leetcode-problemset/leetcode-cn/originData/final-array-state-after-k-multiplication-operations-ii.json

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        "question": {
            "questionId": "3556",
            "questionFrontendId": "3266",
            "categoryTitle": "Algorithms",
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            "title": "Final Array State After K Multiplication Operations II",
            "titleSlug": "final-array-state-after-k-multiplication-operations-ii",
            "content": "<p>You are given an integer array <code>nums</code>, an integer <code>k</code>, and an integer <code>multiplier</code>.</p>\n\n<p>You need to perform <code>k</code> operations on <code>nums</code>. In each operation:</p>\n\n<ul>\n\t<li>Find the <strong>minimum</strong> value <code>x</code> in <code>nums</code>. If there are multiple occurrences of the minimum value, select the one that appears <strong>first</strong>.</li>\n\t<li>Replace the selected minimum value <code>x</code> with <code>x * multiplier</code>.</li>\n</ul>\n\n<p>After the <code>k</code> operations, apply <strong>modulo</strong> <code>10<sup>9</sup> + 7</code> to every value in <code>nums</code>.</p>\n\n<p>Return an integer array denoting the <em>final state</em> of <code>nums</code> after performing all <code>k</code> operations and then applying the modulo.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,1,3,5,6], k = 5, multiplier = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[8,4,6,5,6]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<table>\n\t<tbody>\n\t\t<tr>\n\t\t\t<th>Operation</th>\n\t\t\t<th>Result</th>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After operation 1</td>\n\t\t\t<td>[2, 2, 3, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After operation 2</td>\n\t\t\t<td>[4, 2, 3, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After operation 3</td>\n\t\t\t<td>[4, 4, 3, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After operation 4</td>\n\t\t\t<td>[4, 4, 6, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After operation 5</td>\n\t\t\t<td>[8, 4, 6, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After applying modulo</td>\n\t\t\t<td>[8, 4, 6, 5, 6]</td>\n\t\t</tr>\n\t</tbody>\n</table>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [100000,2000], k = 2, multiplier = 1000000</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[999999307,999999993]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<table>\n\t<tbody>\n\t\t<tr>\n\t\t\t<th>Operation</th>\n\t\t\t<th>Result</th>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After operation 1</td>\n\t\t\t<td>[100000, 2000000000]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After operation 2</td>\n\t\t\t<td>[100000000000, 2000000000]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>After applying modulo</td>\n\t\t\t<td>[999999307, 999999993]</td>\n\t\t</tr>\n\t</tbody>\n</table>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= multiplier &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
            "translatedTitle": "K 次乘运算后的最终数组 II",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code>&nbsp;，一个整数&nbsp;<code>k</code>&nbsp;&nbsp;和一个整数&nbsp;<code>multiplier</code>&nbsp;。</p>\n\n<p>你需要对 <code>nums</code>&nbsp;执行 <code>k</code>&nbsp;次操作，每次操作中：</p>\n\n<ul>\n\t<li>找到 <code>nums</code>&nbsp;中的 <strong>最小</strong>&nbsp;值&nbsp;<code>x</code>&nbsp;，如果存在多个最小值，选择最 <strong>前面</strong>&nbsp;的一个。</li>\n\t<li>将 <code>x</code>&nbsp;替换为&nbsp;<code>x * multiplier</code>&nbsp;。</li>\n</ul>\n\n<p><code>k</code>&nbsp;次操作以后，你需要将 <code>nums</code>&nbsp;中每一个数值对&nbsp;<code>10<sup>9</sup> + 7</code>&nbsp;取余。</p>\n\n<p>请你返回执行完 <code>k</code>&nbsp;次乘运算以及取余运算之后，最终的 <code>nums</code>&nbsp;数组。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [2,1,3,5,6], k = 5, multiplier = 2</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[8,4,6,5,6]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<table>\n\t<tbody>\n\t\t<tr>\n\t\t\t<th>操作</th>\n\t\t\t<th>结果</th>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>1 次操作后</td>\n\t\t\t<td>[2, 2, 3, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>2 次操作后</td>\n\t\t\t<td>[4, 2, 3, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>3 次操作后</td>\n\t\t\t<td>[4, 4, 3, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>4 次操作后</td>\n\t\t\t<td>[4, 4, 6, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>5 次操作后</td>\n\t\t\t<td>[8, 4, 6, 5, 6]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>取余操作后</td>\n\t\t\t<td>[8, 4, 6, 5, 6]</td>\n\t\t</tr>\n\t</tbody>\n</table>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [100000,2000], k = 2, multiplier = 1000000</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[999999307,999999993]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<table>\n\t<tbody>\n\t\t<tr>\n\t\t\t<th>操作</th>\n\t\t\t<th>结果</th>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>1 次操作后</td>\n\t\t\t<td>[100000, 2000000000]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>2 次操作后</td>\n\t\t\t<td>[100000000000, 2000000000]</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>取余操作后</td>\n\t\t\t<td>[999999307, 999999993]</td>\n\t\t</tr>\n\t</tbody>\n</table>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= multiplier &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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