leetcode-problemset/leetcode-cn/originData/count-beautiful-substrings-ii.json

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        "question": {
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            "title": "Count Beautiful Substrings II",
            "titleSlug": "count-beautiful-substrings-ii",
            "content": "<p>You are given a string <code>s</code> and a positive integer <code>k</code>.</p>\n\n<p>Let <code>vowels</code> and <code>consonants</code> be the number of vowels and consonants in a string.</p>\n\n<p>A string is <strong>beautiful</strong> if:</p>\n\n<ul>\n\t<li><code>vowels == consonants</code>.</li>\n\t<li><code>(vowels * consonants) % k == 0</code>, in other terms the multiplication of <code>vowels</code> and <code>consonants</code> is divisible by <code>k</code>.</li>\n</ul>\n\n<p>Return <em>the number of <strong>non-empty beautiful substrings</strong> in the given string</em> <code>s</code>.</p>\n\n<p>A <strong>substring</strong> is a contiguous sequence of characters in a string.</p>\n\n<p><strong>Vowel letters</strong> in English are <code>&#39;a&#39;</code>, <code>&#39;e&#39;</code>, <code>&#39;i&#39;</code>, <code>&#39;o&#39;</code>, and <code>&#39;u&#39;</code>.</p>\n\n<p><strong>Consonant letters</strong> in English are every letter except vowels.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;baeyh&quot;, k = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> There are 2 beautiful substrings in the given string.\n- Substring &quot;b<u>aeyh</u>&quot;, vowels = 2 ([&quot;a&quot;,e&quot;]), consonants = 2 ([&quot;y&quot;,&quot;h&quot;]).\nYou can see that string &quot;aeyh&quot; is beautiful as vowels == consonants and vowels * consonants % k == 0.\n- Substring &quot;<u>baey</u>h&quot;, vowels = 2 ([&quot;a&quot;,e&quot;]), consonants = 2 ([&quot;b&quot;,&quot;y&quot;]).\nYou can see that string &quot;baey&quot; is beautiful as vowels == consonants and vowels * consonants % k == 0.\nIt can be shown that there are only 2 beautiful substrings in the given string.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abba&quot;, k = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> There are 3 beautiful substrings in the given string.\n- Substring &quot;<u>ab</u>ba&quot;, vowels = 1 ([&quot;a&quot;]), consonants = 1 ([&quot;b&quot;]).\n- Substring &quot;ab<u>ba</u>&quot;, vowels = 1 ([&quot;a&quot;]), consonants = 1 ([&quot;b&quot;]).\n- Substring &quot;<u>abba</u>&quot;, vowels = 2 ([&quot;a&quot;,&quot;a&quot;]), consonants = 2 ([&quot;b&quot;,&quot;b&quot;]).\nIt can be shown that there are only 3 beautiful substrings in the given string.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;bcdf&quot;, k = 1\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There are no beautiful substrings in the given string.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 1000</code></li>\n\t<li><code>s</code> consists of only English lowercase letters.</li>\n</ul>\n",
            "translatedTitle": "统计美丽子字符串 II",
            "translatedContent": "<p>给你一个字符串 <code>s</code> 和一个正整数 <code>k</code> 。</p>\n\n<p>用 <code>vowels</code> 和 <code>consonants</code> 分别表示字符串中元音字母和辅音字母的数量。</p>\n\n<p>如果某个字符串满足以下条件，则称其为 <strong>美丽字符串</strong> ：</p>\n\n<ul>\n\t<li><code>vowels == consonants</code>，即元音字母和辅音字母的数量相等。</li>\n\t<li><code>(vowels * consonants) % k == 0</code>，即元音字母和辅音字母的数量的乘积能被 <code>k</code> 整除。</li>\n</ul>\n\n<p>返回字符串 <code>s</code> 中 <strong>非空美丽子字符串</strong> 的数量。</p>\n\n<p>子字符串是字符串中的一个连续字符序列。</p>\n\n<p>英语中的<strong> 元音字母 </strong>为 <code>'a'</code>、<code>'e'</code>、<code>'i'</code>、<code>'o'</code> 和 <code>'u'</code> 。</p>\n\n<p>英语中的<strong> 辅音字母 </strong>为除了元音字母之外的所有字母。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"baeyh\", k = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>字符串 s 中有 2 个美丽子字符串。\n- 子字符串 \"b<em><strong>aeyh</strong></em>\"，vowels = 2（[\"a\",\"e\"]），consonants = 2（[\"y\",\"h\"]）。\n可以看出字符串 \"aeyh\" 是美丽字符串，因为 vowels == consonants 且 vowels * consonants % k == 0 。\n- 子字符串 \"<em><strong>baey</strong></em>h\"，vowels = 2（[\"a\",\"e\"]），consonants = 2（[\"b\",\"y\"]）。\n可以看出字符串 \"baey\" 是美丽字符串，因为 vowels == consonants 且 vowels * consonants % k == 0 。\n可以证明字符串 s 中只有 2 个美丽子字符串。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abba\", k = 1\n<strong>输出：</strong>3\n<strong>解释：</strong>字符串 s 中有 3 个美丽子字符串。\n- 子字符串 \"<strong><em>ab</em></strong>ba\"，vowels = 1（[\"a\"]），consonants = 1（[\"b\"]）。\n- 子字符串 \"ab<strong><em>ba</em></strong>\"，vowels = 1（[\"a\"]），consonants = 1（[\"b\"]）。\n- 子字符串 \"<em><strong>abba</strong></em>\"，vowels = 2（[\"a\",\"a\"]），consonants = 2（[\"b\",\"b\"]）。\n可以证明字符串 s 中只有 3 个美丽子字符串。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"bcdf\", k = 1\n<strong>输出：</strong>0\n<strong>解释：</strong>字符串 s 中没有美丽子字符串。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 1000</code></li>\n\t<li><code>s</code> 仅由小写英文字母组成。</li>\n</ul>\n",
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                "We can iterate over all such <code>x</codes> values and count the number of substrings such that <code>vowels == consonants == x</code>.",
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