leetcode-problemset/leetcode-cn/originData/find-majority-element-lcci.json

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        "question": {
            "questionId": "1000038",
            "questionFrontendId": "面试题 17.10",
            "categoryTitle": "LCCI",
            "boundTopicId": 94592,
            "title": "Find Majority Element LCCI",
            "titleSlug": "find-majority-element-lcci",
            "content": "<p>A majority element is an element that makes up more than half of the items in an array. Given a&nbsp;integers array, find the majority element. If there is no majority element, return -1. Do this in O(N) time and O(1) space.</p>\r\n\r\n<p><strong>Example 1: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>[1,2,5,9,5,9,5,5,5]\r\n<strong>Output: </strong>5</pre>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><strong>Example 2: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>[3,2]\r\n<strong>Output: </strong>-1</pre>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><strong>Example 3: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>[2,2,1,1,1,2,2]\r\n<strong>Output: </strong>2\r\n</pre>\r\n",
            "translatedTitle": "主要元素",
            "translatedContent": "<p>数组中占比超过一半的元素称之为主要元素。给你一个<strong> 整数 </strong>数组，找出其中的主要元素。若没有，返回 <code>-1</code> 。请设计时间复杂度为 <code>O(N)</code> 、空间复杂度为 <code>O(1)</code> 的解决方案。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>[1,2,5,9,5,9,5,5,5]\n<strong>输出：</strong>5</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>[3,2]\n<strong>输出：</strong>-1</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>[2,2,1,1,1,2,2]\n<strong>输出：</strong>2</pre>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int majorityElement(vector<int>& nums) {\n\n    }\n};",
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                    "code": "class Solution {\n    public int majorityElement(int[] nums) {\n\n    }\n}",
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                    "code": "class Solution(object):\n    def majorityElement(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: int\n        \"\"\"",
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                    "code": "\n\nint majorityElement(int* nums, int numsSize){\n\n}\n",
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                    "code": "public class Solution {\n    public int MajorityElement(int[] nums) {\n\n    }\n}",
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                    "code": "/**\n * @param {number[]} nums\n * @return {number}\n */\nvar majorityElement = function(nums) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @return Integer\n     */\n    function majorityElement($nums) {\n\n    }\n}",
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                    "code": "class Solution {\n    func majorityElement(_ nums: [Int]) -> Int {\n\n    }\n}",
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                    "lang": "Go",
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                    "code": "func majorityElement(nums []int) int {\n\n}",
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                    "code": "# @param {Integer[]} nums\n# @return {Integer}\ndef majority_element(nums)\n\nend",
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                    "code": "-spec majority_element(Nums :: [integer()]) -> integer().\nmajority_element(Nums) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec majority_element(nums :: [integer]) :: integer\n  def majority_element(nums) do\n\n  end\nend",
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            "hints": [
                "从蛮力解法开始。你能检查一下每个值是否为主要元素吗?",
                "考虑蛮力解法。我们选择一个元素，然后通过计算匹配和非匹配元素的数量来验证它是否是主要元素。假设对于第一个元素，前几次检查显示 7 个不匹配的元素和 3 个匹配的元素。有必要继续检查这个元素吗?",
                "主要元素一开始看起来并不一定像主要元素。例如，有可能主要元素出现在数组的第一个元素中，然后在接下来的 8 个元素中都不再出现。但是，在这些情况下，主要元素将在数组的后面出现(实际上，在数组的后面会出现很多次)。当某个元素看起来“不太像”主要元素时，继续检查它并不一定很重要。",
                "还要注意，主要元素对于某些子数组也必须是主要元素，而且子数组不能拥有多个主要元素。",
                "试试这个:给定一个元素，开始检查它是否是一个子数组的开始，同时对于这个子数组，该元素是它的主要元素。一旦它变得“不太可能”(出现的次数少于一半)，就开始检查下一个元素(子数组之后的元素)。"
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