leetcode-problemset/leetcode-cn/originData/divide-a-string-into-groups-of-size-k.json

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        "question": {
            "questionId": "2260",
            "questionFrontendId": "2138",
            "categoryTitle": "Algorithms",
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            "title": "Divide a String Into Groups of Size k",
            "titleSlug": "divide-a-string-into-groups-of-size-k",
            "content": "<p>A string <code>s</code> can be partitioned into groups of size <code>k</code> using the following procedure:</p>\n\n<ul>\n\t<li>The first group consists of the first <code>k</code> characters of the string, the second group consists of the next <code>k</code> characters of the string, and so on. Each character can be a part of <strong>exactly one</strong> group.</li>\n\t<li>For the last group, if the string <strong>does not</strong> have <code>k</code> characters remaining, a character <code>fill</code> is used to complete the group.</li>\n</ul>\n\n<p>Note that the partition is done so that after removing the <code>fill</code> character from the last group (if it exists) and concatenating all the groups in order, the resultant string should be <code>s</code>.</p>\n\n<p>Given the string <code>s</code>, the size of each group <code>k</code> and the character <code>fill</code>, return <em>a string array denoting the <strong>composition of every group</strong> </em><code>s</code><em> has been divided into, using the above procedure</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcdefghi&quot;, k = 3, fill = &quot;x&quot;\n<strong>Output:</strong> [&quot;abc&quot;,&quot;def&quot;,&quot;ghi&quot;]\n<strong>Explanation:</strong>\nThe first 3 characters &quot;abc&quot; form the first group.\nThe next 3 characters &quot;def&quot; form the second group.\nThe last 3 characters &quot;ghi&quot; form the third group.\nSince all groups can be completely filled by characters from the string, we do not need to use fill.\nThus, the groups formed are &quot;abc&quot;, &quot;def&quot;, and &quot;ghi&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcdefghij&quot;, k = 3, fill = &quot;x&quot;\n<strong>Output:</strong> [&quot;abc&quot;,&quot;def&quot;,&quot;ghi&quot;,&quot;jxx&quot;]\n<strong>Explanation:</strong>\nSimilar to the previous example, we are forming the first three groups &quot;abc&quot;, &quot;def&quot;, and &quot;ghi&quot;.\nFor the last group, we can only use the character &#39;j&#39; from the string. To complete this group, we add &#39;x&#39; twice.\nThus, the 4 groups formed are &quot;abc&quot;, &quot;def&quot;, &quot;ghi&quot;, and &quot;jxx&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s</code> consists of lowercase English letters only.</li>\n\t<li><code>1 &lt;= k &lt;= 100</code></li>\n\t<li><code>fill</code> is a lowercase English letter.</li>\n</ul>\n",
            "translatedTitle": "将字符串拆分为若干长度为 k 的组",
            "translatedContent": "<p>字符串 <code>s</code> 可以按下述步骤划分为若干长度为 <code>k</code> 的组：</p>\n\n<ul>\n\t<li>第一组由字符串中的前 <code>k</code> 个字符组成，第二组由接下来的 <code>k</code> 个字符串组成，依此类推。每个字符都能够成为 <strong>某一个</strong> 组的一部分。</li>\n\t<li>对于最后一组，如果字符串剩下的字符 <strong>不足</strong> <code>k</code> 个，需使用字符 <code>fill</code> 来补全这一组字符。</li>\n</ul>\n\n<p>注意，在去除最后一个组的填充字符 <code>fill</code>（如果存在的话）并按顺序连接所有的组后，所得到的字符串应该是 <code>s</code> 。</p>\n\n<p>给你一个字符串 <code>s</code> ，以及每组的长度 <code>k</code> 和一个用于填充的字符 <code>fill</code> ，按上述步骤处理之后，返回一个字符串数组，该数组表示 <code>s</code> 分组后 <strong>每个组的组成情况</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>s = \"abcdefghi\", k = 3, fill = \"x\"\n<strong>输出：</strong>[\"abc\",\"def\",\"ghi\"]\n<strong>解释：</strong>\n前 3 个字符是 \"abc\" ，形成第一组。\n接下来 3 个字符是 \"def\" ，形成第二组。\n最后 3 个字符是 \"ghi\" ，形成第三组。\n由于所有组都可以由字符串中的字符完全填充，所以不需要使用填充字符。\n因此，形成 3 组，分别是 \"abc\"、\"def\" 和 \"ghi\" 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>s = \"abcdefghij\", k = 3, fill = \"x\"\n<strong>输出：</strong>[\"abc\",\"def\",\"ghi\",\"jxx\"]\n<strong>解释：</strong>\n与前一个例子类似，形成前三组 \"abc\"、\"def\" 和 \"ghi\" 。\n对于最后一组，字符串中仅剩下字符 'j' 可以用。为了补全这一组，使用填充字符 'x' 两次。\n因此，形成 4 组，分别是 \"abc\"、\"def\"、\"ghi\" 和 \"jxx\" 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s</code> 仅由小写英文字母组成</li>\n\t<li><code>1 &lt;= k &lt;= 100</code></li>\n\t<li><code>fill</code> 是一个小写英文字母</li>\n</ul>\n",
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                "Using the length of the string and k, can you count the number of groups the string can be divided into?",
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