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leetcode-problemset/leetcode-cn/originData/find-the-number-of-good-pairs-i.json
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{
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"question": {
"questionId": "3446",
"questionFrontendId": "3162",
"categoryTitle": "Algorithms",
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"title": "Find the Number of Good Pairs I",
"titleSlug": "find-the-number-of-good-pairs-i",
"content": "<p>You are given 2 integer arrays <code>nums1</code> and <code>nums2</code> of lengths <code>n</code> and <code>m</code> respectively. You are also given a <strong>positive</strong> integer <code>k</code>.</p>\n\n<p>A pair <code>(i, j)</code> is called <strong>good</strong> if <code>nums1[i]</code> is divisible by <code>nums2[j] * k</code> (<code>0 &lt;= i &lt;= n - 1</code>, <code>0 &lt;= j &lt;= m - 1</code>).</p>\n\n<p>Return the total number of <strong>good</strong> pairs.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums1 = [1,3,4], nums2 = [1,3,4], k = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">5</span></p>\n\n<p><strong>Explanation:</strong></p>\nThe 5 good pairs are <code>(0, 0)</code>, <code>(1, 0)</code>, <code>(1, 1)</code>, <code>(2, 0)</code>, and <code>(2, 2)</code>.</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums1 = [1,2,4,12], nums2 = [2,4], k = 3</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The 2 good pairs are <code>(3, 0)</code> and <code>(3, 1)</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n, m &lt;= 50</code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[j] &lt;= 50</code></li>\n\t<li><code>1 &lt;= k &lt;= 50</code></li>\n</ul>\n",
"translatedTitle": "优质数对的总数 I",
"translatedContent": "<p>给你两个整数数组 <code>nums1</code> 和 <code>nums2</code>,长度分别为 <code>n</code> 和 <code>m</code>。同时给你一个<strong>正整数</strong> <code>k</code>。</p>\n\n<p>如果 <code>nums1[i]</code> 可以被 <code>nums2[j] * k</code> 整除,则称数对 <code>(i, j)</code> 为 <strong>优质数对</strong><code>0 &lt;= i &lt;= n - 1</code>, <code>0 &lt;= j &lt;= m - 1</code>)。</p>\n\n<p>返回<strong> 优质数对 </strong>的总数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong><span class=\"example-io\">nums1 = [1,3,4], nums2 = [1,3,4], k = 1</span></p>\n\n<p><strong>输出:</strong><span class=\"example-io\">5</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>5个优质数对分别是 <code>(0, 0)</code>, <code>(1, 0)</code>, <code>(1, 1)</code>, <code>(2, 0)</code>, 和 <code>(2, 2)</code>。</p>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong><span class=\"example-io\">nums1 = [1,2,4,12], nums2 = [2,4], k = 3</span></p>\n\n<p><strong>输出:</strong><span class=\"example-io\">2</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>2个优质数对分别是 <code>(3, 0)</code> 和 <code>(3, 1)</code>。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n, m &lt;= 50</code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[j] &lt;= 50</code></li>\n\t<li><code>1 &lt;= k &lt;= 50</code></li>\n</ul>\n",
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