leetcode-problemset/leetcode-cn/originData/find-occurrences-of-an-element-in-an-array.json

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        "question": {
            "questionId": "3420",
            "questionFrontendId": "3159",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2790208,
            "title": "Find Occurrences of an Element in an Array",
            "titleSlug": "find-occurrences-of-an-element-in-an-array",
            "content": "<p>You are given an integer array <code>nums</code>, an integer array <code>queries</code>, and an integer <code>x</code>.</p>\n\n<p>For each <code>queries[i]</code>, you need to find the index of the <code>queries[i]<sup>th</sup></code> occurrence of <code>x</code> in the <code>nums</code> array. If there are fewer than <code>queries[i]</code> occurrences of <code>x</code>, the answer should be -1 for that query.</p>\n\n<p>Return an integer array <code>answer</code> containing the answers to all queries.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,3,1,7], queries = [1,3,2,4], x = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[0,-1,2,-1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>For the 1<sup>st</sup> query, the first occurrence of 1 is at index 0.</li>\n\t<li>For the 2<sup>nd</sup> query, there are only two occurrences of 1 in <code>nums</code>, so the answer is -1.</li>\n\t<li>For the 3<sup>rd</sup> query, the second occurrence of 1 is at index 2.</li>\n\t<li>For the 4<sup>th</sup> query, there are only two occurrences of 1 in <code>nums</code>, so the answer is -1.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,3], queries = [10], x = 5</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[-1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>For the 1<sup>st</sup> query, 5 doesn&#39;t exist in <code>nums</code>, so the answer is -1.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= queries[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], x &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "查询数组中元素的出现位置",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code>&nbsp;，一个整数数组&nbsp;<code>queries</code>&nbsp;和一个整数&nbsp;<code>x</code>&nbsp;。</p>\n\n<p>对于每个查询&nbsp;<code>queries[i]</code>&nbsp;，你需要找到&nbsp;<code>nums</code>&nbsp;中第&nbsp;<code>queries[i]</code>&nbsp;个&nbsp;<code>x</code>&nbsp;的位置，并返回它的下标。如果数组中&nbsp;<code>x</code>&nbsp;的出现次数少于&nbsp;<code>queries[i]</code>&nbsp;，该查询的答案为 -1 。</p>\n\n<p>请你返回一个整数数组&nbsp;<code>answer</code>&nbsp;，包含所有查询的答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [1,3,1,7], queries = [1,3,2,4], x = 1</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[0,-1,2,-1]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>第 1 个查询，第一个 1 出现在下标 0 处。</li>\n\t<li>第 2 个查询，<code>nums</code>&nbsp;中只有两个 1 ，所以答案为 -1 。</li>\n\t<li>第 3 个查询，第二个 1 出现在下标 2 处。</li>\n\t<li>第 4 个查询，<code>nums</code>&nbsp;中只有两个 1 ，所以答案为 -1 。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [1,2,3], queries = [10], x = 5</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[-1]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>第 1 个查询，<code>nums</code>&nbsp;中没有 5 ，所以答案为 -1 。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= queries[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], x &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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                    "name": "Array",
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                    "translatedName": "数组",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<int> occurrencesOfElement(vector<int>& nums, vector<int>& queries, int x) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def occurrencesOfElement(self, nums, queries, x):\n        \"\"\"\n        :type nums: List[int]\n        :type queries: List[int]\n        :type x: int\n        :rtype: List[int]\n        \"\"\"",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* occurrencesOfElement(int* nums, int numsSize, int* queries, int queriesSize, int x, int* returnSize) {\n    \n}",
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                    "code": "public class Solution {\n    public int[] OccurrencesOfElement(int[] nums, int[] queries, int x) {\n\n    }\n}",
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                    "code": "/**\n * @param {number[]} nums\n * @param {number[]} queries\n * @param {number} x\n * @return {number[]}\n */\nvar occurrencesOfElement = function(nums, queries, x) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @param Integer[] $queries\n     * @param Integer $x\n     * @return Integer[]\n     */\n    function occurrencesOfElement($nums, $queries, $x) {\n\n    }\n}",
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                    "code": "object Solution {\n    def occurrencesOfElement(nums: Array[Int], queries: Array[Int], x: Int): Array[Int] = {\n        \n    }\n}",
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