leetcode-problemset/leetcode-cn/originData/double-modular-exponentiation.json

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            "title": "Double Modular Exponentiation",
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            "content": "<p>You are given a <strong>0-indexed</strong> 2D array <code>variables</code> where <code>variables[i] = [a<sub>i</sub>, b<sub>i</sub>, c<sub>i,</sub> m<sub>i</sub>]</code>, and an integer <code>target</code>.</p>\n\n<p>An index <code>i</code> is <strong>good</strong> if the following formula holds:</p>\n\n<ul>\n\t<li><code>0 &lt;= i &lt; variables.length</code></li>\n\t<li><code>((a<sub>i</sub><sup>b<sub>i</sub></sup> % 10)<sup>c<sub>i</sub></sup>) % m<sub>i</sub> == target</code></li>\n</ul>\n\n<p>Return <em>an array consisting of <strong>good</strong> indices in <strong>any order</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> variables = [[2,3,3,10],[3,3,3,1],[6,1,1,4]], target = 2\n<strong>Output:</strong> [0,2]\n<strong>Explanation:</strong> For each index i in the variables array:\n1) For the index 0, variables[0] = [2,3,3,10], (2<sup>3</sup> % 10)<sup>3</sup> % 10 = 2.\n2) For the index 1, variables[1] = [3,3,3,1], (3<sup>3</sup> % 10)<sup>3</sup> % 1 = 0.\n3) For the index 2, variables[2] = [6,1,1,4], (6<sup>1</sup> % 10)<sup>1</sup> % 4 = 2.\nTherefore we return [0,2] as the answer.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> variables = [[39,3,1000,1000]], target = 17\n<strong>Output:</strong> []\n<strong>Explanation:</strong> For each index i in the variables array:\n1) For the index 0, variables[0] = [39,3,1000,1000], (39<sup>3</sup> % 10)<sup>1000</sup> % 1000 = 1.\nTherefore we return [] as the answer.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= variables.length &lt;= 100</code></li>\n\t<li><code>variables[i] == [a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, m<sub>i</sub>]</code></li>\n\t<li><code>1 &lt;= a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, m<sub>i</sub> &lt;= 10<sup>3</sup></code></li>\n\t<li><code><font face=\"monospace\">0 &lt;= target &lt;= 10<sup>3</sup></font></code></li>\n</ul>\n",
            "translatedTitle": "双模幂运算",
            "translatedContent": "<p>给你一个下标从 <strong>0 </strong>开始的二维数组 <code>variables</code> ，其中 <code>variables[i] = [a<sub>i</sub>, b<sub>i</sub>, c<sub>i,</sub> m<sub>i</sub>]</code>，以及一个整数 <code>target</code> 。</p>\n\n<p>如果满足以下公式，则下标 <code>i</code> 是 <strong>好下标</strong>：</p>\n\n<ul>\n\t<li><code>0 &lt;= i &lt; variables.length</code></li>\n\t<li><code>((a<sub>i</sub><sup>b<sub>i</sub></sup> % 10)<sup>c<sub>i</sub></sup>) % m<sub>i</sub> == target</code></li>\n</ul>\n\n<p>返回一个由<strong> 好下标 </strong>组成的数组，<strong>顺序不限</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>variables = [[2,3,3,10],[3,3,3,1],[6,1,1,4]], target = 2\n<strong>输出：</strong>[0,2]\n<strong>解释：</strong>对于 variables 数组中的每个下标 i ：\n1) 对于下标 0 ，variables[0] = [2,3,3,10] ，(2<sup>3</sup> % 10)<sup>3</sup> % 10 = 2 。\n2) 对于下标 1 ，variables[1] = [3,3,3,1] ，(3<sup>3</sup> % 10)<sup>3</sup> % 1 = 0 。\n3) 对于下标 2 ，variables[2] = [6,1,1,4] ，(6<sup>1</sup> % 10)<sup>1</sup> % 4 = 2 。\n因此，返回 [0,2] 作为答案。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>variables = [[39,3,1000,1000]], target = 17\n<strong>输出：</strong>[]\n<strong>解释：</strong>对于 variables 数组中的每个下标 i ：\n1) 对于下标 0 ，variables[0] = [39,3,1000,1000] ，(39<sup>3</sup> % 10)<sup>1000</sup> % 1000 = 1 。\n因此，返回 [] 作为答案。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= variables.length &lt;= 100</code></li>\n\t<li><code>variables[i] == [a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, m<sub>i</sub>]</code></li>\n\t<li><code>1 &lt;= a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, m<sub>i</sub> &lt;= 10<sup>3</sup></code></li>\n\t<li><code><font face=\"monospace\">0 &lt;= target &lt;= 10<sup>3</sup></font></code></li>\n</ul>\n",
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