mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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126 lines
14 KiB
JSON
126 lines
14 KiB
JSON
{
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"questionId": "100305",
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"questionFrontendId": "LCR 155",
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"categoryTitle": "Algorithms",
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"boundTopicId": 87118,
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"title": "将二叉搜索树转化为排序的双向链表",
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"titleSlug": "er-cha-sou-suo-shu-yu-shuang-xiang-lian-biao-lcof",
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"content": "English description is not available for the problem. Please switch to Chinese.",
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"translatedTitle": "将二叉搜索树转化为排序的双向链表",
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"translatedContent": "<p>将一个 <strong>二叉搜索树</strong> 就地转化为一个 <strong>已排序的双向循环链表</strong> 。</p>\n\n<p>对于双向循环列表,你可以将左右孩子指针作为双向循环链表的前驱和后继指针,第一个节点的前驱是最后一个节点,最后一个节点的后继是第一个节点。</p>\n\n<p>特别地,我们希望可以 <strong>就地</strong> 完成转换操作。当转化完成以后,树中节点的左指针需要指向前驱,树中节点的右指针需要指向后继。还需要返回链表中最小元素的指针。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [4,2,5,1,3] \n\n<img src=\"https://assets.leetcode.com/uploads/2018/10/12/bstdllreturndll.png\" />\n<strong>输出:</strong>[1,2,3,4,5]\n\n<strong>解释:</strong>下图显示了转化后的二叉搜索树,实线表示后继关系,虚线表示前驱关系。\n<img src=\"https://assets.leetcode.com/uploads/2018/10/12/bstdllreturnbst.png\" />\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [2,1,3]\n<strong>输出:</strong>[1,2,3]\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>root = []\n<strong>输出:</strong>[]\n<strong>解释:</strong>输入是空树,所以输出也是空链表。\n</pre>\n\n<p><strong>示例 4:</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [1]\n<strong>输出:</strong>[1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>-1000 <= Node.val <= 1000</code></li>\n\t<li><code>Node.left.val < Node.val < Node.right.val</code></li>\n\t<li><code>Node.val</code> 的所有值都是独一无二的</li>\n\t<li><code>0 <= Number of Nodes <= 2000</code></li>\n</ul>\n\n<p>注意:本题与主站 426 题相同:<a href=\"https://leetcode-cn.com/problems/convert-binary-search-tree-to-sorted-doubly-linked-list/\" rel=\"noopener noreferrer\" target=\"_blank\">https://leetcode-cn.com/problems/convert-binary-search-tree-to-sorted-doubly-linked-list/</a></p>\n",
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"difficulty": "Medium",
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"similarQuestions": "[]",
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"langToValidPlayground": "{\"cpp\": false, \"java\": false, \"python\": false, \"python3\": false, \"mysql\": false, \"mssql\": false, \"oraclesql\": false, \"c\": false, \"csharp\": false, \"javascript\": false, \"typescript\": false, \"bash\": false, \"php\": false, \"swift\": false, \"kotlin\": false, \"dart\": false, \"golang\": false, \"ruby\": false, \"scala\": false, \"html\": false, \"pythonml\": false, \"rust\": false, \"racket\": false, \"erlang\": false, \"elixir\": false, \"pythondata\": false, \"react\": false, \"vanillajs\": false, \"postgresql\": false}",
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"topicTags": [
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{
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"name": "Stack",
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"slug": "stack",
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"translatedName": "栈",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Tree",
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"slug": "tree",
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"translatedName": "树",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Depth-First Search",
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"slug": "depth-first-search",
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"translatedName": "深度优先搜索",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Binary Search Tree",
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"slug": "binary-search-tree",
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"translatedName": "二叉搜索树",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Linked List",
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"slug": "linked-list",
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"translatedName": "链表",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Binary Tree",
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"slug": "binary-tree",
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"translatedName": "二叉树",
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"__typename": "TopicTagNode"
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},
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{
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"name": "Doubly-Linked List",
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"slug": "doubly-linked-list",
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"translatedName": "双向链表",
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"__typename": "TopicTagNode"
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