strong>7\n<strong>解释:</strong>在第 5 天(芯片价格 = 3买入在第 6 天(芯片价格 = 10卖出最大利润 = 10 - 3 = 7。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><b>提示:</b></p>\n\n<ul>\n\t<li><code>0 &lt;= prices.length &lt;= 10^5</code></li>\n\t<li><code>0 &lt;= prices[i] &lt;= 10^4</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>注意:</strong>本题与主站 121 题相同:<a href=\"https://leetcode-cn.com/problems/best-time-to-buy-and-sell-stock/\">https://leetcode-cn.com/problems/best-time-to-buy-and-sell-stock/</a></p>\n\n<p>&nbsp;</p>\n",
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