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"questionId": "3220",
"questionFrontendId": "2960",
"categoryTitle": "Algorithms",
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"title": "Count Tested Devices After Test Operations",
"titleSlug": "count-tested-devices-after-test-operations",
"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>batteryPercentages</code> having length <code>n</code>, denoting the battery percentages of <code>n</code> <strong>0-indexed</strong> devices.</p>\n\n<p>Your task is to test each device <code>i</code> <strong>in order</strong> from <code>0</code> to <code>n - 1</code>, by performing the following test operations:</p>\n\n<ul>\n\t<li>If <code>batteryPercentages[i]</code> is <strong>greater</strong> than <code>0</code>:\n\n\t<ul>\n\t\t<li><strong>Increment</strong> the count of tested devices.</li>\n\t\t<li><strong>Decrease</strong> the battery percentage of all devices with indices <code>j</code> in the range <code>[i + 1, n - 1]</code> by <code>1</code>, ensuring their battery percentage <strong>never goes below</strong> <code>0</code>, i.e, <code>batteryPercentages[j] = max(0, batteryPercentages[j] - 1)</code>.</li>\n\t\t<li>Move to the next device.</li>\n\t</ul>\n\t</li>\n\t<li>Otherwise, move to the next device without performing any test.</li>\n</ul>\n\n<p>Return <em>an integer denoting the number of devices that will be tested after performing the test operations in order.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> batteryPercentages = [1,1,2,1,3]\n<strong>Output:</strong> 3\n<strong>Explanation: </strong>Performing the test operations in order starting from device 0:\nAt device 0, batteryPercentages[0] &gt; 0, so there is now 1 tested device, and batteryPercentages becomes [1,0,1,0,2].\nAt device 1, batteryPercentages[1] == 0, so we move to the next device without testing.\nAt device 2, batteryPercentages[2] &gt; 0, so there are now 2 tested devices, and batteryPercentages becomes [1,0,1,0,1].\nAt device 3, batteryPercentages[3] == 0, so we move to the next device without testing.\nAt device 4, batteryPercentages[4] &gt; 0, so there are now 3 tested devices, and batteryPercentages stays the same.\nSo, the answer is 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> batteryPercentages = [0,1,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Performing the test operations in order starting from device 0:\nAt device 0, batteryPercentages[0] == 0, so we move to the next device without testing.\nAt device 1, batteryPercentages[1] &gt; 0, so there is now 1 tested device, and batteryPercentages becomes [0,1,1].\nAt device 2, batteryPercentages[2] &gt; 0, so there are now 2 tested devices, and batteryPercentages stays the same.\nSo, the answer is 2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == batteryPercentages.length &lt;= 100 </code></li>\n\t<li><code>0 &lt;= batteryPercentages[i] &lt;= 100</code></li>\n</ul>\n",
"translatedTitle": "统计已测试设备",
"translatedContent": "<p>给你一个长度为 <code>n</code> 、下标从<strong> 0 </strong>开始的整数数组 <code>batteryPercentages</code> ,表示 <code>n</code> 个设备的电池百分比。</p>\n\n<p>你的任务是按照顺序测试每个设备 <code>i</code>,执行以下测试操作:</p>\n\n<ul>\n\t<li>如果 <code>batteryPercentages[i]</code> <strong>大于</strong> <code>0</code>\n\n\t<ul>\n\t\t<li><strong>增加</strong> 已测试设备的计数。</li>\n\t\t<li>将下标在 <code>[i + 1, n - 1]</code> 的所有设备的电池百分比减少 <code>1</code>,确保它们的电池百分比<strong> 不会低于</strong> <code>0</code> ,即 <code>batteryPercentages[j] = max(0, batteryPercentages[j] - 1)</code>。</li>\n\t\t<li>移动到下一个设备。</li>\n\t</ul>\n\t</li>\n\t<li>否则,移动到下一个设备而不执行任何测试。</li>\n</ul>\n\n<p>返回一个整数,表示按顺序执行测试操作后 <strong>已测试设备</strong> 的数量。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>batteryPercentages = [1,1,2,1,3]\n<strong>输出:</strong>3\n<strong>解释:</strong>按顺序从设备 0 开始执行测试操作:\n在设备 0 上batteryPercentages[0] &gt; 0 ,现在有 1 个已测试设备batteryPercentages 变为 [1,0,1,0,2] 。\n在设备 1 上batteryPercentages[1] == 0 ,移动到下一个设备而不进行测试。\n在设备 2 上batteryPercentages[2] &gt; 0 ,现在有 2 个已测试设备batteryPercentages 变为 [1,0,1,0,1] 。\n在设备 3 上batteryPercentages[3] == 0 ,移动到下一个设备而不进行测试。\n在设备 4 上batteryPercentages[4] &gt; 0 ,现在有 3 个已测试设备batteryPercentages 保持不变。\n因此答案是 3 。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>batteryPercentages = [0,1,2]\n<strong>输出:</strong>2\n<strong>解释:</strong>按顺序从设备 0 开始执行测试操作:\n在设备 0 上batteryPercentages[0] == 0 ,移动到下一个设备而不进行测试。\n在设备 1 上batteryPercentages[1] &gt; 0 ,现在有 1 个已测试设备batteryPercentages 变为 [0,1,1] 。\n在设备 2 上batteryPercentages[2] &gt; 0 ,现在有 2 个已测试设备batteryPercentages 保持不变。\n因此答案是 2 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == batteryPercentages.length &lt;= 100 </code></li>\n\t<li><code>0 &lt;= batteryPercentages[i] &lt;= 100</code></li>\n</ul>\n",
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"While going through the devices, you can maintain the number of previously tested devices, and the current device can be tested if <code>batteryPercentages[i]</code> is greater than the number of tested devices."
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