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leetcode-problemset/leetcode-cn/originData/count-substrings-that-can-be-rearranged-to-contain-a-string-i.json
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{
"data": {
"question": {
"questionId": "3573",
"questionFrontendId": "3297",
"categoryTitle": "Algorithms",
"boundTopicId": 2922821,
"title": "Count Substrings That Can Be Rearranged to Contain a String I",
"titleSlug": "count-substrings-that-can-be-rearranged-to-contain-a-string-i",
"content": "<p>You are given two strings <code>word1</code> and <code>word2</code>.</p>\n\n<p>A string <code>x</code> is called <strong>valid</strong> if <code>x</code> can be rearranged to have <code>word2</code> as a <span data-keyword=\"string-prefix\">prefix</span>.</p>\n\n<p>Return the total number of <strong>valid</strong> <span data-keyword=\"substring-nonempty\">substrings</span> of <code>word1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">word1 = &quot;bcca&quot;, word2 = &quot;abc&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The only valid substring is <code>&quot;bcca&quot;</code> which can be rearranged to <code>&quot;abcc&quot;</code> having <code>&quot;abc&quot;</code> as a prefix.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">word1 = &quot;abcabc&quot;, word2 = &quot;abc&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">10</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>All the substrings except substrings of size 1 and size 2 are valid.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">word1 = &quot;abcabc&quot;, word2 = &quot;aaabc&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word1.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= word2.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>word1</code> and <code>word2</code> consist only of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "统计重新排列后包含另一个字符串的子字符串数目 I",
"translatedContent": "<p>给你两个字符串&nbsp;<code>word1</code> 和&nbsp;<code>word2</code>&nbsp;。</p>\n\n<p>如果一个字符串 <code>x</code>&nbsp;重新排列后,<code>word2</code>&nbsp;是重排字符串的&nbsp;<span data-keyword=\"string-prefix\">前缀</span>&nbsp;,那么我们称字符串&nbsp;<code>x</code>&nbsp;是&nbsp;<strong>合法的</strong>&nbsp;。</p>\n\n<p>请你返回 <code>word1</code>&nbsp;中 <strong>合法</strong>&nbsp;<span data-keyword=\"substring-nonempty\">子字符串</span>&nbsp;的数目。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>word1 = \"bcca\", word2 = \"abc\"</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>1</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>唯一合法的子字符串是&nbsp;<code>\"bcca\"</code>&nbsp;,可以重新排列得到&nbsp;<code>\"abcc\"</code>&nbsp;<code>\"abc\"</code>&nbsp;是它的前缀。</p>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>word1 = \"abcabc\", word2 = \"abc\"</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>10</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>除了长度为 1 和 2 的所有子字符串都是合法的。</p>\n</div>\n\n<p><strong class=\"example\">示例 3</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>word1 = \"abcabc\", word2 = \"aaabc\"</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>0</span></p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word1.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= word2.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>word1</code> 和&nbsp;<code>word2</code>&nbsp;都只包含小写英文字母。</li>\n</ul>\n",
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"Store the frequency of each character for all prefixes.",
"Use Binary Search."
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