leetcode-problemset/leetcode-cn/originData/distribute-candies-to-people.json

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            "title": "Distribute Candies to People",
            "titleSlug": "distribute-candies-to-people",
            "content": "<p>We distribute some&nbsp;number of <code>candies</code>, to a row of <strong><code>n =&nbsp;num_people</code></strong>&nbsp;people in the following way:</p>\n\n<p>We then give 1 candy to the first person, 2 candies to the second person, and so on until we give <code>n</code>&nbsp;candies to the last person.</p>\n\n<p>Then, we go back to the start of the row, giving <code>n&nbsp;+ 1</code> candies to the first person, <code>n&nbsp;+ 2</code> candies to the second person, and so on until we give <code>2 * n</code>&nbsp;candies to the last person.</p>\n\n<p>This process repeats (with us giving one more candy each time, and moving to the start of the row after we reach the end) until we run out of candies.&nbsp; The last person will receive all of our remaining candies (not necessarily one more than the previous gift).</p>\n\n<p>Return an array (of length <code>num_people</code>&nbsp;and sum <code>candies</code>) that represents the final distribution of candies.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> candies = 7, num_people = 4\n<strong>Output:</strong> [1,2,3,1]\n<strong>Explanation:</strong>\nOn the first turn, ans[0] += 1, and the array is [1,0,0,0].\nOn the second turn, ans[1] += 2, and the array is [1,2,0,0].\nOn the third turn, ans[2] += 3, and the array is [1,2,3,0].\nOn the fourth turn, ans[3] += 1 (because there is only one candy left), and the final array is [1,2,3,1].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> candies = 10, num_people = 3\n<strong>Output:</strong> [5,2,3]\n<strong>Explanation: </strong>\nOn the first turn, ans[0] += 1, and the array is [1,0,0].\nOn the second turn, ans[1] += 2, and the array is [1,2,0].\nOn the third turn, ans[2] += 3, and the array is [1,2,3].\nOn the fourth turn, ans[0] += 4, and the final array is [5,2,3].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>1 &lt;= candies &lt;= 10^9</li>\n\t<li>1 &lt;= num_people &lt;= 1000</li>\n</ul>\n",
            "translatedTitle": "分糖果 II",
            "translatedContent": "<p>排排坐，分糖果。</p>\n\n<p>我们买了一些糖果 <code>candies</code>，打算把它们分给排好队的 <strong><code>n = num_people</code></strong> 个小朋友。</p>\n\n<p>给第一个小朋友 1 颗糖果，第二个小朋友 2 颗，依此类推，直到给最后一个小朋友 <code>n</code>&nbsp;颗糖果。</p>\n\n<p>然后，我们再回到队伍的起点，给第一个小朋友 <code>n&nbsp;+ 1</code> 颗糖果，第二个小朋友 <code>n&nbsp;+ 2</code> 颗，依此类推，直到给最后一个小朋友 <code>2 * n</code>&nbsp;颗糖果。</p>\n\n<p>重复上述过程（每次都比上一次多给出一颗糖果，当到达队伍终点后再次从队伍起点开始），直到我们分完所有的糖果。注意，就算我们手中的剩下糖果数不够（不比前一次发出的糖果多），这些糖果也会全部发给当前的小朋友。</p>\n\n<p>返回一个长度为 <code>num_people</code>、元素之和为 <code>candies</code> 的数组，以表示糖果的最终分发情况（即 <code>ans[i]</code> 表示第 <code>i</code> 个小朋友分到的糖果数）。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>candies = 7, num_people = 4\n<strong>输出：</strong>[1,2,3,1]\n<strong>解释：</strong>\n第一次，ans[0] += 1，数组变为 [1,0,0,0]。\n第二次，ans[1] += 2，数组变为 [1,2,0,0]。\n第三次，ans[2] += 3，数组变为 [1,2,3,0]。\n第四次，ans[3] += 1（因为此时只剩下 1 颗糖果），最终数组变为 [1,2,3,1]。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>candies = 10, num_people = 3\n<strong>输出：</strong>[5,2,3]\n<strong>解释：</strong>\n第一次，ans[0] += 1，数组变为 [1,0,0]。\n第二次，ans[1] += 2，数组变为 [1,2,0]。\n第三次，ans[2] += 3，数组变为 [1,2,3]。\n第四次，ans[0] += 4，最终数组变为 [5,2,3]。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= candies &lt;= 10^9</code></li>\n\t<li><code>1 &lt;= num_people &lt;= 1000</code></li>\n</ul>\n",
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