leetcode-problemset/leetcode-cn/originData/find-substring-with-given-hash-value.json

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        "question": {
            "questionId": "2275",
            "questionFrontendId": "2156",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1235011,
            "title": "Find Substring With Given Hash Value",
            "titleSlug": "find-substring-with-given-hash-value",
            "content": "<p>The hash of a <strong>0-indexed</strong> string <code>s</code> of length <code>k</code>, given integers <code>p</code> and <code>m</code>, is computed using the following function:</p>\n\n<ul>\n\t<li><code>hash(s, p, m) = (val(s[0]) * p<sup>0</sup> + val(s[1]) * p<sup>1</sup> + ... + val(s[k-1]) * p<sup>k-1</sup>) mod m</code>.</li>\n</ul>\n\n<p>Where <code>val(s[i])</code> represents the index of <code>s[i]</code> in the alphabet from <code>val(&#39;a&#39;) = 1</code> to <code>val(&#39;z&#39;) = 26</code>.</p>\n\n<p>You are given a string <code>s</code> and the integers <code>power</code>, <code>modulo</code>, <code>k</code>, and <code>hashValue.</code> Return <code>sub</code>,<em> the <strong>first</strong> <strong>substring</strong> of </em><code>s</code><em> of length </em><code>k</code><em> such that </em><code>hash(sub, power, modulo) == hashValue</code>.</p>\n\n<p>The test cases will be generated such that an answer always <strong>exists</strong>.</p>\n\n<p>A <b>substring</b> is a contiguous non-empty sequence of characters within a string.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;leetcode&quot;, power = 7, modulo = 20, k = 2, hashValue = 0\n<strong>Output:</strong> &quot;ee&quot;\n<strong>Explanation:</strong> The hash of &quot;ee&quot; can be computed to be hash(&quot;ee&quot;, 7, 20) = (5 * 1 + 5 * 7) mod 20 = 40 mod 20 = 0. \n&quot;ee&quot; is the first substring of length 2 with hashValue 0. Hence, we return &quot;ee&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;fbxzaad&quot;, power = 31, modulo = 100, k = 3, hashValue = 32\n<strong>Output:</strong> &quot;fbx&quot;\n<strong>Explanation:</strong> The hash of &quot;fbx&quot; can be computed to be hash(&quot;fbx&quot;, 31, 100) = (6 * 1 + 2 * 31 + 24 * 31<sup>2</sup>) mod 100 = 23132 mod 100 = 32. \nThe hash of &quot;bxz&quot; can be computed to be hash(&quot;bxz&quot;, 31, 100) = (2 * 1 + 24 * 31 + 26 * 31<sup>2</sup>) mod 100 = 25732 mod 100 = 32. \n&quot;fbx&quot; is the first substring of length 3 with hashValue 32. Hence, we return &quot;fbx&quot;.\nNote that &quot;bxz&quot; also has a hash of 32 but it appears later than &quot;fbx&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= s.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= power, modulo &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= hashValue &lt; modulo</code></li>\n\t<li><code>s</code> consists of lowercase English letters only.</li>\n\t<li>The test cases are generated such that an answer always <strong>exists</strong>.</li>\n</ul>\n",
            "translatedTitle": "查找给定哈希值的子串",
            "translatedContent": "<p>给定整数 <code>p</code>&nbsp;和 <code>m</code>&nbsp;，一个长度为 <code>k</code>&nbsp;且下标从 <strong>0</strong>&nbsp;开始的字符串&nbsp;<code>s</code>&nbsp;的哈希值按照如下函数计算：</p>\n\n<ul>\n\t<li><code>hash(s, p, m) = (val(s[0]) * p<sup>0</sup> + val(s[1]) * p<sup>1</sup> + ... + val(s[k-1]) * p<sup>k-1</sup>) mod m</code>.</li>\n</ul>\n\n<p>其中&nbsp;<code>val(s[i])</code>&nbsp;表示&nbsp;<code>s[i]</code>&nbsp;在字母表中的下标，从&nbsp;<code>val('a') = 1</code> 到&nbsp;<code>val('z') = 26</code>&nbsp;。</p>\n\n<p>给你一个字符串&nbsp;<code>s</code>&nbsp;和整数&nbsp;<code>power</code>，<code>modulo</code>，<code>k</code>&nbsp;和&nbsp;<code>hashValue</code>&nbsp;。请你返回 <code>s</code>&nbsp;中 <strong>第一个</strong> 长度为 <code>k</code>&nbsp;的 <strong>子串</strong>&nbsp;<code>sub</code>&nbsp;，满足<em>&nbsp;</em><code>hash(sub, power, modulo) == hashValue</code>&nbsp;。</p>\n\n<p>测试数据保证一定 <strong>存在</strong>&nbsp;至少一个这样的子串。</p>\n\n<p><strong>子串</strong> 定义为一个字符串中连续非空字符组成的序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>s = \"leetcode\", power = 7, modulo = 20, k = 2, hashValue = 0\n<strong>输出：</strong>\"ee\"\n<strong>解释：</strong>\"ee\" 的哈希值为 hash(\"ee\", 7, 20) = (5 * 1 + 5 * 7) mod 20 = 40 mod 20 = 0 。\n\"ee\" 是长度为 2 的第一个哈希值为 0 的子串，所以我们返回 \"ee\" 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>s = \"fbxzaad\", power = 31, modulo = 100, k = 3, hashValue = 32\n<b>输出：</b>\"fbx\"\n<b>解释：</b>\"fbx\" 的哈希值为 hash(\"fbx\", 31, 100) = (6 * 1 + 2 * 31 + 24 * 31<sup>2</sup>) mod 100 = 23132 mod 100 = 32 。\n\"bxz\" 的哈希值为 hash(\"bxz\", 31, 100) = (2 * 1 + 24 * 31 + 26 * 31<sup>2</sup>) mod 100 = 25732 mod 100 = 32 。\n\"fbx\" 是长度为 3 的第一个哈希值为 32 的子串，所以我们返回 \"fbx\" 。\n注意，\"bxz\" 的哈希值也为 32 ，但是它在字符串中比 \"fbx\" 更晚出现。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= s.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= power, modulo &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= hashValue &lt; modulo</code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n\t<li>测试数据保证一定 <strong>存在</strong>&nbsp;满足条件的子串。</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    string subStrHash(string s, int power, int modulo, int k, int hashValue) {\n        \n    }\n};",
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                "How can we update the hash value efficiently while iterating instead of recalculating it each time?",
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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